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Question Number 159852 Answers: 2 Comments: 0
Question Number 159845 Answers: 2 Comments: 1
$$\mathrm{if}\:{q}\:=\:\mathrm{1}−{sin}\theta;\:\mathrm{then}\:\mathrm{prove}\:\mathrm{that} \\ $$$$\left({sec}\theta\:−\:{tan}\theta\right)^{\mathrm{2}} \:=\:\frac{\mathrm{1}}{{q}} \\ $$
Question Number 159844 Answers: 0 Comments: 0
Question Number 159842 Answers: 2 Comments: 4
$$\mathrm{if}\:{p}−\mathrm{5}\:=\:\mathrm{2}\sqrt{\mathrm{6}}\:\mathrm{then}\:\mathrm{prove}\:\mathrm{that} \\ $$$${p}\sqrt{{p}}−\frac{\mathrm{1}}{{p}\sqrt{{p}}}\:=\:\mathrm{22}\sqrt{\mathrm{2}} \\ $$
Question Number 159839 Answers: 1 Comments: 0
$${q}=\mathrm{2}\sqrt{\mathrm{2}\sqrt{\mathrm{2}}} \\ $$
Question Number 159837 Answers: 1 Comments: 0
$$\:\:\underset{{x}\rightarrow−\infty} {\mathrm{lim}}\:\sqrt{\mathrm{2021}{x}^{\mathrm{2}} −\mathrm{6}{x}}\:+\sqrt[{\mathrm{3}}]{\mathrm{1021}{x}^{\mathrm{3}} −\mathrm{5}{x}}\:=? \\ $$
Question Number 159829 Answers: 0 Comments: 2
$$\left(\frac{\boldsymbol{\mathrm{y}}}{\boldsymbol{\mathrm{b}}}\right)^{\frac{\mathrm{2}}{\mathrm{3}}} +\left(\frac{\boldsymbol{\mathrm{x}}}{\boldsymbol{\mathrm{a}}}\right)^{\frac{\mathrm{2}}{\mathrm{3}}} =\mathrm{1}\:\: \\ $$$$\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{length}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{line}} \\ $$
Question Number 159828 Answers: 0 Comments: 6
Question Number 159817 Answers: 0 Comments: 0
Question Number 159823 Answers: 2 Comments: 0
Question Number 159796 Answers: 1 Comments: 0
$$\mathrm{Montrer}\:\mathrm{que}\:\mathrm{la}\:\mathrm{suite}\:\mathrm{d}\acute {\mathrm{e}finie}\:\mathrm{par}\: \\ $$$${u}_{{n}} =\underset{{k}=\mathrm{1}} {\overset{{n}} {\sum}}\frac{{x}^{{k}} }{{k}}\:\mathrm{est}\:\mathrm{une}\:\mathrm{suite}\:\mathrm{de}\:\mathrm{Cauchy}. \\ $$
Question Number 159794 Answers: 1 Comments: 8
Question Number 159787 Answers: 0 Comments: 2
$$\mathrm{if}\:{cos}^{\mathrm{4}} \theta\:−\:{sin}^{\mathrm{4}} \theta\:=\:\mathrm{2}\:−\:\mathrm{5}{cos}\theta \\ $$$$\mathrm{then}\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\theta \\ $$
Question Number 159786 Answers: 0 Comments: 0
$$\mathrm{Work}\:\mathrm{out}\:\mathrm{and}\:\mathrm{sketch}\:\mathrm{P}_{\mathrm{y}} \:\mathrm{orbitals} \\ $$
Question Number 159785 Answers: 0 Comments: 0
$$\mathrm{work}\:\mathrm{out}\:\mathrm{and}\:\mathrm{sketch}\:\mathrm{d}−\mathrm{orbital}\:\mathrm{for}\:\mathrm{the}\:\mathrm{function} \\ $$$$\left.\mathrm{i}\right)\:\mathrm{f}_{\mathrm{1}} =\mathrm{3Cos}^{\mathrm{2}} \theta−\mathrm{1} \\ $$$$\left.\mathrm{i}\right)\:\mathrm{f}_{\mathrm{2}} =\mathrm{Sin}\theta\mathrm{Cos}\theta\mathrm{Cos}\phi \\ $$
Question Number 159784 Answers: 0 Comments: 1
Question Number 159939 Answers: 1 Comments: 2
$$\mathrm{U}_{{n}+\mathrm{2}} −\mathrm{2U}_{{n}+\mathrm{1}} +\mathrm{U}_{{n}} =\mathrm{800} \\ $$
Question Number 159777 Answers: 2 Comments: 1
$$\mathrm{if}\:{x}\:+\:{y}\:=\:\sqrt{\mathrm{7}}\:\mathrm{and}\:{x}^{\mathrm{2}} \:−\:{y}^{\mathrm{2}} \:=\:\sqrt{\mathrm{35}}\:; \\ $$$$\mathrm{then}\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{16}{xy}\left({x}^{\mathrm{2}} \:+\:{y}^{\mathrm{2}} \right) \\ $$
Question Number 159775 Answers: 1 Comments: 0
$$\prod_{\mathrm{n}=\mathrm{1}} ^{\infty} \frac{\alpha^{\mathrm{3}} +\beta^{\mathrm{2}} }{\mathrm{3}^{\mathrm{n}} }=\:? \\ $$$$\mathrm{in}\:\mathrm{expanded}\:\mathrm{form} \\ $$
Question Number 159781 Answers: 0 Comments: 0
Question Number 159771 Answers: 0 Comments: 1
Question Number 159768 Answers: 1 Comments: 1
Question Number 159763 Answers: 0 Comments: 4
Question Number 159762 Answers: 1 Comments: 0
$$\:\:\:{Given}\:\mathrm{log}\:_{\mathrm{3}} \left({n}\right)=\:\mathrm{log}\:_{\mathrm{6}} \left({m}\right)=\mathrm{log}\:_{\mathrm{12}} \left({m}+{n}\right) \\ $$$$\:\:\:\frac{{m}}{{n}}\:=\:? \\ $$
Question Number 159759 Answers: 1 Comments: 0
Question Number 159757 Answers: 0 Comments: 1
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