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Question Number 217912    Answers: 0   Comments: 2

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Question Number 217911    Answers: 2   Comments: 0

Solve ((x/(x−1)))^2 +((x/(x+1)))^2 =6

$${Solve} \\ $$$$\left(\frac{{x}}{{x}−\mathrm{1}}\right)^{\mathrm{2}} +\left(\frac{{x}}{{x}+\mathrm{1}}\right)^{\mathrm{2}} =\mathrm{6} \\ $$

Question Number 217909    Answers: 0   Comments: 15

If two fair dice is thrown twice, what is the probability of obtaining an even number

If two fair dice is thrown twice, what is the probability of obtaining an even number

Question Number 217897    Answers: 1   Comments: 7

Question Number 217895    Answers: 1   Comments: 6

Question Number 217894    Answers: 0   Comments: 0

In △ABC holds: Σ ((cot A)/( (√(cot B + 3 cot C)))) ≥ (1/2) ((27))^(1/4)

$$\mathrm{In}\:\:\bigtriangleup\mathrm{ABC}\:\:\mathrm{holds}: \\ $$$$\Sigma\:\frac{\mathrm{cot}\:\mathrm{A}}{\:\sqrt{\mathrm{cot}\:\mathrm{B}\:\:+\:\:\mathrm{3}\:\mathrm{cot}\:\mathrm{C}}}\:\:\geqslant\:\:\frac{\mathrm{1}}{\mathrm{2}}\:\:\sqrt[{\mathrm{4}}]{\mathrm{27}}\: \\ $$

Question Number 217888    Answers: 3   Comments: 0

Solve: ((x^2 −3x+2)/(x^2 −8x+15))=((x^2 −5x+6)/(x^2 −10x+24))

$${Solve}: \\ $$$$\frac{{x}^{\mathrm{2}} −\mathrm{3}{x}+\mathrm{2}}{{x}^{\mathrm{2}} −\mathrm{8}{x}+\mathrm{15}}=\frac{{x}^{\mathrm{2}} −\mathrm{5}{x}+\mathrm{6}}{{x}^{\mathrm{2}} −\mathrm{10}{x}+\mathrm{24}} \\ $$

Question Number 217887    Answers: 2   Comments: 0

Solve : ((x+1)/(x−2))+((x−1)/(x+2))=((2x+1)/(x−1))+((2x−1)/(x+1))

$${Solve}\:: \\ $$$$\frac{{x}+\mathrm{1}}{{x}−\mathrm{2}}+\frac{{x}−\mathrm{1}}{{x}+\mathrm{2}}=\frac{\mathrm{2}{x}+\mathrm{1}}{{x}−\mathrm{1}}+\frac{\mathrm{2}{x}−\mathrm{1}}{{x}+\mathrm{1}} \\ $$

Question Number 217881    Answers: 2   Comments: 0

Question Number 217873    Answers: 1   Comments: 1

What is 5^(! ) = ?

$${What}\:{is}\:\mathrm{5}^{!\:} =\:? \\ $$

Question Number 217872    Answers: 0   Comments: 0

a , b , c > 0 ab + ac + bc = 1 Prove that: (√(a^3 + a)) + (√(b^3 + b)) + (√(c^3 + c)) ≥ 2 (√(a + b + c))

$$\mathrm{a}\:,\:\mathrm{b}\:,\:\mathrm{c}\:>\:\mathrm{0} \\ $$$$\mathrm{ab}\:+\:\mathrm{ac}\:+\:\mathrm{bc}\:=\:\mathrm{1} \\ $$$$\mathrm{Prove}\:\mathrm{that}: \\ $$$$\sqrt{\mathrm{a}^{\mathrm{3}} \:+\:\mathrm{a}}\:\:+\:\:\sqrt{\mathrm{b}^{\mathrm{3}} \:+\:\mathrm{b}}\:\:+\:\:\sqrt{\mathrm{c}^{\mathrm{3}} \:+\:\mathrm{c}}\:\:\geqslant\:\mathrm{2}\:\sqrt{\mathrm{a}\:+\:\mathrm{b}\:+\:\mathrm{c}} \\ $$

Question Number 217871    Answers: 1   Comments: 0

n ≥ 2 Prove that: Π_(k=1) ^n tg [ (π/3) (1 + (3^k /(3^n − 1)))] = Π_(k=1) ^n ctg [ (π/3) (1 − (3^k /(3^n − 1)))]

$$\mathrm{n}\:\geqslant\:\mathrm{2} \\ $$$$\mathrm{Prove}\:\mathrm{that}: \\ $$$$\underset{\boldsymbol{\mathrm{k}}=\mathrm{1}} {\overset{\boldsymbol{\mathrm{n}}} {\prod}}\:\mathrm{tg}\:\left[\:\frac{\pi}{\mathrm{3}}\:\left(\mathrm{1}\:+\:\frac{\mathrm{3}^{\boldsymbol{\mathrm{k}}} }{\mathrm{3}^{\boldsymbol{\mathrm{n}}} \:−\:\mathrm{1}}\right)\right]\:=\:\underset{\boldsymbol{\mathrm{k}}=\mathrm{1}} {\overset{\boldsymbol{\mathrm{n}}} {\prod}}\:\mathrm{ctg}\:\left[\:\frac{\pi}{\mathrm{3}}\:\left(\mathrm{1}\:−\:\frac{\mathrm{3}^{\boldsymbol{\mathrm{k}}} }{\mathrm{3}^{\boldsymbol{\mathrm{n}}} \:−\:\mathrm{1}}\right)\right] \\ $$

Question Number 217858    Answers: 0   Comments: 0

Question Number 217857    Answers: 2   Comments: 0

Prove that: ((cos20°))^(1/3) + ((cos80°))^(1/3) + ((cos160°))^(1/3) = (((3 ∙ (9)^(1/3) − 6)/2))^(1/3)

$$\mathrm{Prove}\:\mathrm{that}: \\ $$$$\sqrt[{\mathrm{3}}]{\mathrm{cos20}°}\:+\:\sqrt[{\mathrm{3}}]{\mathrm{cos80}°}\:+\:\sqrt[{\mathrm{3}}]{\mathrm{cos160}°}\:=\:\sqrt[{\mathrm{3}}]{\frac{\mathrm{3}\:\centerdot\:\sqrt[{\mathrm{3}}]{\mathrm{9}}\:−\:\mathrm{6}}{\mathrm{2}}} \\ $$

Question Number 217855    Answers: 2   Comments: 0

i need help ∫_0 ^1 x^n (e^(−(x^2 /2)) )dx ,(n∈N)

$${i}\:{need}\:{help}\: \\ $$$$\int_{\mathrm{0}} ^{\mathrm{1}} {x}^{{n}} \left({e}^{−\frac{{x}^{\mathrm{2}} }{\mathrm{2}}} \right){dx}\:\:,\left({n}\in\mathbb{N}\right) \\ $$

Question Number 217849    Answers: 0   Comments: 0

Question Number 217843    Answers: 0   Comments: 5

Question Number 217842    Answers: 2   Comments: 0

f(x)=(√(x^2 −6x+10)) f(3+2(√6))=?

$${f}\left({x}\right)=\sqrt{{x}^{\mathrm{2}} −\mathrm{6}{x}+\mathrm{10}} \\ $$$${f}\left(\mathrm{3}+\mathrm{2}\sqrt{\mathrm{6}}\right)=? \\ $$

Question Number 217837    Answers: 1   Comments: 0

do you guys know about Three Body problem?? when 2−Body problem we can solve equation of motions x_1 ^→ (t) , x_2 ^→ (t) but why we can′t solve 3−body problem? The reason why we can′t solve 3−Body problem is because this Equation isn′t Linear equation???

$$\mathrm{do}\:\mathrm{you}\:\mathrm{guys}\:\mathrm{know}\:\mathrm{about}\:\mathrm{Three}\:\mathrm{Body}\:\mathrm{problem}?? \\ $$$$\mathrm{when}\:\mathrm{2}−\mathrm{Body}\:\mathrm{problem}\: \\ $$$$\mathrm{we}\:\mathrm{can}\:\mathrm{solve}\:\mathrm{equation}\:\mathrm{of}\:\mathrm{motions}\:\overset{\rightarrow} {\boldsymbol{\mathrm{x}}}_{\mathrm{1}} \left({t}\right)\:,\:\overset{\rightarrow} {\boldsymbol{\mathrm{x}}}_{\mathrm{2}} \left({t}\right) \\ $$$$\mathrm{but}\:\mathrm{why}\:\mathrm{we}\:\mathrm{can}'\mathrm{t}\:\mathrm{solve}\:\mathrm{3}−\mathrm{body}\:\mathrm{problem}? \\ $$$$\mathrm{The}\:\mathrm{reason}\:\mathrm{why}\:\mathrm{we}\:\mathrm{can}'\mathrm{t}\:\mathrm{solve}\:\mathrm{3}−\mathrm{Body}\:\mathrm{problem} \\ $$$$\mathrm{is}\:\mathrm{because}\:\mathrm{this}\:\mathrm{Equation}\:\mathrm{isn}'\mathrm{t}\:\:\mathrm{Linear}\:\mathrm{equation}??? \\ $$

Question Number 217821    Answers: 0   Comments: 0

Question Number 217822    Answers: 1   Comments: 0

Question Number 217819    Answers: 0   Comments: 0

Question Number 217818    Answers: 1   Comments: 0

Question Number 217813    Answers: 1   Comments: 0

∫_0 ^∞ [(xp(2+x)]^(−1) dx p∈R

$$\underset{\mathrm{0}} {\overset{\infty} {\int}}\left[\left({xp}\left(\mathrm{2}+{x}\right)\right]^{−\mathrm{1}} {dx}\:\:\:\right. \\ $$$${p}\in\mathbb{R} \\ $$

Question Number 217802    Answers: 1   Comments: 2

Question Number 217797    Answers: 3   Comments: 0

Solve: 5x^2 y′′ + x(1 + x) y′ − y = 0

$$\mathrm{Solve}: \\ $$$$\:\:\:\:\:\mathrm{5x}^{\mathrm{2}} \:\mathrm{y}''\:\:+\:\:\:\mathrm{x}\left(\mathrm{1}\:\:+\:\:\mathrm{x}\right)\:\mathrm{y}'\:\:−\:\:\mathrm{y}\:\:\:=\:\:\:\mathrm{0} \\ $$

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