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Question Number 209166    Answers: 1   Comments: 0

Question Number 209162    Answers: 2   Comments: 0

Cyclic quadrilateral ABCD is inscribed in circle. Point S is intersection of diagonals AC and BD (S is not center of the circle). If AB=BC=6 and BS=4, what is length of BD?

$$ \\ $$Cyclic quadrilateral ABCD is inscribed in circle. Point S is intersection of diagonals AC and BD (S is not center of the circle). If AB=BC=6 and BS=4, what is length of BD?

Question Number 209161    Answers: 3   Comments: 2

Question Number 209137    Answers: 2   Comments: 0

Question Number 209131    Answers: 1   Comments: 0

prove : curve { ((x(t)=((a+r.cos(t))/(a^2 +r^2 +2ar.cos(t))))),((y(t)=((r.sin(t))/(a^2 +r^2 +2ar.cos(t))))) :} 0≤t≤2π is circle , find center & radius

$${prove}\:: \\ $$$${curve}\:\begin{cases}{{x}\left({t}\right)=\frac{{a}+{r}.{cos}\left({t}\right)}{{a}^{\mathrm{2}} +{r}^{\mathrm{2}} +\mathrm{2}{ar}.{cos}\left({t}\right)}}\\{{y}\left({t}\right)=\frac{{r}.{sin}\left({t}\right)}{{a}^{\mathrm{2}} +{r}^{\mathrm{2}} +\mathrm{2}{ar}.{cos}\left({t}\right)}}\end{cases}\:\:\:\:\mathrm{0}\leqslant{t}\leqslant\mathrm{2}\pi \\ $$$${is}\:{circle}\:,\:{find}\:{center}\:\&\:{radius} \\ $$

Question Number 209129    Answers: 1   Comments: 0

Question Number 209128    Answers: 2   Comments: 0

Question Number 209127    Answers: 1   Comments: 0

Question Number 209126    Answers: 2   Comments: 0

Question Number 209125    Answers: 3   Comments: 0

Question Number 209124    Answers: 3   Comments: 0

Question Number 209123    Answers: 2   Comments: 0

Question Number 209122    Answers: 1   Comments: 0

Question Number 209121    Answers: 1   Comments: 0

Question Number 209118    Answers: 0   Comments: 0

Question Number 209117    Answers: 0   Comments: 0

Question Number 209116    Answers: 1   Comments: 0

Question Number 209115    Answers: 0   Comments: 0

Question Number 209099    Answers: 3   Comments: 0

Question Number 209098    Answers: 2   Comments: 0

Question Number 209072    Answers: 0   Comments: 8

Question Number 209066    Answers: 1   Comments: 1

Question Number 209065    Answers: 1   Comments: 0

The cost of maintaining a school is partly constant and partly varies as the number of students. With 50 students the cost is $15705 and with 40 students the cost is $13305. If the fee per student is $360.00, what is the least number of students for which the school can be run without loss?

$${The}\:{cost}\:{of}\:{maintaining}\:{a}\:{school}\:{is} \\ $$$${partly}\:{constant}\:{and}\:{partly}\:{varies}\:{as} \\ $$$${the}\:{number}\:{of}\:{students}.\:{With}\:\mathrm{50}\:{students} \\ $$$${the}\:{cost}\:{is}\:\$\mathrm{15705}\:{and}\:{with}\:\mathrm{40}\:{students} \\ $$$${the}\:{cost}\:{is}\:\$\mathrm{13305}.\:{If}\:{the}\:{fee}\:{per}\:{student} \\ $$$${is}\:\$\mathrm{360}.\mathrm{00},\:{what}\:{is}\:{the}\:{least}\:{number}\:{of} \\ $$$${students}\:{for}\:{which}\:{the}\:{school}\:{can}\:{be} \\ $$$${run}\:{without}\:{loss}? \\ $$

Question Number 209424    Answers: 1   Comments: 2

Question Number 209062    Answers: 1   Comments: 0

Question Number 209059    Answers: 0   Comments: 3

Compare: 8! and 8!!

$$\mathrm{Compare}: \\ $$$$\mathrm{8}!\:\:\:\mathrm{and}\:\:\:\mathrm{8}!! \\ $$

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