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Question Number 216875 Answers: 1 Comments: 0
$$\mathrm{Let}\:\:\mathrm{p}\:\:\mathrm{be}\:\mathrm{a}\:\mathrm{prime}\:\mathrm{number}\:\mathrm{greater}\:\mathrm{than}\:\mathrm{3}.\:\mathrm{Prove}\:\mathrm{that}\:\:\mathrm{p}^{\mathrm{2}} −\:\mathrm{1}\:\: \\ $$$$\mathrm{is}\:\:\mathrm{always}\:\:\mathrm{divisible}\:\mathrm{by}\:\mathrm{24}. \\ $$
Question Number 216861 Answers: 0 Comments: 0
Question Number 216859 Answers: 1 Comments: 3
Question Number 216855 Answers: 2 Comments: 0
Question Number 216842 Answers: 1 Comments: 0
$$\mathrm{Find}\:\mathrm{all}\:\mathrm{pairs}\:\mathrm{of}\:\mathrm{positive}\:\mathrm{integers}\:\:\mathrm{x},\:\mathrm{y}\:\:\mathrm{that}\:\mathrm{satisfy} \\ $$$$\mathrm{the}\:\:\mathrm{system}\:\: \\ $$$$\mathrm{xy}\:+\:\mathrm{x}\:+\:\mathrm{y}=\mathrm{71}\: \\ $$$$\mathrm{x}^{\mathrm{2}} \mathrm{y}\:+\:\mathrm{xy}^{\mathrm{2}} =\mathrm{880} \\ $$
Question Number 216841 Answers: 1 Comments: 0
$$\mathrm{Prove}\:\mathrm{that}:\:\:\:\:\:\delta\left(\mathrm{n}\right)\:=\:\underset{\frac{\boldsymbol{\mathrm{d}}}{\boldsymbol{\mathrm{n}}}} {\sum}\:\boldsymbol{\varphi}\left(\mathrm{d}\right)\:\boldsymbol{\tau}\left(\frac{\mathrm{n}}{\mathrm{d}}\right) \\ $$$$\boldsymbol{\delta}\left(\mathrm{n}\right)\:=\:\underset{\frac{\boldsymbol{\mathrm{d}}}{\boldsymbol{\mathrm{n}}}} {\sum}\:\mathrm{d}\:\:\:,\:\:\:\boldsymbol{\tau}\left(\mathrm{n}\right)\:=\:\underset{\frac{\boldsymbol{\mathrm{d}}}{\boldsymbol{\mathrm{n}}}} {\sum}\:{l}\:\:\:\mathrm{and}\:\:\:\varphi-\mathrm{Eyler}.\mathrm{f} \\ $$
Question Number 216836 Answers: 3 Comments: 0
$$\mathrm{Find}: \\ $$$$\frac{\left(\mathrm{1}\:+\:\mathrm{tan1}°\right)\left(\mathrm{1}\:+\:\mathrm{tan2}°\right)...\left(\mathrm{1}\:+\:\mathrm{tan44}°\right)}{\left(\mathrm{1}−\mathrm{tan46}°\right)\left(\mathrm{1}−\mathrm{tan47}°\right)...\left(\mathrm{1}−\mathrm{tan89}°\right)}\:=\:? \\ $$
Question Number 216830 Answers: 1 Comments: 1
$$\mathrm{Prove}:\forall{x}\in\mathbb{R},\mid\mathrm{cos}\:{x}\mid+\mid\mathrm{cos}\:\mathrm{2}{x}\mid+\ldots+\mid\mathrm{cos}\:{nx}\mid\geq\frac{{n}−\mathrm{1}}{\mathrm{2}}\left({n}\in\mathbb{Z}_{>\mathrm{0}} \right)\:\: \\ $$
Question Number 216827 Answers: 1 Comments: 1
Question Number 216821 Answers: 0 Comments: 0
Question Number 216820 Answers: 2 Comments: 0
$$ \\ $$$$\:\:\:{f}\left({x}\right)\:=\:{ax}^{\mathrm{4}} \:+\:{bx}^{\mathrm{3}} \:+\:{cx}^{\mathrm{2}} \:+\:{dx}\:+\:{e} \\ $$$$\:\:\:{f}\left(\mathrm{1}\right)\:=\:\mathrm{2} \\ $$$$\:\:\:{f}\left(\mathrm{2}\right)\:=\:\mathrm{3} \\ $$$$\:\:\:{f}\left(\mathrm{3}\right)\:=\:\mathrm{4} \\ $$$$\:\:\:{f}\left(\mathrm{4}\right)\:=\:\mathrm{5}\: \\ $$$$\:\:\:{f}\left(\mathrm{0}\right)\:=\:\mathrm{25} \\ $$$$\:\:\:\mathcal{T}{hen}\:\:{f}\left(\mathrm{5}\right)\:=\:? \\ $$$$\:\:\:\mathcal{H}{elp}\:{me},\:\:{please} \\ $$$$ \\ $$
Question Number 216819 Answers: 1 Comments: 0
$$\mathrm{Prove}:\int_{\mathrm{0}\:} ^{\mathrm{1}} \frac{\boldsymbol{\mathrm{K}}\left({x}\right)}{\:\sqrt{\mathrm{3}−{x}}}{dx}=\frac{\mathrm{1}}{\mathrm{96}\pi\sqrt{\mathrm{3}}}×\Gamma\left(\frac{\mathrm{1}}{\mathrm{24}}\right)\Gamma\left(\frac{\mathrm{3}}{\mathrm{24}}\right)\Gamma\left(\frac{\mathrm{7}}{\mathrm{24}}\right)\Gamma\left(\frac{\mathrm{11}}{\mathrm{24}}\right) \\ $$
Question Number 216810 Answers: 0 Comments: 1
$$ \\ $$40 random numbers picked from 0 to 100. what is the probability that at least half of them has the range of 10.
Question Number 216800 Answers: 1 Comments: 0
Question Number 216799 Answers: 1 Comments: 1
Question Number 216807 Answers: 1 Comments: 0
$$\mathrm{Uh}\:\mathrm{guys}\:\mathrm{is}\:\mathrm{the}\:\mathrm{speed}\:\mathrm{formula} \\ $$$$\frac{{d}}{{t}} \\ $$$$\mathrm{or} \\ $$$$\mathrm{li}\underset{\Delta{t}\rightarrow\mathrm{0}} {\mathrm{m}}\frac{\Delta{d}}{\Delta{t}} \\ $$
Question Number 216792 Answers: 0 Comments: 0
Question Number 216788 Answers: 1 Comments: 1
Question Number 216787 Answers: 1 Comments: 0
$${form}\:{the}\:{differential}\:{equationfrom}\:{the}\:{following} \\ $$$$\left.\mathrm{1}\right)\:{y}={Ae}^{\mathrm{3}{x}} +{Be}^{\mathrm{5}{x}} \\ $$$$\left.\mathrm{2}\right)\:{y}^{\mathrm{2}} =\left({x}−\mathrm{1}\right) \\ $$$$\left.\mathrm{3}\right)\:{c}\left({y}+{c}\right)^{\mathrm{2}} +{x}^{\mathrm{3}} =\mathrm{0} \\ $$
Question Number 216786 Answers: 1 Comments: 0
Question Number 216785 Answers: 0 Comments: 0
$$\:\:\:\mathrm{given}\:\mathrm{the}\:\mathrm{recursive}\:\left\{\mathrm{a}_{\mathrm{n}} \right\}\:\mathrm{define}\:\mathrm{by}\:\mathrm{setting} \\ $$$$\:\:\mathrm{a}_{\mathrm{1}\:} \:\in\:\left(\mathrm{0},\mathrm{1}\right)\:\:\:,\:\:\:\:\mathrm{a}_{\mathrm{n}+\mathrm{1}} \:=\:\mathrm{a}_{\mathrm{n}} \left(\mathrm{1}−\mathrm{a}_{\mathrm{n}} \right)\:\:\:,\:\mathrm{n}\geqslant\mathrm{1} \\ $$$$\:\:\mathrm{prove}\:\mathrm{that}\:\:\left(\mathrm{1}\right)\:\:\:\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}}\:\mathrm{na}_{\mathrm{n}} =\:\mathrm{1} \\ $$$$\:\:\left(\mathrm{2}\right)\:\:\mathrm{b}_{\mathrm{n}} \:=\:\mathrm{n}\left(\mathrm{1}−\mathrm{na}_{\mathrm{n}} \right)\:\mathrm{is}\:\mathrm{a}\:\mathrm{incresing}\:\mathrm{sequence} \\ $$$$\:\:\:\mathrm{and}\:\mathrm{diverge}\:\mathrm{to}\:\infty \\ $$$$\:\:\:\left(\mathrm{3}\right)\:\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}}\:\frac{\mathrm{n}\left(\mathrm{1}−\mathrm{na}_{\mathrm{n}} \right)}{\mathrm{ln}\left(\mathrm{n}\right)}\:=\:\mathrm{1} \\ $$
Question Number 216783 Answers: 3 Comments: 0
$${Find}\:{all}\:{positive}\:{integers}\:{n}\:{such}\:{that} \\ $$$${n}^{\mathrm{2}} +\mathrm{7}{n}+\mathrm{6}\:{is}\:{perfect}\:{square}. \\ $$
Question Number 216776 Answers: 1 Comments: 0
Question Number 216774 Answers: 1 Comments: 0
$$\:\:\boldsymbol{{find}}\:\int\:\frac{\boldsymbol{{tan}}^{\mathrm{2}} \left(\boldsymbol{{x}}\right)\:}{\mathrm{1}+\boldsymbol{{sec}}^{\mathrm{4}} \left(\boldsymbol{{x}}\right)}\:.\boldsymbol{{dx}}\: \\ $$
Question Number 216772 Answers: 2 Comments: 0
$$\:\:\boldsymbol{{find}}\:\int\frac{\boldsymbol{{tan}}^{\mathrm{2}} \left(\boldsymbol{{x}}\right)\:}{\mathrm{1}−\boldsymbol{{sec}}^{\mathrm{4}} \left(\boldsymbol{{x}}\right)}\:.\boldsymbol{{dx}}\:\: \\ $$
Question Number 216769 Answers: 1 Comments: 0
$${Solve}\:{for}\:{integer}\:{k},{m}\:{and}\:{n}: \\ $$$${k}^{\mathrm{2}} {m}−{n}^{\mathrm{2}} =\mathrm{8} \\ $$
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