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Question Number 187835 Answers: 5 Comments: 1

Question Number 187830 Answers: 1 Comments: 1

Question Number 187953 Answers: 2 Comments: 0

Question Number 187951 Answers: 3 Comments: 0

please help me to solve 6x^2 +x−2=0

$${please}\:{help}\:{me}\:{to}\:{solve} \\ $$$$\mathrm{6}{x}^{\mathrm{2}} +{x}−\mathrm{2}=\mathrm{0} \\ $$

Question Number 187811 Answers: 1 Comments: 0

Question Number 187810 Answers: 1 Comments: 2

Question Number 187828 Answers: 1 Comments: 0

Question Number 187827 Answers: 2 Comments: 0

Question Number 187826 Answers: 0 Comments: 0

Question Number 187819 Answers: 1 Comments: 0

Question Number 187818 Answers: 1 Comments: 0

1. lim_(x→0) (√x)=? 2. lim_(x→2) (√(x−2))=? solution please

$$\mathrm{1}.\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\sqrt{\mathrm{x}}=? \\ $$$$\mathrm{2}.\:\underset{{x}\rightarrow\mathrm{2}} {\mathrm{lim}}\sqrt{\mathrm{x}−\mathrm{2}}=? \\ $$$$\mathrm{solution}\:\mathrm{please} \\ $$

Question Number 187817 Answers: 2 Comments: 0

Question Number 187808 Answers: 1 Comments: 0

Question Number 188234 Answers: 0 Comments: 0

Question Number 187804 Answers: 0 Comments: 0

Question Number 187790 Answers: 2 Comments: 0

Question Number 187789 Answers: 1 Comments: 0

Question Number 187780 Answers: 1 Comments: 0

solve ⌊ (1/(4 )) + 2^( x) ⌋ + ⌊ (1/2) + 2^( x+1) ⌋=1

$$ \\ $$$$\:\:{solve} \\ $$$$\:\:\:\:\lfloor\:\:\frac{\mathrm{1}}{\mathrm{4}\:}\:+\:\mathrm{2}^{\:{x}} \:\rfloor\:+\:\lfloor\:\frac{\mathrm{1}}{\mathrm{2}}\:+\:\mathrm{2}^{\:{x}+\mathrm{1}} \:\rfloor=\mathrm{1} \\ $$$$ \\ $$

Question Number 187776 Answers: 2 Comments: 0

Question Number 187774 Answers: 2 Comments: 0

Question Number 187765 Answers: 3 Comments: 0

Question Number 187762 Answers: 0 Comments: 0

if point P is any point inside △ABC with side lenghts a,b and c. prove that; ((PA)/a) + ((PB)/b) + ((PC)/c) ≥ (√(3 ))

$$ \\ $$$$\:\:\:\:\:\:\boldsymbol{{if}}\:\boldsymbol{{point}}\:\boldsymbol{{P}}\:\:\boldsymbol{{is}}\:\boldsymbol{{any}}\:\boldsymbol{{point}}\:\boldsymbol{{inside}}\:\:\: \\ $$$$\:\:\:\:\:\:\:\bigtriangleup\boldsymbol{{ABC}}\:\:\boldsymbol{{with}}\:\boldsymbol{{side}}\:\boldsymbol{{lenghts}}\:\boldsymbol{{a}},\boldsymbol{{b}}\:\boldsymbol{{and}}\:\boldsymbol{{c}}.\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\boldsymbol{{prove}}\:\boldsymbol{{that}}; \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\frac{\boldsymbol{{PA}}}{\boldsymbol{{a}}}\:+\:\frac{\boldsymbol{{PB}}}{\boldsymbol{{b}}}\:+\:\frac{\boldsymbol{{PC}}}{\boldsymbol{{c}}}\:\geqslant\:\sqrt{\mathrm{3}\:} \\ $$$$ \\ $$

Question Number 187760 Answers: 1 Comments: 2

Question Number 187754 Answers: 1 Comments: 0

Question Number 187752 Answers: 0 Comments: 5

Question Number 187759 Answers: 0 Comments: 0

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