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Question Number 169922 Answers: 1 Comments: 0

Let f(x)=((2x−7)/(x+1)) . Compute f^(1989) (x). note f^2 (x)= f(f(x))

$$\:\:{Let}\:{f}\left({x}\right)=\frac{\mathrm{2}{x}−\mathrm{7}}{{x}+\mathrm{1}}\:.\:{Compute}\:{f}^{\mathrm{1989}} \left({x}\right). \\ $$$$\:{note}\:{f}^{\mathrm{2}} \left({x}\right)=\:{f}\left({f}\left({x}\right)\right) \\ $$

Question Number 169920 Answers: 0 Comments: 0

Question Number 169918 Answers: 3 Comments: 0

A={z∈C: 2<∣z∣<4} fine log(A) where log is complex logaritmique

$${A}=\left\{\boldsymbol{{z}}\in\mathbb{C}:\:\mathrm{2}<\mid\boldsymbol{{z}}\mid<\mathrm{4}\right\} \\ $$$$\boldsymbol{{fine}}\:\boldsymbol{{log}}\left(\boldsymbol{{A}}\right) \\ $$$$\boldsymbol{{where}}\:\boldsymbol{{log}}\:\boldsymbol{{is}}\:\boldsymbol{{complex}}\:\boldsymbol{{logaritmique}} \\ $$

Question Number 169916 Answers: 1 Comments: 0

Question Number 169915 Answers: 2 Comments: 0

Question Number 169913 Answers: 0 Comments: 1

solve the D.E dx+(−sin(y)+(x/y))dy=0

$${solve}\:{the}\:{D}.{E} \\ $$$${dx}+\left(−{sin}\left({y}\right)+\frac{{x}}{{y}}\right){dy}=\mathrm{0} \\ $$

Question Number 169906 Answers: 0 Comments: 0

Evaluate ∫∫e^(2x+3y) dxdy over the triangle bounded by the lines x = 0, y = 0, x+y = 1.

$$\mathrm{Evaluate}\:\int\int{e}^{\mathrm{2}{x}+\mathrm{3}{y}} {dxdy}\:\mathrm{over}\:\mathrm{the}\:\mathrm{triangle} \\ $$$$\mathrm{bounded}\:\mathrm{by}\:\mathrm{the}\:\mathrm{lines}\:{x}\:=\:\mathrm{0},\:{y}\:=\:\mathrm{0},\:{x}+{y}\:=\:\mathrm{1}. \\ $$

Question Number 170010 Answers: 1 Comments: 1

Question Number 170012 Answers: 1 Comments: 0

Question Number 169901 Answers: 0 Comments: 0

Question Number 169900 Answers: 0 Comments: 0

montrer que ∀z∈C/ ∣z∣=2, ∣(1/(z^4 −5z+1))∣≤(1/5)

$$\boldsymbol{{montrer}}\:\boldsymbol{{que}}\:\forall\boldsymbol{{z}}\in\mathbb{C}/\:\mid\boldsymbol{{z}}\mid=\mathrm{2}, \\ $$$$\mid\frac{\mathrm{1}}{\boldsymbol{{z}}^{\mathrm{4}} −\mathrm{5}\boldsymbol{{z}}+\mathrm{1}}\mid\leqslant\frac{\mathrm{1}}{\mathrm{5}} \\ $$

Question Number 169899 Answers: 1 Comments: 2

Question Number 169897 Answers: 0 Comments: 1

Question Number 169896 Answers: 1 Comments: 0

Question Number 169892 Answers: 1 Comments: 0

(dy/dx) = 2xe^(−y) , y(1) = 0

$$\frac{{dy}}{{dx}}\:=\:\mathrm{2}{xe}^{−{y}} \:,\:\:{y}\left(\mathrm{1}\right)\:=\:\mathrm{0} \\ $$

Question Number 169885 Answers: 1 Comments: 0

∣a^→ ∣=13 ∣b^→ ∣=19 ∣a^→ +b^→ ∣=24 ∣a^→ −b^→ ∣=?

$$\mid\overset{\rightarrow} {{a}}\mid=\mathrm{13} \\ $$$$\mid\overset{\rightarrow} {{b}}\mid=\mathrm{19} \\ $$$$\mid\overset{\rightarrow} {{a}}+\overset{\rightarrow} {{b}}\mid=\mathrm{24} \\ $$$$\mid\overset{\rightarrow} {{a}}−\overset{\rightarrow} {{b}}\mid=? \\ $$

Question Number 169878 Answers: 2 Comments: 0

Question Number 169874 Answers: 1 Comments: 0

Σ_(d∣6) d=?

$$\underset{{d}\mid\mathrm{6}} {\sum}{d}=? \\ $$

Question Number 169873 Answers: 2 Comments: 0

∫_0 ^1 ((ln(1+x))/x)dx=?

$$\underset{\mathrm{0}} {\overset{\mathrm{1}} {\int}}\frac{{ln}\left(\mathrm{1}+{x}\right)}{{x}}{dx}=? \\ $$

Question Number 169870 Answers: 0 Comments: 0

In an artistic design by a contractor of the students’ centre in a university, four pillars were erected to form two triangular figures with the vertices at the first floor of the building and two of the pillars crossing each other. Proof that the spaces occupied by these two triangular figures are equal.

$$ \\ $$In an artistic design by a contractor of the students’ centre in a university, four pillars were erected to form two triangular figures with the vertices at the first floor of the building and two of the pillars crossing each other. Proof that the spaces occupied by these two triangular figures are equal.

Question Number 169865 Answers: 3 Comments: 2

x+y=−2 xy=4 find x^8 +8y^5 =?

$${x}+{y}=−\mathrm{2} \\ $$$${xy}=\mathrm{4} \\ $$$${find}\:{x}^{\mathrm{8}} +\mathrm{8}{y}^{\mathrm{5}} =? \\ $$

Question Number 169864 Answers: 1 Comments: 0

Question Number 169863 Answers: 1 Comments: 0

∫_o ^1 xln∣x^2 −2x∣dx

$$\int_{{o}} ^{\mathrm{1}} {xln}\mid{x}^{\mathrm{2}} −\mathrm{2}{x}\mid{dx} \\ $$

Question Number 169860 Answers: 1 Comments: 0

y = x^2 + 1 y = 0 x = - 1 x = 2 find the volume of the object obtained by rotating the figure bounded by lines around the abscissa axis

$$\mathrm{y}\:=\:\mathrm{x}^{\mathrm{2}} \:+\:\mathrm{1} \\ $$$$\mathrm{y}\:=\:\mathrm{0} \\ $$$$\mathrm{x}\:=\:-\:\mathrm{1} \\ $$$$\mathrm{x}\:=\:\mathrm{2} \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{volume}\:\mathrm{of}\:\mathrm{the}\:\mathrm{object}\:\mathrm{obtained} \\ $$$$\mathrm{by}\:\mathrm{rotating}\:\mathrm{the}\:\mathrm{figure}\:\mathrm{bounded}\:\mathrm{by}\:\mathrm{lines} \\ $$$$\mathrm{around}\:\mathrm{the}\:\mathrm{abscissa}\:\mathrm{axis} \\ $$

Question Number 169859 Answers: 0 Comments: 0

Question Number 169855 Answers: 1 Comments: 0

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