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Question Number 225892 Answers: 2 Comments: 0

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Question 222520

$${Question}\:\mathrm{222520} \\ $$

Question Number 225861 Answers: 0 Comments: 0

∫_0 ^1 (√((ln^(12) (1−x))/( (√((ln^(12) (1−x))/( (√((ln^(12) (1−x))/( (√((ln^(12) (1−x))/(...))))))))))))dx=?

$$\int_{\mathrm{0}} ^{\mathrm{1}} \sqrt{\frac{{ln}^{\mathrm{12}} \left(\mathrm{1}−{x}\right)}{\:\sqrt{\frac{{ln}^{\mathrm{12}} \left(\mathrm{1}−{x}\right)}{\:\sqrt{\frac{{ln}^{\mathrm{12}} \left(\mathrm{1}−{x}\right)}{\:\sqrt{\frac{{ln}^{\mathrm{12}} \left(\mathrm{1}−{x}\right)}{...}}}}}}}}{dx}=? \\ $$

Question Number 225840 Answers: 1 Comments: 1

Question Number 225837 Answers: 3 Comments: 0

Show that, log(√(7(√(7(√(7(√(7....α)))))))) =1

$${Show}\:{that},\:{log}\sqrt{\mathrm{7}\sqrt{\mathrm{7}\sqrt{\mathrm{7}\sqrt{\mathrm{7}....\alpha}}}}\:=\mathrm{1} \\ $$

Question Number 225832 Answers: 2 Comments: 3

Question Number 225820 Answers: 1 Comments: 1

Question Number 225814 Answers: 1 Comments: 0

∫∣x∣dx

$$\int\mid{x}\mid{dx} \\ $$

Question Number 225810 Answers: 0 Comments: 0

Prove that in any triangle: ((4R)/r) ≥ ((w_a w_b w_c )/(h_a h_b h_c )) ∙ ((1/a) + (1/b))∙((√a) + (√b))^2

$$\mathrm{Prove}\:\mathrm{that}\:\mathrm{in}\:\mathrm{any}\:\mathrm{triangle}: \\ $$$$\frac{\mathrm{4R}}{\mathrm{r}}\:\geqslant\:\frac{\mathrm{w}_{\boldsymbol{\mathrm{a}}} \:\mathrm{w}_{\boldsymbol{\mathrm{b}}} \:\mathrm{w}_{\boldsymbol{\mathrm{c}}} }{\mathrm{h}_{\boldsymbol{\mathrm{a}}} \:\mathrm{h}_{\boldsymbol{\mathrm{b}}} \:\mathrm{h}_{\boldsymbol{\mathrm{c}}} }\:\centerdot\:\left(\frac{\mathrm{1}}{\mathrm{a}}\:+\:\frac{\mathrm{1}}{\mathrm{b}}\right)\centerdot\left(\sqrt{\mathrm{a}}\:+\:\sqrt{\mathrm{b}}\right)^{\mathrm{2}} \\ $$

Question Number 225776 Answers: 1 Comments: 3

Question Number 225788 Answers: 1 Comments: 25

∫_( (√2)−1) ^( y) (√((2(√2))y−1))dy

$$\int_{\:\sqrt{\mathrm{2}}−\mathrm{1}} ^{\:{y}} \sqrt{\left(\mathrm{2}\sqrt{\mathrm{2}}\right){y}−\mathrm{1}}{dy} \\ $$

Question Number 225786 Answers: 1 Comments: 0

Question Number 225758 Answers: 4 Comments: 1

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Question Number 225740 Answers: 1 Comments: 0

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((−1))^(1/i)

$$\sqrt[{{i}}]{−\mathrm{1}} \\ $$

Question Number 225676 Answers: 0 Comments: 0

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