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AllQuestion and Answers: Page 380

Question Number 183209 Answers: 1 Comments: 0

Solve the Differential equation below (d^3 y/dx^3 )+8(d^2 y/dx^2 )+12(dy/dx)=0 M.m

$$\mathrm{Solve}\:\mathrm{the}\:\mathrm{Differential}\:\mathrm{equation}\:\mathrm{below} \\ $$$$\frac{\mathrm{d}^{\mathrm{3}} \mathrm{y}}{\mathrm{dx}^{\mathrm{3}} }+\mathrm{8}\frac{\mathrm{d}^{\mathrm{2}} \mathrm{y}}{\mathrm{dx}^{\mathrm{2}} }+\mathrm{12}\frac{\mathrm{dy}}{\mathrm{dx}}=\mathrm{0} \\ $$$$ \\ $$$$ \\ $$$$\mathrm{M}.\mathrm{m} \\ $$

Question Number 183205 Answers: 2 Comments: 0

Find the coefficient of x^(11) in (2x^2 +x−3)^6 .

$$\:\:{Find}\:{the}\:{coefficient}\:{of}\:{x}^{\mathrm{11}} \:{in}\: \\ $$$$\:\left(\mathrm{2}{x}^{\mathrm{2}} +{x}−\mathrm{3}\right)^{\mathrm{6}} \:. \\ $$

Question Number 183202 Answers: 2 Comments: 0

ax^3 +bx^2 +c=0 x_1 = x_2 = x_3 =

$${ax}^{\mathrm{3}} +{bx}^{\mathrm{2}} +{c}=\mathrm{0} \\ $$$${x}_{\mathrm{1}} = \\ $$$${x}_{\mathrm{2}} = \\ $$$${x}_{\mathrm{3}} = \\ $$

Question Number 183295 Answers: 2 Comments: 1

Question Number 183185 Answers: 1 Comments: 0

Question Number 183181 Answers: 2 Comments: 1

prove that (0/0)=1

$${prove}\:{that}\:\frac{\mathrm{0}}{\mathrm{0}}=\mathrm{1} \\ $$

Question Number 183174 Answers: 0 Comments: 2

In the given figure E is the mid point of AB. IF the area of ΔEBF is 8cm^2 .find the area of the parallelogram ABCD.

$$\mathrm{In}\:\mathrm{the}\:\mathrm{given}\:\mathrm{figure}\:\mathrm{E}\:\mathrm{is}\:\mathrm{the}\:\mathrm{mid}\:\mathrm{point}\:\mathrm{of}\:\mathrm{AB}. \\ $$$$\:\mathrm{IF}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\Delta\mathrm{EBF}\:\mathrm{is}\:\mathrm{8cm}^{\mathrm{2}} .\mathrm{find}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{the}\:\mathrm{parallelogram}\:\mathrm{ABCD}. \\ $$

Question Number 183165 Answers: 1 Comments: 0

Question Number 183167 Answers: 0 Comments: 2

In △ABC the following relationship holds: (m_b /b) + (m_c /c) ≤ (a/(2r)) ≤ (n_b /h_b ) + (n_c /h_c )

$$\mathrm{In}\:\:\:\bigtriangleup\mathrm{ABC}\:\:\:\mathrm{the}\:\mathrm{following}\:\mathrm{relationship} \\ $$$$\mathrm{holds}: \\ $$$$\frac{\mathrm{m}_{\boldsymbol{\mathrm{b}}} }{\mathrm{b}}\:+\:\frac{\mathrm{m}_{\boldsymbol{\mathrm{c}}} }{\mathrm{c}}\:\leqslant\:\frac{\mathrm{a}}{\mathrm{2r}}\:\leqslant\:\frac{\mathrm{n}_{\boldsymbol{\mathrm{b}}} }{\mathrm{h}_{\boldsymbol{\mathrm{b}}} }\:+\:\frac{\mathrm{n}_{\boldsymbol{\mathrm{c}}} }{\mathrm{h}_{\boldsymbol{\mathrm{c}}} } \\ $$

Question Number 183162 Answers: 1 Comments: 0

Question Number 183158 Answers: 1 Comments: 0

Given f(x)= (([(1/3)x]∣2x∣+Ax)/(∣4−x^2 ∣)) if f ′(−1)= 5 then A=? [ ] = floor function

$$\:{Given}\:{f}\left({x}\right)=\:\frac{\left[\frac{\mathrm{1}}{\mathrm{3}}{x}\right]\mid\mathrm{2}{x}\mid+{Ax}}{\mid\mathrm{4}−{x}^{\mathrm{2}} \mid} \\ $$$$\:{if}\:{f}\:'\left(−\mathrm{1}\right)=\:\mathrm{5}\:{then}\:{A}=? \\ $$$$\left[\:\:\:\:\right]\:=\:{floor}\:{function}\: \\ $$

Question Number 183157 Answers: 1 Comments: 0

∫ (dx/( ((x^3 +2019))^(1/3) )) =?

$$\:\int\:\frac{{dx}}{\:\sqrt[{\mathrm{3}}]{{x}^{\mathrm{3}} +\mathrm{2019}}}\:=? \\ $$

Question Number 183156 Answers: 1 Comments: 0

∫ ((sin 2x dx)/(sin x−sin^2 2x)) =?

$$\:\int\:\frac{\mathrm{sin}\:\mathrm{2}{x}\:{dx}}{\mathrm{sin}\:{x}−\mathrm{sin}\:^{\mathrm{2}} \mathrm{2}{x}}\:=? \\ $$

Question Number 183136 Answers: 3 Comments: 0

lim_(x→0) ((sinx−x)/x^3 )=?

$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\frac{{sinx}−{x}}{{x}^{\mathrm{3}} }=? \\ $$

Question Number 183124 Answers: 1 Comments: 0

Question Number 183123 Answers: 1 Comments: 0

∫ln(tanx)dx

$$\int{ln}\left({tanx}\right){dx} \\ $$

Question Number 183184 Answers: 1 Comments: 1

Question Number 183120 Answers: 2 Comments: 0

I−Incenter in △ABC A(2,2) , B(6,4) , C(4,8) , M(8,6) Find: MI = ?

$$\mathrm{I}−\mathrm{Incenter}\:\mathrm{in}\:\:\bigtriangleup\mathrm{ABC} \\ $$$$\mathrm{A}\left(\mathrm{2},\mathrm{2}\right)\:,\:\mathrm{B}\left(\mathrm{6},\mathrm{4}\right)\:,\:\mathrm{C}\left(\mathrm{4},\mathrm{8}\right)\:,\:\mathrm{M}\left(\mathrm{8},\mathrm{6}\right) \\ $$$$\mathrm{Find}:\:\:\:\mathrm{MI}\:=\:? \\ $$

Question Number 183119 Answers: 0 Comments: 0

Question Number 183118 Answers: 0 Comments: 0

Question Number 183117 Answers: 2 Comments: 0

Question Number 183116 Answers: 0 Comments: 1

Question Number 183254 Answers: 2 Comments: 0

Question Number 183109 Answers: 2 Comments: 0

∫_0 ^(π/2) ((√(sin x+1))/( (√(cos x+1)))) dx =?

$$\:\:\underset{\mathrm{0}} {\overset{\pi/\mathrm{2}} {\int}}\:\frac{\sqrt{\mathrm{sin}\:{x}+\mathrm{1}}}{\:\sqrt{\mathrm{cos}\:{x}+\mathrm{1}}}\:{dx}\:=?\: \\ $$

Question Number 183107 Answers: 1 Comments: 1

Question Number 186086 Answers: 0 Comments: 0

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