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Question Number 176821 Answers: 0 Comments: 2
Question Number 176820 Answers: 0 Comments: 20
Question Number 173687 Answers: 2 Comments: 0
$$ \\ $$$$\:\:\:{Q}\::\:\:\:\:\:\frac{{ln}\left({a}\:\right)}{{c}−{b}}\:=\frac{{ln}\left({b}\right)}{{a}−{c}}\:=\:\frac{{ln}\left({c}\right)}{{b}−{a}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\Rightarrow\:\:\:{a}^{\:{a}} .\:{b}^{\:{b}} .\:{c}^{\:{c}} \:=? \\ $$$$ \\ $$
Question Number 176083 Answers: 2 Comments: 0
$${can}\:{you}\:{find}\:{f}\left({x}\right)? \\ $$$${f}\left({x}\right)−{f}\left(\mathrm{1}−{x}\right)=\:{x} \\ $$
Question Number 173678 Answers: 3 Comments: 0
$${if}\:{f}\left({x}\right)\:{is}\:\mathrm{2}^{{nd}} \:{digre}\:{function}\:\:\: \\ $$$${f}\left({x}−\mathrm{1}\right)+{f}\left({x}\right)+{f}\left({x}+\mathrm{1}\right)={x}^{\mathrm{2}} +\mathrm{1} \\ $$$${then}\:{faind}\:\:{f}\left(\mathrm{2}\right)=? \\ $$
Question Number 173677 Answers: 0 Comments: 2
$$\mathrm{Find}\:\:\mathrm{tangent}\:\:\mathrm{equation}\:\:\mathrm{of}\:\: \\ $$$$\mathrm{two}\:\:\mathrm{circles}\:: \\ $$$${L}_{\mathrm{1}} \::\:\left({x}−\mathrm{5}\right)^{\mathrm{2}} \:+\:\left({y}+\mathrm{1}\right)^{\mathrm{2}} \:=\:\mathrm{9} \\ $$$${L}_{\mathrm{2}} \::\:\left({x}+\mathrm{4}\right)^{\mathrm{2}} \:+\:\left({y}−\mathrm{11}\right)^{\mathrm{2}} \:=\:\mathrm{144} \\ $$
Question Number 173668 Answers: 3 Comments: 1
Question Number 181426 Answers: 1 Comments: 1
Question Number 181424 Answers: 1 Comments: 1
Question Number 173661 Answers: 0 Comments: 0
Question Number 173652 Answers: 1 Comments: 3
Question Number 173645 Answers: 0 Comments: 3
Question Number 173644 Answers: 1 Comments: 0
Question Number 173643 Answers: 0 Comments: 0
Question Number 181581 Answers: 1 Comments: 0
Question Number 181579 Answers: 1 Comments: 1
$$\left(\sqrt[{\mathrm{3}}]{{x}}\right)^{−\mathrm{2}+{log}_{{x}} \mathrm{11}} =\mathrm{11} \\ $$$${x}=? \\ $$
Question Number 176816 Answers: 3 Comments: 4
Question Number 173630 Answers: 0 Comments: 2
$$\left({x}+\mathrm{4}\right)^{\mathrm{2}} ={x}^{\left({x}+\mathrm{2}\right)} \\ $$$${Please}\:\:{Help}... \\ $$
Question Number 173629 Answers: 2 Comments: 2
Question Number 173624 Answers: 0 Comments: 6
$${find}\:{f}\left({x}\right)\:{such}\:{that}\:{f}'\left({x}\right)={f}^{−\mathrm{1}} \left({x}\right). \\ $$
Question Number 173620 Answers: 2 Comments: 0
Question Number 173610 Answers: 2 Comments: 0
Question Number 173609 Answers: 2 Comments: 2
Question Number 173606 Answers: 0 Comments: 0
Question Number 173613 Answers: 1 Comments: 0
$${if}\:{f}\left({x}\right)={x}^{\mathrm{2}} +\mathrm{4}{x}+\mathrm{2}, \\ $$$${solve}\:\underset{{n}\:{times}} {{f}\left({f}\left({f}\left({f}\left(...{f}\left({x}\right)\right)\right)\right)\right)}=\mathrm{0} \\ $$
Question Number 173599 Answers: 0 Comments: 1
$$\mathrm{Find}\:\mathrm{the}\:\mathrm{area}\:\mathrm{bounded}\:\mathrm{by}\:\mathrm{the}\:\mathrm{graph} \\ $$$$\mathrm{y}=\mathrm{x}^{\mathrm{2}} \:\mathrm{and}\:\mathrm{y}=\mathrm{2}−\mathrm{x}^{\mathrm{2}} \:\mathrm{for}\:\mathrm{0}\leqslant\mathrm{x}\leqslant\mathrm{2}. \\ $$
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