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Question Number 180734 Answers: 1 Comments: 0

If f(x)={_(0, othrrwise) ^(2x , 0≤x≤a) is a probability density funtion of a random variable, then a=? pls solve

$${If}\:{f}\left({x}\right)=\left\{_{\mathrm{0},\:{othrrwise}} ^{\mathrm{2}{x}\:,\:\mathrm{0}\leqslant{x}\leqslant{a}} \:{is}\:{a}\:{probability}\right. \\ $$$${density}\:{funtion}\:{of}\:{a}\:{random}\: \\ $$$${variable},\:{then}\:{a}=? \\ $$$${pls}\:{solve} \\ $$

Question Number 180733 Answers: 0 Comments: 0

let X have a Bernoulli distribution with mean 0.4 , then the variance of 2X−3 is pls solve

$${let}\:{X}\:{have}\:{a}\:{Bernoulli}\:{distribution}\: \\ $$$${with}\:{mean}\:\mathrm{0}.\mathrm{4}\:,\:{then}\:{the}\:{variance} \\ $$$${of}\:\mathrm{2}{X}−\mathrm{3}\:{is} \\ $$$${pls}\:{solve} \\ $$

Question Number 180730 Answers: 1 Comments: 0

is it ((125x^3 ))^(1/3) a polynomial?

$${is}\:{it}\:\sqrt[{\mathrm{3}}]{\mathrm{125}{x}^{\mathrm{3}} }\:\:{a}\:{polynomial}? \\ $$

Question Number 180729 Answers: 2 Comments: 0

if f(x)=((kx+3)/(2x−5)) is a constant function then what will be the value of k?

$${if}\:{f}\left({x}\right)=\frac{{kx}+\mathrm{3}}{\mathrm{2}{x}−\mathrm{5}}\:\:\:{is}\:{a}\:{constant}\:{function} \\ $$$${then}\:{what}\:{will}\:{be}\:{the}\:{value}\:{of}\:{k}? \\ $$

Question Number 180728 Answers: 1 Comments: 0

Given x, y, z∈R^+ such that x^2 −3xy+4y^2 −z=0. when ((xy)/z) reaches its max value, find the max value of (2/x)+(1/y)−(2/z).

$$\mathrm{Given}\:{x},\:{y},\:{z}\in\mathbb{R}^{+} \:\mathrm{such}\:\mathrm{that}\:{x}^{\mathrm{2}} −\mathrm{3}{xy}+\mathrm{4}{y}^{\mathrm{2}} −{z}=\mathrm{0}. \\ $$$$\mathrm{when}\:\frac{{xy}}{{z}}\:\mathrm{reaches}\:\mathrm{its}\:\mathrm{max}\:\mathrm{value},\:\mathrm{find}\:\mathrm{the}\:\mathrm{max}\:\mathrm{value}\:\mathrm{of} \\ $$$$\frac{\mathrm{2}}{{x}}+\frac{\mathrm{1}}{{y}}−\frac{\mathrm{2}}{{z}}. \\ $$

Question Number 180718 Answers: 1 Comments: 0

Resoudre le systeme (dx/dt)=4x+6y (dy/dt)=−3x−5y (dz/dt)=−3x−6y−5z

$${Resoudre}\:{le}\:{systeme} \\ $$$$\frac{{dx}}{{dt}}=\mathrm{4}{x}+\mathrm{6}{y} \\ $$$$\frac{{dy}}{{dt}}=−\mathrm{3}{x}−\mathrm{5}{y} \\ $$$$\frac{{dz}}{{dt}}=−\mathrm{3}{x}−\mathrm{6}{y}−\mathrm{5}{z} \\ $$

Question Number 180713 Answers: 1 Comments: 7

Question Number 180746 Answers: 2 Comments: 0

Question Number 180744 Answers: 2 Comments: 2

Question Number 180698 Answers: 1 Comments: 0

2+(x/(2+(x/(2+(x/:)))))=3 x=?

$$\mathrm{2}+\frac{{x}}{\mathrm{2}+\frac{{x}}{\mathrm{2}+\frac{{x}}{:}}}=\mathrm{3}\:\:\:\:\:\:\:\:\:\:\:{x}=? \\ $$

Question Number 180689 Answers: 1 Comments: 0

value of ∫_o ^(+oo) e^(E(x)) dx

$${value}\:{of}\: \\ $$$$\int_{{o}} ^{+{oo}} {e}^{{E}\left({x}\right)} {dx} \\ $$

Question Number 180695 Answers: 1 Comments: 0

Find all k, m, n ∈ N such that k!+3^m =3^n

$${Find}\:{all}\:{k},\:{m},\:{n}\:\in\:\mathbb{N}\:{such}\:{that} \\ $$$${k}!+\mathrm{3}^{{m}} =\mathrm{3}^{{n}} \\ $$

Question Number 180684 Answers: 1 Comments: 0

Question Number 180683 Answers: 1 Comments: 0

(b) x + y + Kz = 2 3x + 4y + 2z = K 2x + 3y − z = 1

$$\left(\mathrm{b}\right)\:\mathrm{x}\:+\:\mathrm{y}\:+\:\mathrm{Kz}\:=\:\mathrm{2} \\ $$$$\:\:\:\:\mathrm{3x}\:+\:\mathrm{4y}\:+\:\mathrm{2z}\:=\:\mathrm{K} \\ $$$$\:\:\:\:\mathrm{2x}\:+\:\mathrm{3y}\:−\:\mathrm{z}\:=\:\mathrm{1} \\ $$

Question Number 180667 Answers: 3 Comments: 1

Question Number 180680 Answers: 4 Comments: 0

Question Number 180682 Answers: 1 Comments: 0

Determine the value of k such that the following system has (i) a Unique solution (ii) No solution (iii) More than one solution (a) Kx + y + z = 1 x +Ky + z = 1 x + y + Kz = 1

$$\mathrm{Determine}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{k}\:\mathrm{such}\:\mathrm{that}\:\mathrm{the} \\ $$$$\mathrm{following}\:\mathrm{system}\:\mathrm{has}\:\left(\mathrm{i}\right)\:\mathrm{a}\:\mathrm{Unique}\: \\ $$$$\mathrm{solution}\:\left(\mathrm{ii}\right)\:\mathrm{No}\:\mathrm{solution}\:\left(\mathrm{iii}\right)\:\mathrm{More}\:\mathrm{than} \\ $$$$\mathrm{one}\:\mathrm{solution} \\ $$$$ \\ $$$$\left(\mathrm{a}\right)\:\mathrm{Kx}\:+\:\mathrm{y}\:+\:\mathrm{z}\:=\:\mathrm{1} \\ $$$$\:\:\:\:\mathrm{x}\:+\mathrm{Ky}\:+\:\mathrm{z}\:=\:\mathrm{1} \\ $$$$\:\:\:\:\mathrm{x}\:+\:\mathrm{y}\:+\:\mathrm{Kz}\:=\:\mathrm{1} \\ $$

Question Number 180625 Answers: 1 Comments: 0

During the challenge Cup season. Team A scored 15 goals more than Team B. They have 121 goals between them. how many goals did each team score?

$$\mathrm{During}\:\mathrm{the}\:\mathrm{challenge}\:\mathrm{Cup}\:\mathrm{season}.\:\mathrm{Team} \\ $$$$\mathrm{A}\:\mathrm{scored}\:\mathrm{15}\:\mathrm{goals}\:\mathrm{more}\:\mathrm{than}\:\mathrm{Team}\:\mathrm{B}. \\ $$$$\mathrm{They}\:\mathrm{have}\:\mathrm{121}\:\mathrm{goals}\:\mathrm{between}\:\mathrm{them}. \\ $$$$\mathrm{how}\:\mathrm{many}\:\mathrm{goals}\:\mathrm{did}\:\mathrm{each}\:\mathrm{team}\:\mathrm{score}? \\ $$$$ \\ $$

Question Number 180623 Answers: 1 Comments: 0

Question Number 180621 Answers: 1 Comments: 0

Question Number 180615 Answers: 3 Comments: 0

Question Number 180614 Answers: 0 Comments: 0

Question Number 180604 Answers: 1 Comments: 0

Question Number 180603 Answers: 0 Comments: 1

find the real solution of following equation system: x^2 +xy+y^2 =p y^2 +yz+z^2 =q z^2 +zx+x^2 =r with p,q,r>0

$${find}\:{the}\:{real}\:{solution}\:{of}\:{following} \\ $$$${equation}\:{system}: \\ $$$$\boldsymbol{{x}}^{\mathrm{2}} +\boldsymbol{{xy}}+\boldsymbol{{y}}^{\mathrm{2}} =\boldsymbol{{p}} \\ $$$$\boldsymbol{{y}}^{\mathrm{2}} +\boldsymbol{{yz}}+\boldsymbol{{z}}^{\mathrm{2}} =\boldsymbol{{q}} \\ $$$$\boldsymbol{{z}}^{\mathrm{2}} +\boldsymbol{{zx}}+\boldsymbol{{x}}^{\mathrm{2}} =\boldsymbol{{r}} \\ $$$${with}\:{p},{q},{r}>\mathrm{0} \\ $$

Question Number 180599 Answers: 1 Comments: 0

Find the length PQ.

$${Find}\:{the}\:{length}\:{PQ}. \\ $$

Question Number 180585 Answers: 2 Comments: 0

there are 5 points on a line and 4 points on a parallel line. how many quadrilaterals can be formed with these points as vertrices?

$${there}\:{are}\:\mathrm{5}\:{points}\:{on}\:{a}\:{line}\:{and}\:\mathrm{4}\: \\ $$$${points}\:{on}\:{a}\:{parallel}\:{line}. \\ $$$${how}\:{many}\:{quadrilaterals}\:{can}\:{be}\: \\ $$$${formed}\:{with}\:{these}\:{points}\:{as}\: \\ $$$${vertrices}? \\ $$

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