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Question Number 182533 Answers: 1 Comments: 0

If you walk around a triangle with sides 3, 6, 8 respectively such a way that you keep a distance of 3m from it, then how much distance will you travel?

$${If}\:{you}\:{walk}\:{around}\:{a}\:{triangle}\:{with}\:{sides}\:\mathrm{3},\:\mathrm{6},\:\mathrm{8} \\ $$$${respectively}\:{such}\:{a}\:{way}\:{that}\:{you}\:{keep}\:{a}\:{distance} \\ $$$$\:{of}\:\mathrm{3}{m}\:{from}\:{it},\:{then}\: \\ $$$$\:{how}\:{much}\:{distance}\:{will}\:{you}\:{travel}? \\ $$

Question Number 182532 Answers: 0 Comments: 0

Q.181494 Let′s try it

$${Q}.\mathrm{181494} \\ $$$$\:{Let}'{s}\:{try}\:{it} \\ $$

Question Number 182530 Answers: 3 Comments: 0

If: (a/x^9 ) + (x^9 /a) = 7 find: ((a/x^9 ))^(1/4) + ((x^9 /a))^(1/4)

$${If}:\:\:\:\frac{{a}}{{x}^{\mathrm{9}} }\:+\:\frac{{x}^{\mathrm{9}} }{{a}}\:=\:\mathrm{7} \\ $$$$\:{find}:\:\sqrt[{\mathrm{4}}]{\frac{{a}}{{x}^{\mathrm{9}} }}\:+\:\sqrt[{\mathrm{4}}]{\frac{{x}^{\mathrm{9}} }{{a}}} \\ $$

Question Number 182529 Answers: 1 Comments: 0

∫_0 ^1 ((x−1)/((x+1)lnx))dx=?

$$\underset{\mathrm{0}} {\overset{\mathrm{1}} {\int}}\frac{{x}−\mathrm{1}}{\left({x}+\mathrm{1}\right){lnx}}{dx}=? \\ $$

Question Number 182528 Answers: 0 Comments: 1

lim_(x→0) (x!!)^(1/x) =?

$${li}\underset{{x}\rightarrow\mathrm{0}} {{m}}\left({x}!!\right)^{\frac{\mathrm{1}}{{x}}} =? \\ $$

Question Number 182514 Answers: 1 Comments: 1

1. prove that the equaion of parabola whose axis of symmetry is parallel to y axisis given as (x−h)^2 =+_− 4p(y−k) 2. if Dis a perpendicular distance of the point p(r,t)from the line (L):(x/r)+(y/t)=1 then find the value of D why not helped me??

$$\mathrm{1}.\:{prove}\:{that}\:{the}\:{equaion}\:{of}\:{parabola} \\ $$$$\:\:{whose}\:{axis}\:{of}\:{symmetry}\:{is}\:{parallel}\: \\ $$$${to}\:{y}\:{axisis}\:{given}\:{as}\:\left({x}−{h}\right)^{\mathrm{2}} =\underset{−} {+}\:\mathrm{4}{p}\left({y}−{k}\right) \\ $$$$\mathrm{2}.\:\:\:{if}\:{Dis}\:{a}\:{perpendicular}\:{distance}\: \\ $$$$\:\:\:{of}\:{the}\:{point}\:{p}\left({r},{t}\right){from}\:{the}\:{line} \\ $$$$\:\:\:\:\left({L}\right):\frac{{x}}{{r}}+\frac{{y}}{{t}}=\mathrm{1}\:\:{then}\:{find}\:{the} \\ $$$$\:\:\:\:\:\:\:{value}\:{of}\:{D} \\ $$$$\:{why}\:{not}\:{helped}\:{me}?? \\ $$

Question Number 182512 Answers: 2 Comments: 0

Question Number 182508 Answers: 1 Comments: 0

Question Number 182507 Answers: 0 Comments: 0

Can a mathematician solve or know everything?

$$\:{Can}\:{a}\:{mathematician}\:{solve}\:{or}\:{know}\:{everything}? \\ $$

Question Number 182506 Answers: 1 Comments: 0

Calculate S = 1×1! + 2×2! + 3×3! + ...+ n×n!

$$\:\:{Calculate}\:{S}\:=\:\mathrm{1}×\mathrm{1}!\:+\:\mathrm{2}×\mathrm{2}!\:+\:\mathrm{3}×\mathrm{3}!\:+\:...+\:{n}×{n}! \\ $$$$\:\:\: \\ $$

Question Number 182500 Answers: 1 Comments: 1

Question Number 182494 Answers: 0 Comments: 4

Question Number 182486 Answers: 0 Comments: 0

Question Number 182474 Answers: 3 Comments: 0

Find the number of sides of two regular polygons that their sides has a ratio 5:4 and of 9° as a difference between their angles.

$${Find}\:{the}\:{number}\:{of}\:{sides}\:{of}\:{two}\:{regular}\:{polygons} \\ $$$$\:{that}\:{their}\:{sides}\:{has}\:{a}\:{ratio}\:\mathrm{5}:\mathrm{4}\:{and}\:{of}\:\mathrm{9}°\:{as}\:{a} \\ $$$$\:{difference}\:{between}\:{their}\:{angles}. \\ $$

Question Number 182472 Answers: 1 Comments: 0

If you walk around a triangle 4m each side such a way that you keep a distance of 2m from it, then how much distance will you travel?

$${If}\:{you}\:{walk}\:{around}\:{a}\:{triangle}\:\mathrm{4}{m}\:{each}\:{side}\:{such} \\ $$$$\:{a}\:{way}\:{that}\:{you}\:{keep}\:{a}\:{distance}\:{of}\:\mathrm{2}{m}\:{from}\:{it},\:{then} \\ $$$${how}\:{much}\:{distance}\:{will}\:{you}\:{travel}? \\ $$

Question Number 182453 Answers: 1 Comments: 0

Question Number 182441 Answers: 2 Comments: 0

Question Number 182438 Answers: 1 Comments: 0

[Help me!] The rate of change of w = x^3 y^2 z + y^3 z^2 − xz^4 at the point Q(0, 1, 2) in the direction V^→ = 2i + j + 2k is: a) −2 b) −3 c) −4 d) No alternative

Question Number 182437 Answers: 1 Comments: 0