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Question Number 147768 Answers: 1 Comments: 0
Question Number 146444 Answers: 0 Comments: 0
Question Number 146442 Answers: 2 Comments: 0
$$\frac{\mathrm{d}}{\mathrm{dn}}\mid_{\mathrm{n}=\mathrm{1}} \mathrm{H}_{\mathrm{n}} =? \\ $$
Question Number 146436 Answers: 2 Comments: 0
$$\frac{{sin}^{\mathrm{2}} \:\mathrm{25}\:-\:{sin}^{\mathrm{2}} \:\mathrm{5}}{{sin}\:\mathrm{20}}\:=\:? \\ $$
Question Number 146440 Answers: 1 Comments: 0
Question Number 146429 Answers: 1 Comments: 1
$$\underset{\mathrm{n}=\mathrm{1}} {\overset{\infty} {\sum}}\left(\mathrm{n}\centerdot\mathrm{ln}\frac{\mathrm{2n}+\mathrm{1}}{\mathrm{2n}−\mathrm{1}}−\mathrm{1}\right)=? \\ $$
Question Number 146425 Answers: 1 Comments: 2
$$\mathrm{4}\:{people}\:{took}\:{the}\:{elevator}\:{to}\:{the}\:{first} \\ $$$${floor}\:{of}\:{the}\:\mathrm{6}\:-\:{storey}\:{building}.\:{Find} \\ $$$${the}\:{probability}\:{that}\:{they}\:{fall}\:{on} \\ $$$${different}\:{floors}. \\ $$
Question Number 147666 Answers: 0 Comments: 0
$$\mathrm{6bhh} \\ $$$$\mathrm{bnn77} \\ $$$$\mathrm{chb65b} \\ $$$$\mathrm{fbb7}\sqrt{} \\ $$$$\mathrm{m977} \\ $$$$\mathrm{tgvn} \\ $$
Question Number 146420 Answers: 0 Comments: 0
Question Number 146411 Answers: 1 Comments: 1
$${prove}\:\mathrm{197}\:{prime}\:{number} \\ $$
Question Number 146408 Answers: 3 Comments: 3
$${find}\:\mathrm{3}{x}\approxeq\mathrm{4}\left(\:{mod}\:\mathrm{5}\right) \\ $$
Question Number 146404 Answers: 1 Comments: 1
$$\:\mathrm{trigonometry} \\ $$
Question Number 146403 Answers: 0 Comments: 1
$${let}\:{f}\left({x},{y}\right)=\frac{{x}^{\mathrm{5}} {y}^{\mathrm{2}} }{\mathrm{10}}\:{then}\:{find}\: \\ $$$${D}_{{u}} {f}\left(−\mathrm{5},−\mathrm{3}\right)\:{in}\:{the}\:{direction}\:{of}\: \\ $$$${the}\:{vector}\:<\mathrm{0},−\mathrm{2}>? \\ $$
Question Number 146401 Answers: 0 Comments: 1
$$\frac{{dy}}{{dx}}\left({x}!\right) \\ $$
Question Number 146386 Answers: 2 Comments: 0
$${if}\:\:\:\frac{\mathrm{8}}{\mathrm{3}^{\boldsymbol{{x}}} \:+\:\mathrm{2}^{−\boldsymbol{{x}}} }\:=\:\frac{\mathrm{27}}{\mathrm{3}^{−\boldsymbol{{x}}} \:+\:\mathrm{2}^{\boldsymbol{{x}}} } \\ $$$${find}\:\:\:\mathrm{2}{x}+\mathrm{1}=? \\ $$
Question Number 146377 Answers: 0 Comments: 4
$${Determine}\:{all}\:{pairs}\:{of}\:{real}\:{numbers} \\ $$$$\left({a};{b}\right)\:{such}\:{that}: \\ $$$${a}^{\mathrm{6}} −{b}^{\mathrm{4}} ={b}^{\mathrm{6}} −{a}^{\mathrm{4}} =\mathrm{4} \\ $$
Question Number 146376 Answers: 1 Comments: 0
$$\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{1}−\mathrm{cos}\:\mathrm{x}\:\mathrm{cos}\:\mathrm{2x}\:\mathrm{cos}\:\mathrm{3x}...\:\mathrm{cos}\:\mathrm{px}}{\mathrm{x}^{\mathrm{2}} }\:=? \\ $$
Question Number 146371 Answers: 3 Comments: 0
$$\int_{\mathrm{0}} ^{\pi} \frac{\mathrm{1}}{\mathrm{1}+{cos}^{\mathrm{2}} {x}}{dx}=......??? \\ $$
Question Number 146363 Answers: 1 Comments: 0
$$\mathrm{find}\:\int_{−\mathrm{i}} ^{\mathrm{1}+\mathrm{i}} \left(\mathrm{x}^{\mathrm{2}} −\mathrm{iy}\right)\mathrm{dz}\:\:\mathrm{along}\:\:\mathrm{y}=\mathrm{x}^{\mathrm{3}} \\ $$
Question Number 146361 Answers: 2 Comments: 0
$${find}\:\int\frac{\mathrm{1}}{{x}^{{n}} +\mathrm{1}}{dx}\:{for}\:{n}\in{N} \\ $$
Question Number 146355 Answers: 1 Comments: 0
$$\:\mathrm{If}\:\mathrm{3}^{\mathrm{4}^{\mathrm{2}^{{x}} } } =\:\mathrm{81}^{\mathrm{2}^{\mathrm{6}} } \:\mathrm{then}\:\sqrt{{x}^{\mathrm{2}} +\mathrm{5}}\:=? \\ $$
Question Number 146353 Answers: 0 Comments: 0
Question Number 146532 Answers: 2 Comments: 0
$$\mathrm{2}^{\boldsymbol{{x}}} \:=\:\mathrm{5}\:\:,\:\:\mathrm{3}^{\boldsymbol{{y}}} \:=\:\mathrm{9}\:\:{and}\:\:\mathrm{25}^{\boldsymbol{{z}}} \:=\:\mathrm{8} \\ $$$${find}\:\:\:\left({x}\centerdot{y}\centerdot{z}\right)=? \\ $$
Question Number 146334 Answers: 5 Comments: 1
Question Number 146328 Answers: 1 Comments: 0
Question Number 146325 Answers: 1 Comments: 0
$${Given}\:{that}\:\left({a}+{b}\right)=\sqrt{\mathrm{3}\sqrt{\mathrm{3}}−\sqrt{\mathrm{2}}} \\ $$$${and}\:\left({a}−{b}\right)=\sqrt{\mathrm{3}\sqrt{\mathrm{2}}−\sqrt{\mathrm{3}}} \\ $$$${Find} \\ $$$$\left({i}\right)\:{ab}\:\:\:\:\:\:\left({ii}\right)\:{a}^{\mathrm{2}} +{b}^{\mathrm{2}} \\ $$
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