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Question Number 165698 Answers: 1 Comments: 0
Question Number 165687 Answers: 2 Comments: 0
$$ \\ $$$$\:\:\mathrm{I}{f}\:\:\:\:{f}\left({x}\right)=\:\frac{{x}^{\:\mathrm{2}} −\:\mathrm{2}{x}\:−\mathrm{8}}{{x}^{\:\mathrm{2}} −\mathrm{7}{x}\:+\mathrm{12}} \\ $$$$\:\:\:{then}\:,{find}\::\:\:\:\:\:\:\:\:\:\:\:{f}^{\:−\mathrm{1}} \left({x}\right)=? \\ $$$$ \\ $$
Question Number 165685 Answers: 2 Comments: 0
$$\:_{\mathrm{0}} \int^{\mathrm{2}} \mid\:{x}^{\mathrm{2}} −\mathrm{2}{x}+\mathrm{1}\:\mid\:{dx}\:=?\: \\ $$
Question Number 165713 Answers: 1 Comments: 0
Question Number 165731 Answers: 1 Comments: 2
$$\int\:\sqrt{{sinx}}\:{dx} \\ $$
Question Number 165673 Answers: 1 Comments: 0
Question Number 165672 Answers: 0 Comments: 0
Question Number 165670 Answers: 0 Comments: 0
Question Number 165669 Answers: 1 Comments: 1
Question Number 165751 Answers: 1 Comments: 0
$$\:\mathrm{x}^{\mathrm{3}} +\mathrm{6x}−\mathrm{9}=\mathrm{0}\:\Rightarrow\mathrm{x}=? \\ $$
Question Number 165653 Answers: 1 Comments: 2
Question Number 165651 Answers: 1 Comments: 5
$${If}\:{the}\:{equation}\:\left(\mathrm{2}{x}−\mathrm{1}\right)−{p}\left({x}^{\mathrm{2}} +\mathrm{2}\right)=\mathrm{0}, \\ $$$${where}\:{p}\:{is}\:{constant},\:{has}\:{imaginary} \\ $$$${roots},\:{deduce}\:{that}\:\mathrm{2}{p}^{\mathrm{2}} +{p}−\mathrm{1}\geqslant\mathrm{0}. \\ $$
Question Number 165650 Answers: 0 Comments: 0
Question Number 165649 Answers: 0 Comments: 0
Question Number 165648 Answers: 0 Comments: 0
Question Number 165639 Answers: 1 Comments: 1
Question Number 165692 Answers: 1 Comments: 0
$${why}\:{we}\:{use}\:{the}\:{current}\:{as}\:{conventional}\:{in} \\ $$$${a}\:{circuit}? \\ $$
Question Number 165691 Answers: 1 Comments: 0
$${why}\:{can}'{t}\:{birds}\:{catch}\:{by}\:{the}\:{AC}\:{current}? \\ $$
Question Number 165637 Answers: 1 Comments: 0
$$\mathrm{37}{tanx}\:=\mathrm{11}{tan}\mathrm{3}{x} \\ $$$${solve}\:{it} \\ $$
Question Number 165620 Answers: 1 Comments: 0
$${solve} \\ $$$${z}^{\mathrm{7}} =−\mathrm{4} \\ $$
Question Number 165617 Answers: 1 Comments: 0
$${what}\:{is}\:{the}\:{focal}\:{length}\:{formula}\:{for}\: \\ $$$${combined}\:{lenses}?\:{if}\:{lenses}\:{more}\:{than}\: \\ $$$${tow}? \\ $$
Question Number 165616 Answers: 2 Comments: 1
Question Number 165615 Answers: 1 Comments: 0
$$\:\int_{\:\mathrm{0}} ^{\:\mathrm{1}} \:\frac{{dx}}{\:\sqrt{{x}}\:\left(\sqrt[{\mathrm{3}}]{{x}}+\sqrt[{\mathrm{4}}]{{x}}\right)}=? \\ $$
Question Number 165641 Answers: 2 Comments: 0
$$\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{Given}\:\mathrm{that}\:\:{y}\:=\:\frac{\mathrm{1}}{{x}}\: \\ $$$$\left({a}\right)\:\mathrm{Show}\:\mathrm{that}\:\:{y}^{\left({n}\right)} \:=\:\frac{\left(−\mathrm{1}\right)^{{n}} \:{n}!}{{x}^{{n}+\mathrm{1}} } \\ $$$$\left({b}\right)\:\mathrm{Find}\:\mathrm{an}\:\mathrm{expression}\:\mathrm{for}\:{y}^{\left({n}−\mathrm{1}\right)} +\:{y}^{\left({n}\right)} \\ $$$$ \\ $$
Question Number 165608 Answers: 0 Comments: 0
$$\mathrm{Reupload}\:\:\mathrm{unanswered}\:\:\mathrm{question}. \\ $$$$\mathrm{sec}^{\mathrm{2}} \mathrm{1}°\:+\:\mathrm{sec}^{\mathrm{2}} \:\mathrm{2}°\:+\:\mathrm{sec}^{\mathrm{2}} \:\mathrm{3}°\:+\:\ldots+\:\mathrm{sec}^{\mathrm{2}} \:\mathrm{89}°\:\:=\:\:? \\ $$
Question Number 165600 Answers: 0 Comments: 19
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