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Question Number 164299    Answers: 1   Comments: 0

if f(f(f(...f(x)...)))_(n times) =2x+1, find f(1)=?

$${if}\:\underset{{n}\:{times}} {{f}\left({f}\left({f}\left(...{f}\left({x}\right)...\right)\right)\right)}=\mathrm{2}{x}+\mathrm{1},\: \\ $$$${find}\:{f}\left(\mathrm{1}\right)=? \\ $$

Question Number 164300    Answers: 1   Comments: 0

Question a.which numbers have an odd number of divisors b. Is there a number with exactly 13 divisors c. Generalize

$$\mathrm{Question} \\ $$$$\mathrm{a}.\mathrm{which}\:\mathrm{numbers}\:\mathrm{have}\:\mathrm{an}\:\mathrm{odd}\:\mathrm{number} \\ $$$$\:\:\:\:\:\mathrm{of}\:\mathrm{divisors} \\ $$$$\mathrm{b}.\:\:\mathrm{Is}\:\mathrm{there}\:\mathrm{a}\:\mathrm{number}\:\mathrm{with}\:\mathrm{exactly}\:\mathrm{13} \\ $$$$\:\:\:\:\:\:\mathrm{divisors} \\ $$$$\mathrm{c}.\:\:\mathrm{Generalize} \\ $$

Question Number 164290    Answers: 2   Comments: 0

Question Number 164279    Answers: 3   Comments: 0

x^n =n^x x=?

$${x}^{{n}} ={n}^{{x}} \:\:\:{x}=? \\ $$

Question Number 164272    Answers: 1   Comments: 0

Question Number 164269    Answers: 1   Comments: 0

Solve the inequality; (x+3)[(x−1)^2 −x(x+(3/4))]+6+((7x^2 +29x)/4)>0 {Z.A}

$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\boldsymbol{{Solve}}\:\boldsymbol{{the}}\:\boldsymbol{{inequality}}; \\ $$$$\:\:\left(\boldsymbol{{x}}+\mathrm{3}\right)\left[\left(\boldsymbol{{x}}−\mathrm{1}\right)^{\mathrm{2}} −\boldsymbol{{x}}\left(\boldsymbol{{x}}+\frac{\mathrm{3}}{\mathrm{4}}\right)\right]+\mathrm{6}+\frac{\mathrm{7}\boldsymbol{{x}}^{\mathrm{2}} +\mathrm{29}\boldsymbol{{x}}}{\mathrm{4}}>\mathrm{0} \\ $$$$\left\{\boldsymbol{{Z}}.\boldsymbol{{A}}\right\} \\ $$

Question Number 164264    Answers: 0   Comments: 0

Question Number 164266    Answers: 2   Comments: 0

lim_(x→∞) (x−2) − (√(x^2 +2x−5)) = ?

$$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\:\left({x}−\mathrm{2}\right)\:−\:\sqrt{{x}^{\mathrm{2}} +\mathrm{2}{x}−\mathrm{5}}\:\:=\:\:? \\ $$

Question Number 164256    Answers: 1   Comments: 0

Question Number 164242    Answers: 0   Comments: 0

Question Number 164240    Answers: 2   Comments: 0

Find: Σ_(n=1) ^∞ ln (n) = ?

$$\mathrm{Find}:\:\:\:\underset{\boldsymbol{\mathrm{n}}=\mathrm{1}} {\overset{\infty} {\sum}}\:\mathrm{ln}\:\left(\mathrm{n}\right)\:=\:? \\ $$

Question Number 164237    Answers: 1   Comments: 0

Question Number 164236    Answers: 2   Comments: 1

Question Number 164231    Answers: 0   Comments: 0

∫_(−∞) ^∞ −(1/3) ∫_0 ^1 ((((^4 log 3.^4 log 6)/( ^4 log 9.^8 log 2+^4 log 9.^8 log 3))/((^9 log 4.^2 log27+^3 log 81)/(^2 log 64−^2 log 8))))dxdy {z.}

$$\int_{−\infty} ^{\infty} \:−\frac{\mathrm{1}}{\mathrm{3}}\:\:\int_{\mathrm{0}} ^{\mathrm{1}} \:\left(\frac{\frac{\:^{\mathrm{4}} \boldsymbol{\mathrm{log}}\:\mathrm{3}.^{\mathrm{4}} \boldsymbol{\mathrm{log}}\:\mathrm{6}}{\:\:^{\mathrm{4}} \boldsymbol{\mathrm{log}}\:\mathrm{9}.^{\mathrm{8}} \boldsymbol{\mathrm{log}}\:\mathrm{2}+\:^{\mathrm{4}} \boldsymbol{\mathrm{log}}\:\mathrm{9}.^{\mathrm{8}} \boldsymbol{\mathrm{log}}\:\mathrm{3}}}{\frac{\:^{\mathrm{9}} \boldsymbol{\mathrm{log}}\:\mathrm{4}.^{\mathrm{2}} \boldsymbol{\mathrm{log}}\mathrm{27}+^{\mathrm{3}} \boldsymbol{\mathrm{log}}\:\mathrm{81}}{\:^{\mathrm{2}} \boldsymbol{\mathrm{log}}\:\mathrm{64}−^{\mathrm{2}} \boldsymbol{\mathrm{log}}\:\mathrm{8}}}\right)\boldsymbol{\mathrm{dxdy}} \\ $$$$\left\{\boldsymbol{\mathrm{z}}.\right\} \\ $$

Question Number 164227    Answers: 2   Comments: 0

Question Number 164222    Answers: 0   Comments: 0

Question Number 164211    Answers: 1   Comments: 0

Question Number 164210    Answers: 1   Comments: 0

Question Number 164208    Answers: 0   Comments: 0

Question Number 164206    Answers: 2   Comments: 5

Question Number 164457    Answers: 1   Comments: 0

((20)/(10))=2(0/(10))=>((20)/(10))=0 why?

$$\frac{\mathrm{20}}{\mathrm{10}}=\mathrm{2}\frac{\mathrm{0}}{\mathrm{10}}=>\frac{\mathrm{20}}{\mathrm{10}}=\mathrm{0}\:\:\:\:\:{why}? \\ $$

Question Number 164196    Answers: 1   Comments: 0

Evalute the sum: Σ_(k=1) ^n k ((π/n))^2 arctan (((kπ)/n))^2

$$\mathrm{Evalute}\:\mathrm{the}\:\mathrm{sum}: \\ $$$$\underset{\boldsymbol{\mathrm{k}}=\mathrm{1}} {\overset{\boldsymbol{\mathrm{n}}} {\sum}}\:\mathrm{k}\:\left(\frac{\pi}{\mathrm{n}}\right)^{\mathrm{2}} \mathrm{arctan}\:\left(\frac{\mathrm{k}\pi}{\mathrm{n}}\right)^{\mathrm{2}} \\ $$

Question Number 164193    Answers: 2   Comments: 2

Question Number 164191    Answers: 1   Comments: 0

Question Number 164189    Answers: 0   Comments: 1

Question Number 164188    Answers: 0   Comments: 0

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