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Question Number 155361 Answers: 0 Comments: 0
$${x}−\mathrm{4}{z}+\mathrm{8}{y}=\mathrm{7} \\ $$$$\mathrm{8}×+\mathrm{7}{z}−{y}=\mathrm{4} \\ $$$${x}^{\mathrm{2}} +{y}^{\mathrm{2}} −{z}^{\mathrm{2}} =? \\ $$
Question Number 155360 Answers: 1 Comments: 0
Question Number 155359 Answers: 0 Comments: 1
Question Number 155357 Answers: 1 Comments: 1
Question Number 155356 Answers: 0 Comments: 0
$$\mathrm{Find}\:\mathrm{the}\:\mathrm{coefficient}\:\mathrm{of}\:\mathrm{term}\:``\:\mathrm{a}^{\mathrm{m}} \mathrm{b}^{\mathrm{2m}} \:''\:\mathrm{in}\:\left(\mathrm{1}+\mathrm{a}\right)^{\mathrm{m}} \left(\mathrm{1}+\mathrm{b}\right)^{\mathrm{n}+\mathrm{m}} \left(\mathrm{1}+\mathrm{a}+\mathrm{b}\right)^{\mathrm{m}} . \\ $$
Question Number 155353 Answers: 2 Comments: 0
$$\boldsymbol{{show}}\:\boldsymbol{{that}}\:\:\boldsymbol{{lim}}_{\boldsymbol{{x}}\rightarrow\mathrm{0}} \frac{\boldsymbol{{sinx}}}{\boldsymbol{{x}}}\:=\:\mathrm{1} \\ $$
Question Number 155352 Answers: 0 Comments: 0
Question Number 155345 Answers: 2 Comments: 1
$$\mathrm{Solve}\:\mathrm{the}\:\mathrm{equation}\:\mathrm{in}\:\mathbb{R} \\ $$$$\frac{\mathrm{5}\sqrt{\mathrm{x}+\mathrm{1}}}{\:\sqrt{\mathrm{1}\:-\:\mathrm{x}\:+\:\mathrm{x}^{\mathrm{2}} }\:+\:\mathrm{2}\sqrt{\mathrm{x}\:+\:\mathrm{1}}}\:=\:\mathrm{4x}^{\mathrm{2}} \:-\:\mathrm{5x}\:+\:\mathrm{5} \\ $$
Question Number 155344 Answers: 1 Comments: 0
$$\mathrm{Solve}\:\mathrm{for}\:\mathrm{integers}: \\ $$$$ \\ $$$$\mathrm{x}^{\mathrm{2}} \:-\:\mathrm{3x}\left(\mathrm{y}^{\mathrm{2}} \:+\:\mathrm{y}\:-\:\mathrm{1}\right)\:+\:\mathrm{4y}^{\mathrm{2}} \:+\:\mathrm{4y}\:-\:\mathrm{6}\:=\:\mathrm{0} \\ $$
Question Number 155335 Answers: 1 Comments: 0
$$\mathrm{2x}^{\mathrm{5}} \:+\:\mathrm{3x}^{\mathrm{4}} \:-\:\mathrm{7x}^{\mathrm{3}} \:-\:\mathrm{7x}^{\mathrm{2}} \:+\:\mathrm{3x}\:+\:\mathrm{2}\:=\:\mathrm{0} \\ $$$$\mathrm{x}_{\mathrm{1}.\mathrm{2}.\mathrm{3}.\mathrm{4}.\mathrm{5}} \:=\:? \\ $$
Question Number 155331 Answers: 1 Comments: 0
$$\mathrm{what}\:\mathrm{is}\:\mathrm{limit}?\:\mathrm{also}\:\mathrm{where}\:\mathrm{we}\:\mathrm{use}\:\mathrm{it}. \\ $$
Question Number 155323 Answers: 0 Comments: 0
Question Number 155316 Answers: 4 Comments: 0
$$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\left(\sqrt{{x}^{\mathrm{2}} +\mathrm{3}{x}}−{x}\right)=? \\ $$
Question Number 155403 Answers: 0 Comments: 0
Question Number 155337 Answers: 0 Comments: 0
Question Number 155310 Answers: 1 Comments: 0
$$\mathrm{lim}\:\:\:\:{U}_{{n}} =\underset{{k}={o}} {\overset{{n}−\mathrm{1}} {\sum}}\:\:\frac{{n}\left({ln}\left({n}+{k}\right)\right)−{ln}\left({n}\right)}{{n}^{\mathrm{2}} +{k}^{\mathrm{2}} } \\ $$
Question Number 155302 Answers: 0 Comments: 0
Question Number 155295 Answers: 0 Comments: 2
$$\mathrm{Evaluate}:\:\:\:\underset{\boldsymbol{\mathrm{n}}\rightarrow\infty} {\mathrm{lim}}\frac{\Sigma\:\boldsymbol{\mathrm{n}}}{\boldsymbol{\mathrm{n}}^{\mathrm{2}} }\:=\:? \\ $$
Question Number 155294 Answers: 1 Comments: 0
Question Number 155293 Answers: 2 Comments: 0
Question Number 155292 Answers: 1 Comments: 0
Question Number 155285 Answers: 0 Comments: 0
Question Number 155281 Answers: 1 Comments: 0
$$ \\ $$$$\:{f}\::\left[\:\mathrm{0}\:,\:\:\mathrm{6}\right]\:\rightarrow\:\left[−\mathrm{4}\:,\:\mathrm{4}\right] \\ $$$$\:\:\:{f}\:\left(\mathrm{0}\:\right)=\mathrm{0} \\ $$$$\:\:\:\:{f}\:\left(\mathrm{6}\:\right)=\mathrm{4}\: \\ $$$$\:\:{x},\:\:{y}\geqslant\mathrm{0}\:\:,\:{x}+{y}\:\leqslant\mathrm{6} \\ $$$$\:\:\:{f}\:\left({x}+{y}\:\right)=\frac{\mathrm{1}}{\mathrm{4}}\left\{{f}\left({x}\right)\sqrt{\mathrm{16}−\left({f}\left({y}\right)\right)^{\mathrm{2}} }\:+{f}\left({y}\right)\sqrt{\mathrm{16}−\left({f}\left({x}\right)\right)^{\mathrm{2}} }\:\right\} \\ $$$$\:\:\therefore\:\:\:\left(\:{f}\left(\mathrm{1}\right)\:+{f}\:\left(\mathrm{3}\right)\right)^{\:\mathrm{2}} =? \\ $$
Question Number 155277 Answers: 2 Comments: 0
Question Number 155272 Answers: 0 Comments: 3
Question Number 155265 Answers: 1 Comments: 0
$${si}\:{E}\:{est}\:{la}\:{fonction}\:{partie}\:{entiere}\:,{et}\:{n}\:{un}\:{entier}\:{naturel} \\ $$$${alors}\:{I}=\int_{{o}} ^{{n}} {E}\left({x}\right)\:{vaut}? \\ $$
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