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Question Number 148953 Answers: 0 Comments: 4
Question Number 148951 Answers: 2 Comments: 0
$${Let}\:{complex}\:{number}\:{z}=\left({a}+\mathrm{cos}\:\theta\right)+\left(\mathrm{2}{a}−\mathrm{sin}\:\theta\right){i}\:. \\ $$$${If}\:\mid{z}\mid\:\leqslant\mathrm{2}\:{for}\:{any}\:\theta\in{R}\:{then}\:{the} \\ $$$${range}\:{of}\:{real}\:{number}\:{a}\:{is}\:\_\_\_ \\ $$
Question Number 148947 Answers: 1 Comments: 0
$$\mathrm{615}\:+\:{x}^{\mathrm{2}} \:=\:\mathrm{2}^{\boldsymbol{{y}}} \:\:\:;\:\:\:{x};{y}\in\mathbb{N} \\ $$$$\Rightarrow\:{x};{y}\:=\:? \\ $$
Question Number 148946 Answers: 1 Comments: 0
$$\mathrm{Sum}\:\mathrm{to}\:\:\mathrm{n}\:\:\mathrm{term}:\:\:\:\:\:\:\:\frac{\mathrm{1}}{\mathrm{1}.\mathrm{2}.\mathrm{3}}\:\:\:+\:\:\frac{\mathrm{1}}{\mathrm{4}.\mathrm{5}.\mathrm{6}}\:\:\:+\:\:\:\frac{\mathrm{1}}{\mathrm{7}.\mathrm{8}.\mathrm{9}}\:\:+\:\:...\:\:\:\mathrm{to}\:\:\mathrm{n}. \\ $$
Question Number 148944 Answers: 0 Comments: 0
$${find}\:{residuo}\:{f}\left({z}\right)=\frac{{z}}{{z}^{{n}} −\mathrm{1}} \\ $$
Question Number 148942 Answers: 0 Comments: 0
$${M}=\int_{\mathrm{0}} ^{+\infty} \frac{{x}^{\mathrm{2}{n}} {lnx}}{{x}^{\mathrm{2}} +\mathrm{1}}{dx} \\ $$$$ \\ $$
Question Number 148905 Answers: 1 Comments: 0
Question Number 149796 Answers: 0 Comments: 4
Question Number 148901 Answers: 0 Comments: 2
Question Number 148895 Answers: 0 Comments: 2
Question Number 148890 Answers: 1 Comments: 0
$${if}\:\:\:{x}\:+\:\frac{\mathrm{1}}{{x}}\:=\:\sqrt{\mathrm{3}} \\ $$$${find}\:\:\:{x}^{\mathrm{18}} \:+\:{x}^{\mathrm{12}} \:+\:{x}^{\mathrm{6}} \:+\:\mathrm{1}\:=\:? \\ $$
Question Number 148887 Answers: 2 Comments: 0
$$\Omega=\underset{\:\mathrm{1}} {\overset{\:\infty} {\int}}\:\frac{\sqrt{{x}}\:{ln}\:{x}}{{x}^{\mathrm{2}} \:+\:\mathrm{1}}\:{dx}\:=\:? \\ $$
Question Number 148886 Answers: 1 Comments: 0
Question Number 148884 Answers: 1 Comments: 0
Question Number 148881 Answers: 1 Comments: 0
Question Number 148880 Answers: 1 Comments: 0
Question Number 148868 Answers: 2 Comments: 0
Question Number 148864 Answers: 1 Comments: 0
$$\mathrm{A}\:\mathrm{random}\:\mathrm{variable}\:\mathrm{K}\:\mathrm{has}\:\mathrm{a}\:\mathrm{pdf}\: \\ $$$$\mathrm{f}\left(\mathrm{k}\right)=\left\{_{\mathrm{0}\:\:\:\:\:\:,\:\:\:\:\:\:\:\mathrm{otherwise}} ^{\mathrm{e}^{−\mathrm{k}\:\:\:,\:\:\:\:\:\:\:\:\mathrm{0}>\mathrm{k}} } \:\:\:\:\mathrm{find}\:\mathrm{E}\left(\mathrm{K}\right)\:\mathrm{and}\:\right. \\ $$$$\mathrm{the}\:\mathrm{cdf} \\ $$
Question Number 148861 Answers: 1 Comments: 0
Question Number 148860 Answers: 0 Comments: 0
$$ \\ $$$$\:\:\:{f}\left({x}\right):=\:\mid\:{x}^{\:\mathrm{2}} −\:\left({a}+\mathrm{1}\right){x}\:+\mathrm{2}{a}^{\:\mathrm{2}} −\mathrm{1}\mid \\ $$$$\:\:\:\:{is}\:{differentiable}\:{on}\:\left(\:\mathrm{1},\:\mathrm{2}\:\right). \\ $$$$\:\:{find}\:{the}\:{value}\left({s}\right)\:{of}\:\:'\:\:{a}\:\:'\:. \\ $$$$\:\:........ \\ $$
Question Number 148858 Answers: 1 Comments: 0
Question Number 148856 Answers: 0 Comments: 3
$${pls}\:{solve} \\ $$
Question Number 148854 Answers: 0 Comments: 0
$$\int\sqrt{\frac{{A}\centerdot{B}\centerdot\sqrt{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} }}{\left({x}^{\mathrm{2}} +{y}^{\mathrm{2}} \right){B}^{\mathrm{2}} +{C}}}{dx}=\:\:? \\ $$$${A},{B},{C}={const}. \\ $$
Question Number 148849 Answers: 2 Comments: 0
$$\:\underset{{x}\rightarrow\mathrm{0}^{+} } {\mathrm{lim}}\frac{{x}^{\mathrm{3}} −\mathrm{cos}\:\sqrt{{x}}\:\mathrm{sin}\:^{\mathrm{2}} {x}}{{x}^{\mathrm{2}} }\:=? \\ $$
Question Number 148848 Answers: 2 Comments: 0
$$\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\sqrt[{\mathrm{4}}]{{x}+\mathrm{16}}\:\sqrt[{\mathrm{3}}]{{x}+\mathrm{8}}\:−\mathrm{4}}{{x}^{\mathrm{2}} +\mathrm{2}{x}}\:=?\: \\ $$
Question Number 148838 Answers: 0 Comments: 3
$$\:\frac{\mathrm{1}}{\mathrm{2}×\mathrm{3}×\mathrm{4}}\:+\frac{\mathrm{1}}{\mathrm{3}×\mathrm{4}×\mathrm{5}}+\frac{\mathrm{1}}{\mathrm{4}×\mathrm{5}×\mathrm{6}}+\frac{\mathrm{1}}{\mathrm{5}×\mathrm{6}×\mathrm{7}}+\frac{\mathrm{1}}{\mathrm{6}×\mathrm{7}×\mathrm{8}}+...+\frac{\mathrm{1}}{\mathrm{12}×\mathrm{13}×\mathrm{14}}=? \\ $$
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