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AllQuestion and Answers: Page 349

Question Number 187191 Answers: 2 Comments: 2

Question Number 187190 Answers: 2 Comments: 0

Question Number 187186 Answers: 2 Comments: 6

Question Number 187184 Answers: 0 Comments: 0

×/ { { {{×=

$$ ×/ \left\{ \left\{ \left\{\left\{×=\right.\right.\right.\right. \\ $$

Question Number 187177 Answers: 1 Comments: 0

2^y y^2 +(2y)^((2y)) =272

$$ \\ $$$$\mathrm{2}^{{y}} {y}^{\mathrm{2}} +\left(\mathrm{2}{y}\right)^{\left(\mathrm{2}{y}\right)} =\mathrm{272} \\ $$

Question Number 187176 Answers: 1 Comments: 0

Question Number 187168 Answers: 0 Comments: 0

Question Number 187167 Answers: 3 Comments: 0

Question Number 187166 Answers: 0 Comments: 0

x^3 =x+c let x=((mt)/(1−t)) m^3 t^3 =mt(1−t)^2 +c(1−t)^3 ⇒ (m^3 −m−c)t^3 +(2m−3c)t^2 +(3c−m)t−c=0 t^3 +At^2 +Bt+C=0 let AB=C ⇒ (2m−3c)(m−3c)=c(m^3 −m−c) ⇒ m^3 −(2/c)m^2 −8m+10c=0 ...

$${x}^{\mathrm{3}} ={x}+{c} \\ $$$${let}\:\:{x}=\frac{{mt}}{\mathrm{1}−{t}} \\ $$$${m}^{\mathrm{3}} {t}^{\mathrm{3}} ={mt}\left(\mathrm{1}−{t}\right)^{\mathrm{2}} +{c}\left(\mathrm{1}−{t}\right)^{\mathrm{3}} \\ $$$$\Rightarrow \\ $$$$\left({m}^{\mathrm{3}} −{m}−{c}\right){t}^{\mathrm{3}} +\left(\mathrm{2}{m}−\mathrm{3}{c}\right){t}^{\mathrm{2}} \\ $$$$\:\:\:\:\:+\left(\mathrm{3}{c}−{m}\right){t}−{c}=\mathrm{0} \\ $$$${t}^{\mathrm{3}} +{At}^{\mathrm{2}} +{Bt}+{C}=\mathrm{0} \\ $$$${let}\:\:{AB}={C} \\ $$$$\Rightarrow\:\left(\mathrm{2}{m}−\mathrm{3}{c}\right)\left({m}−\mathrm{3}{c}\right)={c}\left({m}^{\mathrm{3}} −{m}−{c}\right) \\ $$$$\Rightarrow\:{m}^{\mathrm{3}} −\frac{\mathrm{2}}{{c}}{m}^{\mathrm{2}} −\mathrm{8}{m}+\mathrm{10}{c}=\mathrm{0} \\ $$$$... \\ $$

Question Number 187164 Answers: 1 Comments: 0

Question Number 187155 Answers: 2 Comments: 2

f(x)=x.e^(2x) =>f^((n)) (x)=

$${f}\left({x}\right)={x}.{e}^{\mathrm{2}{x}} \\ $$$$=>{f}^{\left({n}\right)} \left({x}\right)= \\ $$$$ \\ $$

Question Number 187146 Answers: 2 Comments: 0

Question Number 187144 Answers: 0 Comments: 1

determiner les elements demandes (fig ci−joint)

$${determiner}\:{les}\:{elements} \\ $$$${demandes}\:\left({fig}\:{ci}−{joint}\right) \\ $$

Question Number 187142 Answers: 1 Comments: 2

Montrer que: 4r^2 =a^2 +b^2 +c^2 +d^2

$$\:{Montrer}\:{que}: \\ $$$$\mathrm{4}{r}^{\mathrm{2}} ={a}^{\mathrm{2}} +{b}^{\mathrm{2}} +{c}^{\mathrm{2}} +{d}^{\mathrm{2}} \\ $$$$ \\ $$

Question Number 187135 Answers: 1 Comments: 0

∫_( 0) ^( π/4) ((tan^2 x)/(1+sin x)) dx =?

$$\:\underset{\:\:\mathrm{0}} {\overset{\:\:\pi/\mathrm{4}} {\int}}\:\frac{\mathrm{tan}\:^{\mathrm{2}} {x}}{\mathrm{1}+\mathrm{sin}\:{x}}\:{dx}\:=? \\ $$

Question Number 187132 Answers: 0 Comments: 0

Question Number 187124 Answers: 2 Comments: 0

(a/x)=(b/y)=(c/z)=(1/3) , a−2b+c=2 and −2y+z=1 x=? An altered form of q#187020 (In this case solveable)

$$\frac{{a}}{{x}}=\frac{{b}}{{y}}=\frac{{c}}{{z}}=\frac{\mathrm{1}}{\mathrm{3}}\:, \\ $$$${a}−\mathrm{2}{b}+{c}=\mathrm{2}\:\:{and}\:\:−\mathrm{2}{y}+{z}=\mathrm{1}\:\:\:\: \\ $$$${x}=? \\ $$$${An}\:{altered}\:{form}\:{of}\:\:{q}#\mathrm{187020} \\ $$$$\left({In}\:{this}\:{case}\:{solveable}\right) \\ $$

Question Number 187100 Answers: 1 Comments: 0

Question Number 187095 Answers: 2 Comments: 1

∫_0 ^1 (1/( (√(1 − x^2 )))) + (1/( (√(1 − x^2 )))) dx

$$ \\ $$$$\:\:\:\:\:\:\:\:\int_{\mathrm{0}} ^{\mathrm{1}} \:\:\:\:\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{1}\:−\:\boldsymbol{{x}}^{\mathrm{2}} }}\:\:+\:\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{1}\:−\:\boldsymbol{{x}}^{\mathrm{2}} }}\:\:\boldsymbol{{dx}}\:\:\:\:\:\: \\ $$$$ \\ $$

Question Number 187092 Answers: 2 Comments: 0

lim_(x→0) ((sin x^3 −sin^3 x)/(x^3 (cos x^3 −cos^3 x))) =?

$$\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\frac{\mathrm{sin}\:{x}^{\mathrm{3}} −\mathrm{sin}\:^{\mathrm{3}} {x}}{{x}^{\mathrm{3}} \left(\mathrm{cos}\:{x}^{\mathrm{3}} −\mathrm{cos}\:^{\mathrm{3}} {x}\right)}\:=? \\ $$

Question Number 187091 Answers: 2 Comments: 0

⌊x^2 ⌋ − ⌊x⌋^2 =100 x∈R min(x)=?

$$ \\ $$$$\lfloor{x}^{\mathrm{2}} \rfloor\:\:−\:\:\lfloor{x}\rfloor^{\mathrm{2}} \:=\mathrm{100} \\ $$$${x}\in\mathbb{R} \\ $$$${min}\left({x}\right)=? \\ $$

Question Number 187088 Answers: 0 Comments: 1

prove to (0/0)=2

$$\mathrm{prove}\:\mathrm{to}\:\:\:\:\:\:\:\:\:\:\:\:\:\frac{\mathrm{0}}{\mathrm{0}}=\mathrm{2} \\ $$

Question Number 187087 Answers: 0 Comments: 1

(a/x)=(b/y)=(c/z)=(1/3) ,a−2b+c=2 and 2y−3z=1 x=? how is solution this qution solve by the Properties of proportion

$$ \\ $$$$\frac{{a}}{{x}}=\frac{{b}}{{y}}=\frac{{c}}{{z}}=\frac{\mathrm{1}}{\mathrm{3}}\:\:\:\:,{a}−\mathrm{2}{b}+{c}=\mathrm{2}\:\:{and}\:\:\mathrm{2}{y}−\mathrm{3}{z}=\mathrm{1}\:\:\:\:{x}=? \\ $$$${how}\:{is}\:{solution} \\ $$$$\:{this}\:{qution}\:{solve}\:{by}\:{the}\:\mathrm{Properties}\:\mathrm{of}\:\mathrm{proportion} \\ $$$$ \\ $$$$ \\ $$

Question Number 187086 Answers: 0 Comments: 0

Question Number 187085 Answers: 1 Comments: 0

Question Number 187080 Answers: 0 Comments: 0

The hands of a clock are known to move in clockwise direction. If the minute hand is turned manually thrice, in an anticlockwise movement from 11 round the clock and then left pointing to 4, calculate the smallest angle which would have been covered of the minute hand was moving in clockwise direction.

$$ \\ $$The hands of a clock are known to move in clockwise direction. If the minute hand is turned manually thrice, in an anticlockwise movement from 11 round the clock and then left pointing to 4, calculate the smallest angle which would have been covered of the minute hand was moving in clockwise direction.

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