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AllQuestion and Answers: Page 336

Question Number 179258    Answers: 1   Comments: 1

y=x^x^x (dy/dx)=?

$${y}={x}^{{x}^{{x}} } \\ $$$$\frac{{dy}}{{dx}}=? \\ $$

Question Number 179253    Answers: 1   Comments: 1

(fog)_x =cos2x and g(x)=tanx f(x)=?

$$\left({fog}\right)_{{x}} ={cos}\mathrm{2}{x}\:\:{and}\:{g}\left({x}\right)={tanx} \\ $$$${f}\left({x}\right)=? \\ $$

Question Number 179244    Answers: 2   Comments: 0

Evaluate ∫tan^4 x sec^5 x dx

$${Evaluate}\:\int\mathrm{tan}^{\mathrm{4}} \:{x}\:\mathrm{sec}^{\mathrm{5}} \:{x}\:{dx} \\ $$

Question Number 179242    Answers: 1   Comments: 1

f(x+1)= 2x−5 , find the value of the f(x) at x=2

$${f}\left({x}+\mathrm{1}\right)=\:\mathrm{2}{x}−\mathrm{5}\:,\:{find}\:{the}\:{value}\:{of}\:{the}\:{f}\left({x}\right)\:{at}\:{x}=\mathrm{2} \\ $$

Question Number 179230    Answers: 3   Comments: 0

f(x+y)=f(x)+f(y)+x∙y and f(4)=10 faind f(2022)=?

$${f}\left({x}+{y}\right)={f}\left({x}\right)+{f}\left({y}\right)+{x}\centerdot{y} \\ $$$${and}\:{f}\left(\mathrm{4}\right)=\mathrm{10}\:\:{faind}\:\:{f}\left(\mathrm{2022}\right)=? \\ $$

Question Number 179229    Answers: 1   Comments: 0

Question Number 179228    Answers: 1   Comments: 0

prove in right triangle : a^2 +b^2 =c^2 −−−−−−

$${prove}\:{in}\:{right}\:{triangle}\::\:{a}^{\mathrm{2}} +{b}^{\mathrm{2}} ={c}^{\mathrm{2}} \\ $$$$−−−−−− \\ $$

Question Number 179226    Answers: 2   Comments: 1

Question Number 179198    Answers: 5   Comments: 2

Question Number 179195    Answers: 1   Comments: 0

a+(1/b)=tan59 b+(1/c)=tan60 c+(1/a)=tan61 (abc)^(2022) +(1/((abc)^(2022) ))=?

$${a}+\frac{\mathrm{1}}{{b}}={tan}\mathrm{59} \\ $$$${b}+\frac{\mathrm{1}}{{c}}={tan}\mathrm{60} \\ $$$${c}+\frac{\mathrm{1}}{{a}}={tan}\mathrm{61} \\ $$$$\left({abc}\right)^{\mathrm{2022}} +\frac{\mathrm{1}}{\left({abc}\right)^{\mathrm{2022}} }=? \\ $$

Question Number 179194    Answers: 2   Comments: 0

Evaluate the ∫ ((tan^5 x)/(cos^9 x)) dx

$${Evaluate}\:{the}\:\int\:\frac{\mathrm{tan}^{\mathrm{5}} \:{x}}{\mathrm{cos}^{\mathrm{9}} \:{x}}\:{dx} \\ $$

Question Number 179175    Answers: 0   Comments: 2

Find ∫x^5 (√(x^3 +1)) dx Answer: I= (2/(45)) (3x^3 −2) (√((x^3 +1)^3 )) + c

$$\:{Find}\:\int{x}^{\mathrm{5}} \:\sqrt{{x}^{\mathrm{3}} +\mathrm{1}}\:{dx} \\ $$$$\: \\ $$$$\:{Answer}:\:{I}=\:\frac{\mathrm{2}}{\mathrm{45}}\:\left(\mathrm{3}{x}^{\mathrm{3}} −\mathrm{2}\right)\:\sqrt{\left({x}^{\mathrm{3}} +\mathrm{1}\right)^{\mathrm{3}} }\:+\:{c} \\ $$$$ \\ $$

Question Number 180359    Answers: 1   Comments: 0

Question Number 180035    Answers: 0   Comments: 4

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Question Number 179159    Answers: 1   Comments: 1

Question Number 179157    Answers: 1   Comments: 0

If x = a^2 − bc, y = b^2 − ca, z = c^2 − ab then prove that, x^3 + y^3 + z^3 − 3xyz is a perfect square.

$$\mathrm{If}\:{x}\:=\:{a}^{\mathrm{2}} −\:{bc},\:{y}\:=\:{b}^{\mathrm{2}} \:−\:{ca},\:{z}\:=\:{c}^{\mathrm{2}} \:−\:{ab} \\ $$$$\mathrm{then}\:\mathrm{prove}\:\mathrm{that}, \\ $$$${x}^{\mathrm{3}} \:+\:{y}^{\mathrm{3}} \:+\:{z}^{\mathrm{3}} \:−\:\mathrm{3}{xyz}\:\mathrm{is}\:\mathrm{a}\:\mathrm{perfect}\:\mathrm{square}. \\ $$

Question Number 179181    Answers: 3   Comments: 0

Help-me! Use double integral to find the area of the region bounded by the following curves given in the plane shown below: y^2 = 4x and x^2 = 4y

$$\:\mathrm{Help}-\mathrm{me}! \\ $$$$\: \\ $$$$\:\mathrm{Use}\:\mathrm{double}\:\mathrm{integral}\:\mathrm{to}\:\mathrm{find}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{the} \\ $$$$\:\mathrm{region}\:\mathrm{bounded}\:\mathrm{by}\:\mathrm{the}\:\mathrm{following}\:\mathrm{curves}\: \\ $$$$\:\mathrm{given}\:\mathrm{in}\:\mathrm{the}\:\mathrm{plane}\:\mathrm{shown}\:\mathrm{below}: \\ $$$$\: \\ $$$$\:\mathrm{y}^{\mathrm{2}} \:=\:\mathrm{4x}\:\mathrm{and}\:\:\boldsymbol{\mathrm{x}}^{\mathrm{2}} \:=\:\mathrm{4y} \\ $$

Question Number 179156    Answers: 0   Comments: 0

Question Number 179140    Answers: 4   Comments: 0

(1/(3a)) = (1/(4b)) = (1/(6c)) and a+b+c=27 find a−c=?

$$\frac{\mathrm{1}}{\mathrm{3a}}\:=\:\frac{\mathrm{1}}{\mathrm{4b}}\:=\:\frac{\mathrm{1}}{\mathrm{6c}}\:\:\:\mathrm{and}\:\:\:\mathrm{a}+\mathrm{b}+\mathrm{c}=\mathrm{27} \\ $$$$\mathrm{find}\:\:\:\mathrm{a}−\mathrm{c}=? \\ $$

Question Number 179137    Answers: 1   Comments: 0

Question Number 179131    Answers: 1   Comments: 8

Question Number 179105    Answers: 2   Comments: 0

1. Compare: π^(2022e) and e^(2022𝛑) 2. Compute value of P = π^𝛑^𝛑^(...^𝛑 )

$$\mathrm{1}.\:\mathrm{Compare}:\:\:\:\pi^{\mathrm{2022}\boldsymbol{\mathrm{e}}} \:\:\:\mathrm{and}\:\:\:\mathrm{e}^{\mathrm{2022}\boldsymbol{\pi}} \\ $$$$\mathrm{2}.\:\mathrm{Compute}\:\mathrm{value}\:\mathrm{of}\:\:\:\mathrm{P}\:=\:\pi^{\boldsymbol{\pi}^{\boldsymbol{\pi}^{...^{\boldsymbol{\pi}} } } } \\ $$

Question Number 179100    Answers: 4   Comments: 2

if x^2 +y^2 +xy=5, find the range of x^2 +y^2 −xy. (x,y ∈R)

$${if}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} +{xy}=\mathrm{5},\:{find}\:{the}\:{range}\:{of} \\ $$$${x}^{\mathrm{2}} +{y}^{\mathrm{2}} −{xy}. \\ $$$$\left({x},{y}\:\in\mathbb{R}\right) \\ $$

Question Number 179095    Answers: 2   Comments: 1

Question Number 179094    Answers: 0   Comments: 1

determine 1)L^− [((s^3 +3)/(s(s^2 +9)))] 2)L^− [(4/((s^2 +2s+5)^2 ))] L^− is the inverse laplace transform

$${determine} \\ $$$$\left.\mathrm{1}\right)\mathcal{L}^{−} \left[\frac{{s}^{\mathrm{3}} +\mathrm{3}}{{s}\left({s}^{\mathrm{2}} +\mathrm{9}\right)}\right] \\ $$$$\left.\mathrm{2}\right)\mathcal{L}^{−} \left[\frac{\mathrm{4}}{\left({s}^{\mathrm{2}} +\mathrm{2}{s}+\mathrm{5}\right)^{\mathrm{2}} }\right] \\ $$$$\mathcal{L}^{−} \:{is}\:{the}\:{inverse}\:{laplace}\:{transform} \\ $$

Question Number 179093    Answers: 0   Comments: 0

find the laplace transform of f(t)= t^2 cos(2t) u(t) u(t) is unit step function u(t)= { ((1 t≥0)),((0 t<0)) :}

$$\:{find}\:{the}\:{laplace}\:{transform}\:{of} \\ $$$${f}\left({t}\right)=\:{t}^{\mathrm{2}} \:{cos}\left(\mathrm{2}{t}\right)\:{u}\left({t}\right) \\ $$$${u}\left({t}\right)\:{is}\:{unit}\:{step}\:{function}\: \\ $$$${u}\left({t}\right)=\begin{cases}{\mathrm{1}\:\:\:\:\:\:\:{t}\geqslant\mathrm{0}}\\{\mathrm{0}\:\:\:\:\:\:{t}<\mathrm{0}}\end{cases} \\ $$$$ \\ $$

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