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Question Number 156610 Answers: 2 Comments: 0
$$\mathrm{If}\:\mathrm{A}\:\mathrm{and}\:\mathrm{B}\:\mathrm{are}\:\mathrm{invertible}\:\mathrm{matrices},\mathrm{then}: \\ $$$$\left(\mathrm{AB}\right)^{−\mathrm{1}} =\mathrm{B}^{−\mathrm{1}} \mathrm{A}^{−\mathrm{1}} \neq\:\mathrm{A}^{−\mathrm{1}} \mathrm{B}^{−\mathrm{1}} \\ $$$$\boldsymbol{\mathrm{proove}}. \\ $$
Question Number 156609 Answers: 1 Comments: 0
Question Number 156604 Answers: 1 Comments: 2
Question Number 156595 Answers: 0 Comments: 2
$$\mathrm{Mary}\:\mathrm{walks}\:\mathrm{9}\:\mathrm{city}\:\mathrm{blocks}\:\mathrm{south}, \\ $$$$\mathrm{2}\:\mathrm{blocks}\:\mathrm{east},\:\mathrm{3}\:\mathrm{blocks}\:\mathrm{south}\:\mathrm{and}\: \\ $$$$\mathrm{7}\:\mathrm{blocks}\:\mathrm{east}.\:\mathrm{if}\:\mathrm{all}\:\mathrm{blocks}\:\mathrm{are}\:\mathrm{the}\:\mathrm{same} \\ $$$$\mathrm{length}.\:\mathrm{How}\:\mathrm{far}\:\mathrm{is}\:\mathrm{she}\:\mathrm{from}\:\mathrm{her}\:\mathrm{starting} \\ $$$$\mathrm{point}. \\ $$$$ \\ $$$$\mathrm{please}\:\mathrm{help}\:\mathrm{with}\:\mathrm{the}\:\mathrm{aid}\:\mathrm{of}\:\mathrm{a}\:\mathrm{diagram} \\ $$
Question Number 156593 Answers: 1 Comments: 1
Question Number 156591 Answers: 0 Comments: 0
$${Find}\:{all}\:{the}\:{triplets}\:\left({a},\:{b},\:{c}\right)\:{of}\:{pozitif}\:{integers} \\ $$$${such}\:{that} \\ $$$$\boldsymbol{\mathrm{a}}^{\mathrm{3}} +\boldsymbol{\mathrm{b}}^{\mathrm{3}} +\boldsymbol{\mathrm{c}}^{\mathrm{3}} =\left(\boldsymbol{\mathrm{abc}}\right)^{\mathrm{2}} \\ $$$$ \\ $$$$ \\ $$$$?????? \\ $$
Question Number 156590 Answers: 1 Comments: 0
Question Number 156586 Answers: 0 Comments: 0
Question Number 156584 Answers: 1 Comments: 1
$$\mathrm{find}\:\mathrm{p}\:\mathrm{if}\:\mathrm{y}=\mathrm{1}−\mathrm{px}−\mathrm{3x}^{\mathrm{2}} \\ $$$$\mathrm{if}\:\mathrm{the}\:\mathrm{maximum}\:\mathrm{is}\:\mathrm{13}\:\:\left(\mathrm{help}\:\mathrm{pls}\right) \\ $$
Question Number 156579 Answers: 1 Comments: 0
$$\:\boldsymbol{\mathrm{Find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{value}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{x}}\:\boldsymbol{\mathrm{by}}\:\boldsymbol{\mathrm{using}}\:\boldsymbol{\mathrm{Cardon}}'\boldsymbol{\mathrm{s}}\:\boldsymbol{\mathrm{Method}}. \\ $$$$\:\:\:\frac{\mathrm{1}}{\boldsymbol{\mathrm{x}}}\:+\:\frac{\mathrm{2}}{\boldsymbol{\mathrm{x}}+\mathrm{1}}+\:\frac{\mathrm{3}}{\boldsymbol{\mathrm{x}}+\mathrm{2}}\:=\:\mathrm{1} \\ $$
Question Number 156578 Answers: 0 Comments: 0
Question Number 156577 Answers: 0 Comments: 4
Question Number 156575 Answers: 1 Comments: 1
$$\mathrm{let}\:\:\mathrm{n}\geqslant\mathrm{1}\:\:\mathrm{and}\:\:\lambda=\mathrm{2n}^{\mathrm{2}} -\mathrm{2n}+\mathrm{1} \\ $$$$\mathrm{solve}\:\mathrm{for}\:\mathrm{real}\:\mathrm{numbers}: \\ $$$$\sqrt{\lambda\:+\:\mathrm{x}^{\mathrm{2}} }\:-\:\sqrt{\lambda\:-\:\mathrm{x}^{\mathrm{2}} }\:=\:\frac{\mathrm{x}^{\mathrm{2}} }{\mathrm{n}} \\ $$
Question Number 156574 Answers: 0 Comments: 0
$$\mathrm{if}\:\:\mathrm{a};\mathrm{b};\mathrm{c}>\mathrm{0}\:\:\mathrm{and}\:\:\frac{\mathrm{1}}{\mathrm{a}+\mathrm{b}}\:+\:\frac{\mathrm{1}}{\mathrm{b}+\mathrm{c}}\:+\:\frac{\mathrm{1}}{\mathrm{c}+\mathrm{a}}\:=\:\mathrm{4}\:\:\mathrm{then}: \\ $$$$\frac{\mathrm{1}}{\mathrm{a}}\:+\:\frac{\mathrm{1}}{\mathrm{b}}\:+\:\frac{\mathrm{1}}{\mathrm{c}}\:+\:\frac{\mathrm{9}}{\mathrm{a}+\mathrm{b}+\mathrm{c}}\:\geqslant\:\mathrm{16} \\ $$
Question Number 156600 Answers: 2 Comments: 0
$$\int\:\frac{{e}^{{x}} }{{e}^{\mathrm{2}{x}} +\mathrm{4}}\:{dx}\:=?\: \\ $$
Question Number 156557 Answers: 0 Comments: 1
Question Number 156548 Answers: 1 Comments: 2
Question Number 156543 Answers: 0 Comments: 0
Question Number 156536 Answers: 0 Comments: 0
Question Number 156535 Answers: 1 Comments: 0
Question Number 156534 Answers: 2 Comments: 1
Question Number 156532 Answers: 1 Comments: 0
Question Number 156529 Answers: 1 Comments: 0
Question Number 156522 Answers: 0 Comments: 1
Question Number 156520 Answers: 1 Comments: 0
$$\boldsymbol{{if}}\:\mid\:\boldsymbol{{z}}+\mathrm{6}\boldsymbol{{i}}\:\mid\leqslant\mathrm{5}\:\boldsymbol{{find}}\:\boldsymbol{{the}}\:\boldsymbol{{maximum}}\:\boldsymbol{{and}}\:\boldsymbol{{minimum}}\:\boldsymbol{{value}}\:\boldsymbol{{of}}\:\mid\:\boldsymbol{{z}}+\mathrm{5}\mid\:? \\ $$
Question Number 156513 Answers: 0 Comments: 3
$$\mathrm{x}^{\mathrm{4}} +\mathrm{4x}^{\mathrm{3}} −\mathrm{26x}^{\mathrm{2}} −\mathrm{20x}+\mathrm{25}=\mathrm{0} \\ $$$$\mathrm{x}=?\:\left(\mathrm{exact}\:\mathrm{form}\right) \\ $$
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