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Question Number 146606 Answers: 1 Comments: 0

Question Number 146602 Answers: 1 Comments: 0

Question Number 146599 Answers: 0 Comments: 1

(1) from butanol what you need prepare 1 −butan ? (2) from alchols prepare 1−propan ? (3)from alkynes and what you need prepare C is and trans ethene ? (4) By hydrolysis of alkyle halide prepare 1−butane ?

$$\left(\mathrm{1}\right)\:{from}\:{butanol}\:{what}\:{you}\:{need}\:{prepare}\: \\ $$$$\mathrm{1}\:−{butan}\:? \\ $$$$ \\ $$$$\left(\mathrm{2}\right)\:{from}\:{alchols}\:{prepare}\:\mathrm{1}−{propan}\:? \\ $$$$ \\ $$$$\left(\mathrm{3}\right){from}\:{alkynes}\:{and}\:{what}\:{you}\:{need}\:{prepare}\:{C} \\ $$$${is}\:{and}\:{trans}\:{ethene}\:? \\ $$$$ \\ $$$$\left(\mathrm{4}\right)\:{By}\:{hydrolysis}\:{of}\:{alkyle}\:{halide}\:{prepare}\: \\ $$$$\mathrm{1}−{butane}\:? \\ $$

Question Number 146597 Answers: 5 Comments: 0

∫ ((cos 5x+cos 4x)/(1−2cos 3x)) dx =? ∫ ((√(tan x))/(sin 2x)) dx =? ∫ (dx/( (√(cos^3 x sin^5 x)))) =?

$$\:\:\:\:\int\:\frac{\mathrm{cos}\:\mathrm{5x}+\mathrm{cos}\:\mathrm{4x}}{\mathrm{1}−\mathrm{2cos}\:\mathrm{3x}}\:\mathrm{dx}\:=?\: \\ $$$$\:\:\int\:\frac{\sqrt{\mathrm{tan}\:\mathrm{x}}}{\mathrm{sin}\:\mathrm{2x}}\:\mathrm{dx}\:=? \\ $$$$\:\:\int\:\frac{\mathrm{dx}}{\:\sqrt{\mathrm{cos}\:^{\mathrm{3}} \mathrm{x}\:\mathrm{sin}\:^{\mathrm{5}} \mathrm{x}}}\:=? \\ $$

Question Number 146592 Answers: 0 Comments: 0

By hydrolysis of Grinyard reagent prepare butan ?

$${By}\:{hydrolysis}\:{of}\:{Grinyard}\:{reagent}\:{prepare}\:{butan}\:? \\ $$

Question Number 146590 Answers: 1 Comments: 1

Question Number 146589 Answers: 1 Comments: 0

arcsin (sin 10) = ?

$${arcsin}\:\left({sin}\:\mathrm{10}\right)\:=\:? \\ $$

Question Number 146587 Answers: 0 Comments: 0

arccos((π/2) - (1/2) arccos (4/5)) = ?

$${arccos}\left(\frac{\pi}{\mathrm{2}}\:-\:\frac{\mathrm{1}}{\mathrm{2}}\:{arccos}\:\frac{\mathrm{4}}{\mathrm{5}}\right)\:=\:? \\ $$

Question Number 146586 Answers: 0 Comments: 1

Question Number 146584 Answers: 0 Comments: 0

......nice ... ... ... calculus...... Ω= ∫_0 ^( 4) x^( 2) d (⌊x+⌊x +⌊x+⌊x⌋⌋⌋)=?

$$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:......{nice}\:...\:...\:...\:{calculus}...... \\ $$$$\: \\ $$$$\Omega=\:\int_{\mathrm{0}} ^{\:\mathrm{4}} {x}^{\:\mathrm{2}} \:{d}\:\left(\lfloor{x}+\lfloor{x}\:+\lfloor{x}+\lfloor{x}\rfloor\rfloor\rfloor\right)=?\: \\ $$$$ \\ $$

Question Number 146582 Answers: 1 Comments: 0

∫ tan^4 x cos^2 x dx =?

$$\:\:\:\int\:\mathrm{tan}\:^{\mathrm{4}} \mathrm{x}\:\mathrm{cos}\:^{\mathrm{2}} \mathrm{x}\:\mathrm{dx}\:=? \\ $$

Question Number 146577 Answers: 2 Comments: 1

Question Number 146559 Answers: 2 Comments: 0

lim_(x→−∞) (−2x+1+((8x^3 +2x^2 −10))^(1/3) )=? lim_(x→∞) (((125x^3 −5x^2 ))^(1/3) −4−5x )=?

$$\:\underset{{x}\rightarrow−\infty} {\mathrm{lim}}\:\left(−\mathrm{2}{x}+\mathrm{1}+\sqrt[{\mathrm{3}}]{\mathrm{8}{x}^{\mathrm{3}} +\mathrm{2}{x}^{\mathrm{2}} −\mathrm{10}}\:\right)=? \\ $$$$\:\underset{{x}\rightarrow\infty} {\mathrm{lim}}\left(\sqrt[{\mathrm{3}}]{\mathrm{125}{x}^{\mathrm{3}} −\mathrm{5}{x}^{\mathrm{2}} }−\mathrm{4}−\mathrm{5}{x}\:\right)=?\: \\ $$

Question Number 146550 Answers: 0 Comments: 0

f(x)=x^3 arctan((2/x)) 1)calculate f^((n)) (x) 2)developp f at integr srie at x_0 =1

$$\mathrm{f}\left(\mathrm{x}\right)=\mathrm{x}^{\mathrm{3}} \:\mathrm{arctan}\left(\frac{\mathrm{2}}{\mathrm{x}}\right) \\ $$$$\left.\mathrm{1}\right)\mathrm{calculate}\:\:\mathrm{f}^{\left(\mathrm{n}\right)} \left(\mathrm{x}\right) \\ $$$$\left.\mathrm{2}\right)\mathrm{developp}\:\mathrm{f}\:\mathrm{at}\:\mathrm{integr}\:\mathrm{srie}\:\mathrm{at}\:\mathrm{x}_{\mathrm{0}} =\mathrm{1} \\ $$

Question Number 146549 Answers: 2 Comments: 0

find lim_(x→0) ((cos(x−sinx)+1−cos(x^2 ))/x^2 )

$$\mathrm{find}\:\mathrm{lim}_{\mathrm{x}\rightarrow\mathrm{0}} \:\frac{\mathrm{cos}\left(\mathrm{x}−\mathrm{sinx}\right)+\mathrm{1}−\mathrm{cos}\left(\mathrm{x}^{\mathrm{2}} \right)}{\mathrm{x}^{\mathrm{2}} } \\ $$

Question Number 146548 Answers: 2 Comments: 0

let f(x)=cos(αx) developp f at fourier serie (α real)

$$\mathrm{let}\:\mathrm{f}\left(\mathrm{x}\right)=\mathrm{cos}\left(\alpha\mathrm{x}\right)\:\mathrm{developp}\:\mathrm{f}\:\mathrm{at}\:\mathrm{fourier}\:\mathrm{serie}\:\:\left(\alpha\:\mathrm{real}\right) \\ $$

Question Number 146547 Answers: 3 Comments: 0

calculate ∫_(∣z∣=5) ((2−z^2 )/((z^2 +9)(z−i)^2 ))dz

$$\mathrm{calculate}\:\int_{\mid\mathrm{z}\mid=\mathrm{5}} \:\:\:\frac{\mathrm{2}−\mathrm{z}^{\mathrm{2}} }{\left(\mathrm{z}^{\mathrm{2}} +\mathrm{9}\right)\left(\mathrm{z}−\mathrm{i}\right)^{\mathrm{2}} }\mathrm{dz} \\ $$

Question Number 146546 Answers: 2 Comments: 0

find ∫_(∣z−1∣=3) ((cos(πz))/((z−2)(z^2 +4)))dz

$$\mathrm{find}\:\int_{\mid\mathrm{z}−\mathrm{1}\mid=\mathrm{3}} \:\:\frac{\mathrm{cos}\left(\pi\mathrm{z}\right)}{\left(\mathrm{z}−\mathrm{2}\right)\left(\mathrm{z}^{\mathrm{2}} +\mathrm{4}\right)}\mathrm{dz} \\ $$

Question Number 146545 Answers: 1 Comments: 0

arcsin(x^2 -3) = arcsin(x^2 +3x+4) find x=?

$${arcsin}\left({x}^{\mathrm{2}} -\mathrm{3}\right)\:=\:{arcsin}\left({x}^{\mathrm{2}} +\mathrm{3}{x}+\mathrm{4}\right) \\ $$$${find}\:\:\boldsymbol{{x}}=? \\ $$

Question Number 146535 Answers: 2 Comments: 0

{ ((((15)/(x^2 +xy)) + (3/(y^2 +xy)) = 5,5)),((((12)/(x^2 +xy)) - (6/(y^2 +xy)) = 3)) :} ⇒ ∣x+y∣=?

$$\begin{cases}{\frac{\mathrm{15}}{{x}^{\mathrm{2}} +{xy}}\:+\:\frac{\mathrm{3}}{{y}^{\mathrm{2}} +{xy}}\:=\:\mathrm{5},\mathrm{5}}\\{\frac{\mathrm{12}}{{x}^{\mathrm{2}} +{xy}}\:-\:\frac{\mathrm{6}}{{y}^{\mathrm{2}} +{xy}}\:=\:\mathrm{3}}\end{cases}\:\:\:\Rightarrow\:\:\mid{x}+{y}\mid=? \\ $$

Question Number 146529 Answers: 1 Comments: 0

Question Number 146528 Answers: 1 Comments: 0

Question Number 146524 Answers: 0 Comments: 0

find ∫_0 ^∞ ((xsinx)/((x^4 +1)^3 ))dx

$$\mathrm{find}\:\int_{\mathrm{0}} ^{\infty} \:\:\frac{\mathrm{xsinx}}{\left(\mathrm{x}^{\mathrm{4}} \:+\mathrm{1}\right)^{\mathrm{3}} }\mathrm{dx} \\ $$

Question Number 146523 Answers: 2 Comments: 0

Question Number 146521 Answers: 1 Comments: 0

(i - 1)^(−100) = ?

$$\left(\boldsymbol{{i}}\:-\:\mathrm{1}\right)^{−\mathrm{100}} \:=\:? \\ $$

Question Number 146519 Answers: 0 Comments: 0

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