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AllQuestion and Answers: Page 380

Question Number 174664 Answers: 1 Comments: 0

Question Number 174661 Answers: 1 Comments: 0

After being marked down 20 percent. a calculator sells for $10. The Original selling price was ?

$$\mathrm{After}\:\mathrm{being}\:\mathrm{marked}\:\mathrm{down}\:\mathrm{20}\:\mathrm{percent}. \\ $$$$\mathrm{a}\:\mathrm{calculator}\:\mathrm{sells}\:\mathrm{for}\:\$\mathrm{10}.\:\mathrm{The}\:\mathrm{Original} \\ $$$$\mathrm{selling}\:\mathrm{price}\:\mathrm{was}\:? \\ $$

Question Number 174655 Answers: 1 Comments: 0

Factorize a^3 − 16a − 3

$$\mathrm{Factorize}\:{a}^{\mathrm{3}} \:−\:\mathrm{16}{a}\:−\:\mathrm{3} \\ $$

Question Number 174654 Answers: 0 Comments: 1

Factorize x^9 + x^7 + 1

$$\mathrm{Factorize}\:{x}^{\mathrm{9}} \:+\:{x}^{\mathrm{7}} \:+\:\mathrm{1} \\ $$

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Question Number 174628 Answers: 1 Comments: 2

Ω = ∫ (x/(1+csc x)) dx =?

$$\:\:\:\Omega\:=\:\int\:\frac{{x}}{\mathrm{1}+\mathrm{csc}\:{x}}\:{dx}\:=? \\ $$

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Question Number 174613 Answers: 1 Comments: 0

In a mixture of Skettles and M&M′s, 80% of the pieces are M&M′s. A fourth of this mixture is replaced by a second mixture, resulting in combination which contain 16% Skittles in total. What was the percentage of Skittles in the second mixture?

$$\mathrm{In}\:\mathrm{a}\:\mathrm{mixture}\:\mathrm{of}\:\:\mathrm{Skettles}\:\mathrm{and}\:\mathrm{M\&M}'\mathrm{s}, \\ $$$$\mathrm{80\%}\:\mathrm{of}\:\mathrm{the}\:\mathrm{pieces}\:\mathrm{are}\:\mathrm{M\&M}'\mathrm{s}.\:\mathrm{A}\:\mathrm{fourth} \\ $$$$\mathrm{of}\:\mathrm{this}\:\mathrm{mixture}\:\mathrm{is}\:\mathrm{replaced}\:\mathrm{by}\:\mathrm{a}\:\mathrm{second} \\ $$$$\mathrm{mixture},\:\mathrm{resulting}\:\mathrm{in}\:\mathrm{combination} \\ $$$$\mathrm{which}\:\mathrm{contain}\:\mathrm{16\%}\:\mathrm{Skittles}\:\mathrm{in}\:\mathrm{total}. \\ $$$$\mathrm{What}\:\mathrm{was}\:\mathrm{the}\:\mathrm{percentage}\:\mathrm{of}\:\mathrm{Skittles} \\ $$$$\mathrm{in}\:\mathrm{the}\:\mathrm{second}\:\mathrm{mixture}? \\ $$

Question Number 174612 Answers: 0 Comments: 1

Question Number 174611 Answers: 0 Comments: 2

Find the expected payback for a game in which you bet $8.00 on any number from 0 to 99 and if your number comes up, you win $2,000.00

$$\mathrm{Find}\:\mathrm{the}\:\mathrm{expected}\:\mathrm{payback}\:\mathrm{for}\:\mathrm{a}\: \\ $$$$\mathrm{game}\:\mathrm{in}\:\mathrm{which}\:\mathrm{you}\:\mathrm{bet}\:\$\mathrm{8}.\mathrm{00}\:\mathrm{on}\:\mathrm{any} \\ $$$$\mathrm{number}\:\mathrm{from}\:\mathrm{0}\:\mathrm{to}\:\mathrm{99}\:\mathrm{and}\:\mathrm{if}\:\mathrm{your} \\ $$$$\mathrm{number}\:\mathrm{comes}\:\mathrm{up},\:\mathrm{you}\:\mathrm{win}\:\$\mathrm{2},\mathrm{000}.\mathrm{00} \\ $$

Question Number 174610 Answers: 0 Comments: 0

find the value of this integral: I=∫_0 ^∞ ((tan^(−1) (x))/(1+x+x^2 )) dx

$${find}\:{the}\:{value}\:{of}\:{this}\:{integral}: \\ $$$${I}=\int_{\mathrm{0}} ^{\infty} \:\frac{{tan}^{−\mathrm{1}} \left({x}\right)}{\mathrm{1}+{x}+{x}^{\mathrm{2}} }\:{dx} \\ $$

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Question Number 174594 Answers: 1 Comments: 0

Let σ(n) be the sum of all positive divisors of the integer n and let p be any prime number. show that σ(n)<2n holds true for all n of the form n=p^2 . Mastermind

$$\mathrm{Let}\:\sigma\left(\mathrm{n}\right)\:\mathrm{be}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{all}\:\mathrm{positive} \\ $$$$\mathrm{divisors}\:\mathrm{of}\:\mathrm{the}\:\mathrm{integer}\:\mathrm{n}\:\mathrm{and}\:\mathrm{let}\:\mathrm{p}\:\mathrm{be} \\ $$$$\mathrm{any}\:\mathrm{prime}\:\mathrm{number}.\:\mathrm{show}\:\mathrm{that}\: \\ $$$$\sigma\left(\mathrm{n}\right)<\mathrm{2n}\:\mathrm{holds}\:\mathrm{true}\:\mathrm{for}\:\mathrm{all}\:\mathrm{n}\:\mathrm{of}\:\mathrm{the}\: \\ $$$$\mathrm{form}\:\mathrm{n}=\mathrm{p}^{\mathrm{2}} . \\ $$$$ \\ $$$$\mathrm{Mastermind} \\ $$

Question Number 174630 Answers: 1 Comments: 0

lim_(n→∞) Σ_(r=1) ^∞ (r/(n^2 +r))

$$\:\:\underset{{n}\rightarrow\infty} {\mathrm{lim}}\:\underset{{r}=\mathrm{1}} {\overset{\infty} {\sum}}\:\frac{{r}}{{n}^{\mathrm{2}} +{r}} \\ $$

Question Number 174591 Answers: 1 Comments: 0

The drawing below shows two equilateral triangles with side length a. The triangle are horizontally shifted by (a/2). Find the intersection area A of the two triangles (grey area).

$$\mathrm{The}\:\mathrm{drawing}\:\mathrm{below}\:\mathrm{shows}\:\mathrm{two}\: \\ $$$$\mathrm{equilateral}\:\mathrm{triangles}\:\mathrm{with}\:\mathrm{side}\:\mathrm{length} \\ $$$$\boldsymbol{\mathrm{a}}.\:\mathrm{The}\:\mathrm{triangle}\:\mathrm{are}\:\mathrm{horizontally}\:\mathrm{shifted} \\ $$$$\mathrm{by}\:\frac{\mathrm{a}}{\mathrm{2}}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{intersection}\:\mathrm{area}\:\mathrm{A}\:\mathrm{of} \\ $$$$\mathrm{the}\:\mathrm{two}\:\mathrm{triangles}\:\left(\mathrm{grey}\:\mathrm{area}\right). \\ $$$$ \\ $$$$ \\ $$$$ \\ $$

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Your friend makes 6 field goals and 2 free throws. You make twice as many field goals as your friend and half the number of free throws. How many points do you have. explain the order of operation you followed

$$\:\mathrm{Your}\:\mathrm{friend}\:\mathrm{makes}\:\mathrm{6}\:\mathrm{field}\:\mathrm{goals}\:\mathrm{and}\: \\ $$$$\:\:\mathrm{2}\:\mathrm{free}\:\mathrm{throws}.\:\mathrm{You}\:\mathrm{make}\:\mathrm{twice}\:\mathrm{as} \\ $$$$\:\mathrm{many}\:\mathrm{field}\:\mathrm{goals}\:\mathrm{as}\:\mathrm{your}\:\mathrm{friend}\:\mathrm{and}\: \\ $$$$\:\mathrm{half}\:\mathrm{the}\:\mathrm{number}\:\mathrm{of}\:\mathrm{free}\:\mathrm{throws}.\:\mathrm{How} \\ $$$$\mathrm{many}\:\mathrm{points}\:\mathrm{do}\:\mathrm{you}\:\mathrm{have}.\:\mathrm{explain}\:\mathrm{the} \\ $$$$\mathrm{order}\:\mathrm{of}\:\mathrm{operation}\:\mathrm{you}\:\mathrm{followed} \\ $$$$\:\:\:\:\: \\ $$

Question Number 174582 Answers: 0 Comments: 0

Your friend makes 4 field goals . you make three times as many field goals as your friend plus one field goals. how many points do you have. Explain the order of operation you followed

$$\:\mathrm{Your}\:\mathrm{friend}\:\mathrm{makes}\:\mathrm{4}\:\mathrm{field}\:\mathrm{goals}\:.\:\mathrm{you} \\ $$$$\:\mathrm{make}\:\mathrm{three}\:\mathrm{times}\:\mathrm{as}\:\mathrm{many}\:\mathrm{field}\:\mathrm{goals} \\ $$$$\mathrm{as}\:\mathrm{your}\:\mathrm{friend}\:\mathrm{plus}\:\mathrm{one}\:\mathrm{field}\:\mathrm{goals}. \\ $$$$\:\mathrm{how}\:\mathrm{many}\:\mathrm{points}\:\mathrm{do}\:\mathrm{you}\:\mathrm{have}.\: \\ $$$$\mathrm{Explain}\:\mathrm{the}\:\mathrm{order}\:\mathrm{of}\:\mathrm{operation}\:\mathrm{you}\: \\ $$$$\mathrm{followed} \\ $$

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