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Question Number 161060 Answers: 1 Comments: 2

Given sin(5x−38)=cos(2x+16), 0°≤x≤90°, find the value of x

$$\mathrm{Given}\:\mathrm{sin}\left(\mathrm{5x}−\mathrm{38}\right)=\mathrm{cos}\left(\mathrm{2x}+\mathrm{16}\right),\:\mathrm{0}°\leqslant\mathrm{x}\leqslant\mathrm{90}°, \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{x} \\ $$

Question Number 161059 Answers: 0 Comments: 0

Find: 𝛀 =∫_( 0) ^( 1) ∫_( 0) ^( 1) (x^2 +2xy+x)ln(1 + (1/(x+y)))dxdy

$$\mathrm{Find}: \\ $$$$\boldsymbol{\Omega}\:=\underset{\:\mathrm{0}} {\overset{\:\mathrm{1}} {\int}}\:\underset{\:\mathrm{0}} {\overset{\:\mathrm{1}} {\int}}\:\left(\mathrm{x}^{\mathrm{2}} +\mathrm{2xy}+\mathrm{x}\right)\mathrm{ln}\left(\mathrm{1}\:+\:\frac{\mathrm{1}}{\mathrm{x}+\mathrm{y}}\right)\mathrm{dxdy} \\ $$

Question Number 161058 Answers: 1 Comments: 0

Solve the differential equation: x(y-1)dx + (x+1)dy = 0

$$\mathrm{Solve}\:\mathrm{the}\:\mathrm{differential}\:\mathrm{equation}: \\ $$$$\mathrm{x}\left(\mathrm{y}-\mathrm{1}\right)\mathrm{dx}\:+\:\left(\mathrm{x}+\mathrm{1}\right)\mathrm{dy}\:=\:\mathrm{0} \\ $$$$ \\ $$

Question Number 161039 Answers: 0 Comments: 0

let the differential equation: (1 + x) y^(′′) (x) + (1 - x) y^′ (x) = ((1-x)/(1+x)) y(x) y(0) = 1 , y^′ (0) = 0 then prove that: ∫_( 0) ^( ∞) (y^(′′) (x) + y^′ (x) + y(x)) e^(-x) dx = (3/2)

$$\mathrm{let}\:\mathrm{the}\:\mathrm{differential}\:\mathrm{equation}: \\ $$$$\left(\mathrm{1}\:+\:\mathrm{x}\right)\:\mathrm{y}^{''} \left(\mathrm{x}\right)\:+\:\left(\mathrm{1}\:-\:\mathrm{x}\right)\:\mathrm{y}^{'} \left(\mathrm{x}\right)\:=\:\frac{\mathrm{1}-\mathrm{x}}{\mathrm{1}+\mathrm{x}}\:\mathrm{y}\left(\mathrm{x}\right) \\ $$$$\mathrm{y}\left(\mathrm{0}\right)\:=\:\mathrm{1}\:,\:\mathrm{y}^{'} \left(\mathrm{0}\right)\:=\:\mathrm{0} \\ $$$$\mathrm{then}\:\mathrm{prove}\:\mathrm{that}: \\ $$$$\underset{\:\mathrm{0}} {\overset{\:\infty} {\int}}\left(\mathrm{y}^{''} \left(\mathrm{x}\right)\:+\:\mathrm{y}^{'} \left(\mathrm{x}\right)\:+\:\mathrm{y}\left(\mathrm{x}\right)\right)\:\mathrm{e}^{-\boldsymbol{\mathrm{x}}} \:\mathrm{dx}\:=\:\frac{\mathrm{3}}{\mathrm{2}} \\ $$

Question Number 161026 Answers: 0 Comments: 0

Question Number 161025 Answers: 1 Comments: 0

Two commodities A and B cost $70 and $80 per kg respectively. If 34.5kg of A is mixed with 26kg of B and the mixture is sold at $85 per kg, calculate the percentage profit. please help me out, I′m somehow confused

$${Two}\:{commodities}\:{A}\:{and}\:{B}\:{cost} \\ $$$$\$\mathrm{70}\:{and}\:\$\mathrm{80}\:{per}\:{kg}\:{respectively}. \\ $$$${If}\:\mathrm{34}.\mathrm{5}{kg}\:{of}\:{A}\:{is}\:{mixed}\:{with}\:\mathrm{26}{kg} \\ $$$${of}\:{B}\:{and}\:{the}\:{mixture}\:{is}\:{sold}\:{at} \\ $$$$\$\mathrm{85}\:{per}\:{kg},\:{calculate}\:{the}\:{percentage} \\ $$$${profit}. \\ $$$${please}\:{help}\:{me}\:{out},\:{I}'{m}\:{somehow} \\ $$$${confused} \\ $$

Question Number 161023 Answers: 1 Comments: 2