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Question Number 147684 Answers: 0 Comments: 0

decompse F(x)=(x^3 /((x^2 +1)^4 )) inside C(x)

$$\mathrm{decompse}\:\mathrm{F}\left(\mathrm{x}\right)=\frac{\mathrm{x}^{\mathrm{3}} }{\left(\mathrm{x}^{\mathrm{2}} \:+\mathrm{1}\right)^{\mathrm{4}} }\:\:\:\mathrm{inside}\:\mathrm{C}\left(\mathrm{x}\right) \\ $$

Question Number 147683 Answers: 1 Comments: 0

let F(x)=(1/((x+1)^5 (2x−3)^4 )) 1) find ∫ F(x)dx 2)en deduire la decomposition de F en element simples

$$\mathrm{let}\:\mathrm{F}\left(\mathrm{x}\right)=\frac{\mathrm{1}}{\left(\mathrm{x}+\mathrm{1}\right)^{\mathrm{5}} \left(\mathrm{2x}−\mathrm{3}\right)^{\mathrm{4}} } \\ $$$$\left.\mathrm{1}\right)\:\mathrm{find}\:\int\:\mathrm{F}\left(\mathrm{x}\right)\mathrm{dx} \\ $$$$\left.\mathrm{2}\right)\mathrm{en}\:\mathrm{deduire}\:\mathrm{la}\:\mathrm{decomposition}\:\mathrm{de}\:\mathrm{F}\:\mathrm{en}\:\mathrm{element}\:\mathrm{simples} \\ $$

Question Number 147682 Answers: 0 Comments: 0

decompose F(x)=(1/((x^n −1)(x^2 +x+1))) dans C(x) puis dans R(x)

$$\mathrm{decompose}\:\mathrm{F}\left(\mathrm{x}\right)=\frac{\mathrm{1}}{\left(\mathrm{x}^{\mathrm{n}} −\mathrm{1}\right)\left(\mathrm{x}^{\mathrm{2}} \:+\mathrm{x}+\mathrm{1}\right)}\:\mathrm{dans}\:\mathrm{C}\left(\mathrm{x}\right)\:\mathrm{puis}\:\mathrm{dans}\:\mathrm{R}\left(\mathrm{x}\right) \\ $$

Question Number 147680 Answers: 0 Comments: 2

find by residus ∫_0 ^∞ ((cos(2x))/((x^2 −x+1)^3 ))dx

$$\mathrm{find}\:\mathrm{by}\:\mathrm{residus}\:\int_{\mathrm{0}} ^{\infty} \:\:\:\frac{\mathrm{cos}\left(\mathrm{2x}\right)}{\left(\mathrm{x}^{\mathrm{2}} −\mathrm{x}+\mathrm{1}\right)^{\mathrm{3}} }\mathrm{dx} \\ $$

Question Number 147678 Answers: 0 Comments: 0

roots of Υ_n (x)=sin(narcsinx) (n integr natural) deompose F(x)=(1/(Υ_n (x)))

$$\mathrm{roots}\:\mathrm{of}\:\:\Upsilon_{\mathrm{n}} \left(\mathrm{x}\right)=\mathrm{sin}\left(\mathrm{narcsinx}\right)\:\:\left(\mathrm{n}\:\mathrm{integr}\:\mathrm{natural}\right) \\ $$$$\mathrm{deompose}\:\mathrm{F}\left(\mathrm{x}\right)=\frac{\mathrm{1}}{\Upsilon_{\mathrm{n}} \left(\mathrm{x}\right)} \\ $$

Question Number 147673 Answers: 3 Comments: 0

Question Number 147670 Answers: 1 Comments: 0

Question Number 147654 Answers: 0 Comments: 1

Question Number 147651 Answers: 1 Comments: 2

tan 1°+tan 5°+tan 9°+...+tan 173°+tan 177°=?

$$\:\mathrm{tan}\:\mathrm{1}°+\mathrm{tan}\:\mathrm{5}°+\mathrm{tan}\:\mathrm{9}°+...+\mathrm{tan}\:\mathrm{173}°+\mathrm{tan}\:\mathrm{177}°=? \\ $$

Question Number 147643 Answers: 2 Comments: 0

tan (x+(π/4))+3(tan (π/9)+tan ((2π)/9))=tan (x+(π/4))tan (π/9)tan ((2π)/9)

$$\:\mathrm{tan}\:\left(\mathrm{x}+\frac{\pi}{\mathrm{4}}\right)+\mathrm{3}\left(\mathrm{tan}\:\frac{\pi}{\mathrm{9}}+\mathrm{tan}\:\frac{\mathrm{2}\pi}{\mathrm{9}}\right)=\mathrm{tan}\:\left(\mathrm{x}+\frac{\pi}{\mathrm{4}}\right)\mathrm{tan}\:\frac{\pi}{\mathrm{9}}\mathrm{tan}\:\frac{\mathrm{2}\pi}{\mathrm{9}} \\ $$

Question Number 147635 Answers: 0 Comments: 5

find the taylor series f(z)=cosz ,z=(π/4)

$${find}\:{the}\:{taylor}\:{series}\:{f}\left({z}\right)={cosz}\:\:,{z}=\frac{\pi}{\mathrm{4}} \\ $$$$ \\ $$$$ \\ $$

Question Number 147626 Answers: 2 Comments: 0

∫_( 0) ^( 3) (dx/(2 + cosx)) = ?

$$\underset{\:\mathrm{0}} {\overset{\:\mathrm{3}} {\int}}\:\frac{{dx}}{\mathrm{2}\:+\:{cosx}}\:=\:? \\ $$

Question Number 147624 Answers: 0 Comments: 0

The current in the windings on a toroid is 2.0A.There are 400 turns and the mean circumferential length is 40cm.With the aid of a search coil and charge measuring instrument the magnetic field is found to be 1.0T.calculate: i)magnetic density ii)magnetization iii) magnetic susceptibility

$$\mathrm{The}\:\mathrm{current}\:\mathrm{in}\:\mathrm{the}\:\mathrm{windings}\:\mathrm{on}\:\mathrm{a}\: \\ $$$$\mathrm{toroid}\:\mathrm{is}\:\mathrm{2}.\mathrm{0A}.\mathrm{There}\:\mathrm{are}\:\mathrm{400}\:\mathrm{turns} \\ $$$$\mathrm{and}\:\mathrm{the}\:\mathrm{mean}\:\mathrm{circumferential}\:\mathrm{length} \\ $$$$\mathrm{is}\:\mathrm{40cm}.\mathrm{With}\:\mathrm{the}\:\mathrm{aid}\:\mathrm{of}\:\mathrm{a}\:\mathrm{search} \\ $$$$\:\mathrm{coil}\:\mathrm{and}\:\mathrm{charge}\:\mathrm{measuring}\:\mathrm{instrument} \\ $$$$\mathrm{the}\:\mathrm{magnetic}\:\mathrm{field}\:\mathrm{is}\:\mathrm{found}\:\mathrm{to}\:\mathrm{be} \\ $$$$\mathrm{1}.\mathrm{0T}.\mathrm{calculate}: \\ $$$$\left.\mathrm{i}\left.\right)\mathrm{magnetic}\:\mathrm{density}\:\mathrm{ii}\right)\mathrm{magnetization} \\ $$$$\left.\mathrm{iii}\right)\:\mathrm{magnetic}\:\mathrm{susceptibility} \\ $$

Question Number 147623 Answers: 0 Comments: 1