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Question Number 181449 Answers: 0 Comments: 1

integrate ∫x^x dx

$$\:\:\:\:\:\:\:\mathrm{integrate} \\ $$$$\:\:\:\:\:\:\:\:\int\boldsymbol{\mathrm{x}}^{\boldsymbol{\mathrm{x}}} \boldsymbol{\mathrm{dx}} \\ $$

Question Number 174258 Answers: 1 Comments: 0

lim_(x→∞) (√(√(x^4 −x^3 ))) − x =?

$$\:\:\:\:\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\sqrt{\sqrt{{x}^{\mathrm{4}} −{x}^{\mathrm{3}} }}\:−\:{x}\:=? \\ $$

Question Number 174253 Answers: 1 Comments: 0

Question Number 174250 Answers: 0 Comments: 1

Question Number 174227 Answers: 0 Comments: 4

Q : Max_ _(x>1) ((( x^( 4) −x^( 2) )/(x^( 6) + 2x^( 3) − 1)) ) = ?

$$ \\ $$$$\:\:\:{Q}\:: \\ $$$$\:\:\:\:\:\:\:{Max}_{\underset{{x}>\mathrm{1}} {\:}} \:\left(\frac{\:{x}^{\:\mathrm{4}} −{x}^{\:\mathrm{2}} }{{x}^{\:\mathrm{6}} +\:\mathrm{2}{x}^{\:\mathrm{3}} −\:\mathrm{1}}\:\right)\:=\:? \\ $$$$ \\ $$

Question Number 174211 Answers: 1 Comments: 0

for positive real number x and y , xy = 16 then find the minimum value of [x]+[y] , [ ] greatest integer function

$${for}\:{positive}\:{real}\:{number}\:{x}\: \\ $$$${and}\:{y}\:,\:{xy}\:=\:\mathrm{16}\:{then}\:{find}\:{the} \\ $$$$\:{minimum}\:{value}\:{of}\:\:\left[{x}\right]+\left[{y}\right]\:, \\ $$$$\left[\:\right]\:{greatest}\:{integer}\:{function} \\ $$

Question Number 174220 Answers: 1 Comments: 7

Question Number 174218 Answers: 0 Comments: 0

Question Number 174215 Answers: 0 Comments: 0

Question Number 174203 Answers: 1 Comments: 1

solve: x!=9, find x

$${solve}: \\ $$$${x}!=\mathrm{9}, \\ $$$${find}\:{x} \\ $$$$ \\ $$

Question Number 174336 Answers: 1 Comments: 0

∫_1 ^3 ((∣x−2∣)/(x^2 −4x)) dx =?

$$\:\underset{\mathrm{1}} {\overset{\mathrm{3}} {\int}}\:\frac{\mid{x}−\mathrm{2}\mid}{{x}^{\mathrm{2}} −\mathrm{4}{x}}\:{dx}\:=? \\ $$

Question Number 174199 Answers: 1 Comments: 0

Question Number 174197 Answers: 0 Comments: 0

Question Number 174193 Answers: 0 Comments: 2

what is the range of the inverse the relation {(x,y):y=(√(4−∣x−1∣))}???

$${what}\:{is}\:{the}\:{range}\:{of}\:{the}\:{inverse}\: \\ $$$${the}\:{relation}\:\left\{\left({x},{y}\right):{y}=\sqrt{\mathrm{4}−\mid{x}−\mathrm{1}\mid}\right\}??? \\ $$

Question Number 174192 Answers: 0 Comments: 5

∫_0 ^(π/2) cosxe^((cosxdx)) dx ?????

$$\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} {cosxe}^{\left({cosxdx}\right)} {dx}\:\:\:????? \\ $$

Question Number 174191 Answers: 0 Comments: 3

intgrate ∫(x+2)cos(x^2 +4x)dx?

$$\:\:\:\:\:{intgrate}\:\int\left({x}+\mathrm{2}\right){cos}\left({x}^{\mathrm{2}} +\mathrm{4}{x}\right){dx}? \\ $$

Question Number 174190 Answers: 1 Comments: 0

Question Number 174214 Answers: 1 Comments: 0

Question Number 181466 Answers: 1 Comments: 0

3∙5^(2x+1) − 7∙2^(4x+1) = 19 x= ?

$$\:\mathrm{3}\centerdot\mathrm{5}^{\mathrm{2}\boldsymbol{\mathrm{x}}+\mathrm{1}} \:−\:\mathrm{7}\centerdot\mathrm{2}^{\mathrm{4}\boldsymbol{\mathrm{x}}+\mathrm{1}} \:=\:\mathrm{19} \\ $$$$ \\ $$$$\:\:\: \\ $$$$\:\:\:\:\:\:\:\boldsymbol{\mathrm{x}}=\:? \\ $$$$ \\ $$$$ \\ $$

Question Number 181464 Answers: 0 Comments: 0

lim_(x→0) ((sin (tan x)−sin (x))/(x−tan (x))) =?

$$\:\:\:\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{sin}\:\left(\mathrm{tan}\:\mathrm{x}\right)−\mathrm{sin}\:\left(\mathrm{x}\right)}{\mathrm{x}−\mathrm{tan}\:\left(\mathrm{x}\right)}\:=? \\ $$

Question Number 174185 Answers: 1 Comments: 0

The circle x^2 +y^2 −2x−4y−20=0 is inscribed in a square. One vertex of the square is (−4, 7). Find the coordinates of the other vertices.

$$\mathrm{The}\:\mathrm{circle}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} −\mathrm{2}{x}−\mathrm{4}{y}−\mathrm{20}=\mathrm{0}\:\mathrm{is} \\ $$$$\mathrm{inscribed}\:\mathrm{in}\:\mathrm{a}\:\mathrm{square}.\:\mathrm{One}\:\mathrm{vertex} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{square}\:\mathrm{is}\:\left(−\mathrm{4},\:\mathrm{7}\right).\:\mathrm{Find}\:\mathrm{the} \\ $$$$\mathrm{coordinates}\:\mathrm{of}\:\mathrm{the}\:\mathrm{other}\:\mathrm{vertices}. \\ $$

Question Number 174182 Answers: 0 Comments: 0

Question Number 174177 Answers: 4 Comments: 0

x^3 +(1/x^3 )=1 then prove that (((x^5 +(1/x^5 ))^3 −1)/(x^5 +(1/x^5 )))=3

$${x}^{\mathrm{3}} +\frac{\mathrm{1}}{{x}^{\mathrm{3}} }=\mathrm{1}\:\:\:\:\:{then}\:{prove}\:{that} \\ $$$$\frac{\left({x}^{\mathrm{5}} +\frac{\mathrm{1}}{{x}^{\mathrm{5}} }\right)^{\mathrm{3}} −\mathrm{1}}{{x}^{\mathrm{5}} +\frac{\mathrm{1}}{{x}^{\mathrm{5}} }}=\mathrm{3} \\ $$

Question Number 174194 Answers: 4 Comments: 0

Question Number 181462 Answers: 2 Comments: 1

Question Number 181461 Answers: 0 Comments: 0

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