Question and Answers Forum

All Questions Topic List

AllQuestion and Answers: Page 60

Question Number 218735 Answers: 5 Comments: 0

Question Number 218734 Answers: 7 Comments: 0

Question Number 218733 Answers: 4 Comments: 1

Question Number 218719 Answers: 0 Comments: 0

Question Number 218713 Answers: 1 Comments: 3

Question Number 218709 Answers: 2 Comments: 0

∫_0 ^(π/2) (dθ/( (√(sinθ +cosθ))))

$$ \\ $$$$\:\:\:\:\:\:\int_{\mathrm{0}} ^{\pi/\mathrm{2}} \:\frac{{d}\theta}{\:\sqrt{{sin}\theta\:+{cos}\theta}} \\ $$$$ \\ $$

Question Number 218703 Answers: 3 Comments: 0

Prove; lim_(x→0) ((x − sin x)/x^3 ) = (1/6)

$$ \\ $$$$\:\:\:\:{Prove};\:{lim}_{{x}\rightarrow\mathrm{0}} \:\frac{{x}\:−\:{sin}\:{x}}{{x}^{\mathrm{3}} }\:=\:\frac{\mathrm{1}}{\mathrm{6}}\:\: \\ $$$$ \\ $$

Question Number 218676 Answers: 2 Comments: 0

Question Number 218675 Answers: 4 Comments: 0

Question Number 218674 Answers: 3 Comments: 0

Question Number 218673 Answers: 3 Comments: 1

Question Number 218672 Answers: 2 Comments: 0

Question Number 218662 Answers: 4 Comments: 0

Prove: ∫^∞ _0 ((sin(x))/x) dx = (π/2)

$$\: \\ $$$$\:\:\:\:{Prove}:\:\:\:\:\underset{\mathrm{0}} {\int}^{\infty} \:\frac{{sin}\left({x}\right)}{{x}}\:{dx}\:=\:\frac{\pi}{\mathrm{2}} \\ $$$$ \\ $$

Question Number 218658 Answers: 2 Comments: 0

Question Number 218769 Answers: 1 Comments: 0

Fourier Series f(θ)=e^(izsin(θ))

$$\mathrm{Fourier}\:\mathrm{Series}\:{f}\left(\theta\right)={e}^{\boldsymbol{{i}}{z}\mathrm{sin}\left(\theta\right)} \\ $$

Question Number 218656 Answers: 2 Comments: 0

resolve the equation with unknow p P is polynom 1) P(X^2 )=(X^2 +1)P(X) 2) P 0P =P

$${resolve}\:{the}\:{equation}\:{with}\:{unknow}\:{p} \\ $$$${P}\:\:{is}\:{polynom}\: \\ $$$$\left.\mathrm{1}\right)\:{P}\left({X}^{\mathrm{2}} \right)=\left({X}^{\mathrm{2}} +\mathrm{1}\right){P}\left({X}\right) \\ $$$$\left.\mathrm{2}\right)\:{P}\:\mathrm{0}{P}\:={P} \\ $$

Question Number 218652 Answers: 0 Comments: 4

Angle of incidence is 40° if the direction of the incidence ray is constant and the mirror is rotated through 20° the angle between the new reflected ray and new normal is

Angle of incidence is 40° if the direction of the incidence ray is constant and the mirror is rotated through 20° the angle between the new reflected ray and new normal is

Question Number 218651 Answers: 1 Comments: 0

Question Number 218650 Answers: 1 Comments: 0

Question Number 218649 Answers: 2 Comments: 0

Question Number 218648 Answers: 1 Comments: 0

Question Number 218646 Answers: 1 Comments: 1

Question Number 218645 Answers: 4 Comments: 0

Question Number 218644 Answers: 2 Comments: 0

Question Number 218636 Answers: 1 Comments: 0

Question Number 218629 Answers: 1 Comments: 0

Pg 55 Pg 56 Pg 57 Pg 58 Pg 59 Pg 60 Pg 61 Pg 62 Pg 63 Pg 64

Terms of Service

Contact: info@tinkutara.com