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Question Number 163926 Answers: 2 Comments: 0

{: ((sin θ=1−sin^2 θ)),((csc^2 θ−tan^2 θ =? )) }

$$\:\:\:\:\:\:\:\:\:\:\:\:\:\left.\begin{matrix}{\mathrm{sin}\:\theta=\mathrm{1}−\mathrm{sin}\:^{\mathrm{2}} \theta}\\{\mathrm{csc}\:^{\mathrm{2}} \theta−\mathrm{tan}\:^{\mathrm{2}} \theta\:=?\:}\end{matrix}\right\} \\ $$

Question Number 163921 Answers: 2 Comments: 0

Question Number 163914 Answers: 0 Comments: 0

Question Number 163913 Answers: 0 Comments: 0

Question Number 163912 Answers: 0 Comments: 1

Question Number 163906 Answers: 1 Comments: 0

{ ((x^3 + x + 6 = 8y)),((y^3 + y + 6 = 8z)),((z^3 + z + 6 = 8x)) :} ⇒ x;y;z = ?

$$\begin{cases}{\mathrm{x}^{\mathrm{3}} \:+\:\mathrm{x}\:+\:\mathrm{6}\:=\:\mathrm{8y}}\\{\mathrm{y}^{\mathrm{3}} \:+\:\mathrm{y}\:+\:\mathrm{6}\:=\:\mathrm{8z}}\\{\mathrm{z}^{\mathrm{3}} \:+\:\mathrm{z}\:+\:\mathrm{6}\:=\:\mathrm{8x}}\end{cases}\:\:\:\Rightarrow\:\:\:\mathrm{x};\mathrm{y};\mathrm{z}\:=\:? \\ $$

Question Number 163905 Answers: 0 Comments: 0

Question Number 163903 Answers: 0 Comments: 0

prouve a/bc ,si (a,b)=1,alors a/c

$${prouve}\: \\ $$$${a}/{bc}\:,{si}\:\left({a},{b}\right)=\mathrm{1},{alors} \\ $$$${a}/{c} \\ $$

Question Number 163902 Answers: 1 Comments: 0

(√(x!^(x!) )) + 2^(x!) = x!^3 + 10x! + 4 find: x = ?

$$\sqrt{\mathrm{x}!^{\boldsymbol{\mathrm{x}}!} }\:\:+\:\:\mathrm{2}^{\boldsymbol{\mathrm{x}}!} \:\:=\:\mathrm{x}!^{\mathrm{3}} \:\:+\:\:\mathrm{10x}!\:\:+\:\:\mathrm{4} \\ $$$$\mathrm{find}:\:\:\boldsymbol{\mathrm{x}}\:=\:? \\ $$

Question Number 163899 Answers: 2 Comments: 0

Find: 𝛀 = ∫_( 0) ^( 1) ((cos(ax))/( (√x) ∙ (√(1 - x)))) dx

$$\mathrm{Find}:\:\:\boldsymbol{\Omega}\:=\:\underset{\:\mathrm{0}} {\overset{\:\mathrm{1}} {\int}}\:\frac{\mathrm{cos}\left(\mathrm{ax}\right)}{\:\sqrt{\mathrm{x}}\:\centerdot\:\sqrt{\mathrm{1}\:-\:\mathrm{x}}}\:\mathrm{dx} \\ $$

Question Number 163897 Answers: 2 Comments: 0

if x^3 = 1 and x ≠ 1 simplificar (((1/x^4 )/(1 + x^5 )))^3

$$\mathrm{if}\:\:\mathrm{x}^{\mathrm{3}} \:=\:\mathrm{1}\:\:\mathrm{and}\:\:\mathrm{x}\:\neq\:\mathrm{1} \\ $$$$\mathrm{simplificar}\:\:\left(\frac{\frac{\mathrm{1}}{\mathrm{x}^{\mathrm{4}} }}{\mathrm{1}\:+\:\mathrm{x}^{\mathrm{5}} }\right)^{\mathrm{3}} \\ $$

Question Number 163891 Answers: 2 Comments: 0

if f(x^3 + 1) = x^5 + 4x + 2 find ∫_( 0) ^( 1) f(x) dx = ?

$$\mathrm{if}\:\:\:\mathrm{f}\left(\mathrm{x}^{\mathrm{3}} \:+\:\mathrm{1}\right)\:=\:\mathrm{x}^{\mathrm{5}} \:+\:\mathrm{4x}\:+\:\mathrm{2} \\ $$$$\mathrm{find}\:\:\:\underset{\:\mathrm{0}} {\overset{\:\mathrm{1}} {\int}}\:\mathrm{f}\left(\mathrm{x}\right)\:\mathrm{dx}\:=\:? \\ $$

Question Number 163888 Answers: 1 Comments: 1

prove∫((1−x^2 )/( (√(1−x^2 ))))dx = ∫(√(1−x^2 ))dx

$${prove}\int\frac{\mathrm{1}−{x}^{\mathrm{2}} }{\:\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }}{dx}\:=\:\int\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }{dx} \\ $$

Question Number 163886 Answers: 1 Comments: 2

Evaluate the following by using integration by parts formula: ∫xsin^(−1) (x)dx

$${Evaluate}\:{the}\:{following}\:{by}\:{using}\: \\ $$$$\:{integration}\:{by}\:{parts}\:{formula}: \\ $$$$\int{xsin}^{−\mathrm{1}} \left({x}\right){dx} \\ $$

Question Number 163885 Answers: 0 Comments: 0

preuve a)HH^(−1) =H b)HH=H c)H^(−1) =H

$${preuve} \\ $$$$\left.{a}\right){HH}^{−\mathrm{1}} ={H} \\ $$$$\left.{b}\right){HH}={H} \\ $$$$\left.{c}\right){H}^{−\mathrm{1}} ={H} \\ $$

Question Number 163881 Answers: 1 Comments: 0

16^(1−x) 32^(2x+1) =128^(2x−1) solve

$$\mathrm{16}^{\mathrm{1}−\mathrm{x}} \mathrm{32}^{\mathrm{2x}+\mathrm{1}} =\mathrm{128}^{\mathrm{2x}−\mathrm{1}} \:\:\:\:\mathrm{solve} \\ $$

Question Number 163865 Answers: 2 Comments: 0

Question Number 163861 Answers: 1 Comments: 0

Question Number 163860 Answers: 1 Comments: 0

Question Number 163856 Answers: 1 Comments: 0

Question Number 163858 Answers: 0 Comments: 2

which object or substance has the 2rd number velocity after light?

$${which}\:{object}\:{or}\:{substance}\:{has}\:\:{the}\: \\ $$$$\mathrm{2}{rd}\:{number}\:{velocity}\:{after}\:{light}? \\ $$

Question Number 163854 Answers: 1 Comments: 0

solution with residu theorem ∫_0 ^∞ (x^2 /(x^4 +2x^2 +2))dx=?

$$\boldsymbol{\mathrm{solution}}\:\boldsymbol{\mathrm{with}}\:\boldsymbol{\mathrm{residu}}\:\boldsymbol{\mathrm{theorem}} \\ $$$$\int_{\mathrm{0}} ^{\infty} \frac{\boldsymbol{\mathrm{x}}^{\mathrm{2}} }{\boldsymbol{\mathrm{x}}^{\mathrm{4}} +\mathrm{2}\boldsymbol{\mathrm{x}}^{\mathrm{2}} +\mathrm{2}}\boldsymbol{\mathrm{dx}}=?\:\:\:\: \\ $$

Question Number 163849 Answers: 1 Comments: 0

(1/(1 ∙ 2)) + (1/(2 ∙ 3)) + ... (1/(19 ∙ 20)) + (1/(20 ∙ 21)) = ?

$$\frac{\mathrm{1}}{\mathrm{1}\:\centerdot\:\mathrm{2}}\:+\:\frac{\mathrm{1}}{\mathrm{2}\:\centerdot\:\mathrm{3}}\:+\:...\:\frac{\mathrm{1}}{\mathrm{19}\:\centerdot\:\mathrm{20}}\:+\:\frac{\mathrm{1}}{\mathrm{20}\:\centerdot\:\mathrm{21}}\:=\:? \\ $$

Question Number 163843 Answers: 0 Comments: 0

Question Number 163844 Answers: 0 Comments: 0

Question Number 163842 Answers: 1 Comments: 0

calculate Ω = ∫_0 ^( 1) ((( Arctanh (x))/x^ ))^( 2) dx =? −− m.n −−

$$ \\ $$$$\:\:\:\:\:\:\:{calculate} \\ $$$$\:\:\:\: \\ $$$$\:\:\Omega\:=\:\int_{\mathrm{0}} ^{\:\mathrm{1}} \left(\frac{\:\:\mathscr{A}{rctanh}\:\left({x}\right)}{{x}^{\:} }\right)^{\:\mathrm{2}} \:{dx}\:=? \\ $$$$\:\:\:\:\:\:\:\:\:−−\:{m}.{n}\:−− \\ $$

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