it is known that after injecting the 1^(st)
dosage of a drug in exactly hours
p(t)= { ((Ae^(−(t/(24))) , 0≤t≤8)),(((A+Ae^(−(1/3)) )e^(−(((t−8)/(24)))) , 8 ≤ t≤24)) :}
A is the initial dosage at t= 0hours
a) show that towards the application of
the n^(th) dosage , the dosage remained in blood is
(((1−e^(−(1/n)) )/(1−e^(−(1/3)) )))×A
|