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Question Number 186849 Answers: 0 Comments: 1
Question Number 186841 Answers: 0 Comments: 0
Question Number 186840 Answers: 1 Comments: 0
$$\:\:\underset{\mathrm{9}} {\overset{\:\mathrm{16}} {\int}}\:\frac{\sqrt{\mathrm{4}−\sqrt{{x}}}}{{x}}\:{dx}\:=? \\ $$
Question Number 186838 Answers: 3 Comments: 0
Question Number 186837 Answers: 0 Comments: 0
Question Number 186835 Answers: 0 Comments: 1
Question Number 186833 Answers: 1 Comments: 1
Question Number 186830 Answers: 1 Comments: 1
Question Number 186821 Answers: 1 Comments: 0
Question Number 188822 Answers: 1 Comments: 3
$${is}\:{it}\:{a}\:{polynomial}? \\ $$$${p}\left({x}\right)=\mathrm{2}{x}^{\mathrm{2}} +\mathrm{4}{x}^{{x}} −\mathrm{10} \\ $$
Question Number 186809 Answers: 1 Comments: 0
Question Number 186808 Answers: 0 Comments: 0
Question Number 186805 Answers: 1 Comments: 0
Question Number 186803 Answers: 1 Comments: 0
Question Number 186800 Answers: 0 Comments: 0
$$\boldsymbol{\mathrm{show}}\:\boldsymbol{\mathrm{that}} \\ $$$$\int_{\mathrm{0}} ^{\:\infty\:} \frac{\boldsymbol{\mathrm{tan}}^{−\mathrm{1}} \boldsymbol{\alpha{x}}\:\boldsymbol{\mathrm{tan}}^{−\mathrm{1}} \boldsymbol{\beta{x}}}{\boldsymbol{{x}}^{\mathrm{2}} }\boldsymbol{{dx}}\:=\:\frac{\boldsymbol{\pi}}{\mathrm{2}}\mathrm{log}\left\{\frac{\left(\boldsymbol{\alpha}+\boldsymbol{\beta}\right)^{\boldsymbol{\alpha}+\boldsymbol{\beta}} }{\boldsymbol{\alpha}^{\boldsymbol{\alpha}} \boldsymbol{\beta}^{\boldsymbol{\beta}} }\right\}\: \\ $$
Question Number 186790 Answers: 0 Comments: 0
$${Solve}\:{using}\:{Fourier}'{s}\:{series}: \\ $$$${x}^{\mathrm{2}} \left(\mathrm{1}−{x}\right){y}''−{x}\left(\mathrm{1}+{x}\right){y}'+{y}=\mathrm{0} \\ $$
Question Number 186788 Answers: 1 Comments: 0
Question Number 186787 Answers: 0 Comments: 0
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Question Number 186784 Answers: 1 Comments: 0
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Question Number 186772 Answers: 0 Comments: 0
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Question Number 186771 Answers: 2 Comments: 0
$$ \\ $$$$\:\:\:\:\mathrm{Q}\::\:\:\:\:\mathrm{Find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{the}\:\mathrm{following}\:\mathrm{integral}.\:\:\:\:\:\:\: \\ $$$$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{I}\:=\:\int_{\mathrm{0}} ^{\:\frac{\:\pi}{\:\mathrm{2}}} \:\frac{\:\:\mathrm{1}}{\:\mathrm{1}\:+\:\mathrm{sin}^{\:\mathrm{4}} \:\left(\:{x}\:\right)\:+\:\mathrm{cos}^{\:\mathrm{4}} \:\left(\:{x}\:\right)\:}\:\mathrm{d}{x}\:=\:\:?\:\:\:\:\:\:\:\:\: \\ $$$$ \\ $$
Question Number 186780 Answers: 1 Comments: 0
$$ \\ $$$$\:\:\:\:\:\:\:\int\:\:\:\frac{\mathrm{1}\:+\:\boldsymbol{{sin}}\:\boldsymbol{{x}}\:+\:\boldsymbol{{cos}}\:\boldsymbol{{x}}}{\mathrm{1}\:+\:\boldsymbol{{sin}}\:\boldsymbol{{x}}}\:\:\boldsymbol{{dx}}\:\: \\ $$$$ \\ $$
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