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Question Number 188730    Answers: 2   Comments: 2

let p(x) = (5/3)−6x−9x^2 and Q(y) = −4y^2 −4y+((13)/2) if there exist unique pair of real number (x,y) such that p(x)×Q(y) = 20 then find the value 6x+10y = ?

$$\:\:\mathrm{let}\:{p}\left({x}\right)\:=\:\frac{\mathrm{5}}{\mathrm{3}}−\mathrm{6}{x}−\mathrm{9}{x}^{\mathrm{2}} \:\mathrm{and}\:{Q}\left({y}\right)\:=\:−\mathrm{4}{y}^{\mathrm{2}} −\mathrm{4}{y}+\frac{\mathrm{13}}{\mathrm{2}} \\ $$$$\mathrm{if}\:\mathrm{there}\:\mathrm{exist}\:\mathrm{unique}\:\mathrm{pair}\:\mathrm{of}\:\mathrm{real}\:\mathrm{number} \\ $$$$\:\left({x},{y}\right)\:\mathrm{such}\:\mathrm{that}\:{p}\left({x}\right)×{Q}\left({y}\right)\:=\:\mathrm{20}\:\mathrm{then} \\ $$$$\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{6}{x}+\mathrm{10}{y}\:=\:? \\ $$

Question Number 188726    Answers: 0   Comments: 2

Question Number 188725    Answers: 1   Comments: 0

tan193=k cos167=?

$$\mathrm{tan193}=\mathrm{k} \\ $$$$\mathrm{cos167}=? \\ $$

Question Number 188722    Answers: 1   Comments: 1

Question Number 188721    Answers: 1   Comments: 0

Question Number 188720    Answers: 1   Comments: 2

Question Number 188717    Answers: 0   Comments: 0

Question Number 188704    Answers: 1   Comments: 0

Question Number 188701    Answers: 2   Comments: 2

Question Number 188700    Answers: 0   Comments: 2

is it a polynomial f(x)=2sinx+10?

$${is}\:{it}\:{a}\:{polynomial}\:{f}\left({x}\right)=\mathrm{2}{sinx}+\mathrm{10}? \\ $$

Question Number 188699    Answers: 1   Comments: 0

lim_(x→∞) (sec^2 x−sec x tan x )=?

$$\:\:\:\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\left(\mathrm{sec}\:^{\mathrm{2}} \mathrm{x}−\mathrm{sec}\:\mathrm{x}\:\mathrm{tan}\:\mathrm{x}\:\right)=? \\ $$

Question Number 188669    Answers: 4   Comments: 0

Question Number 188660    Answers: 2   Comments: 0

solve x^4 +4x=1

$${solve}\:{x}^{\mathrm{4}} +\mathrm{4}{x}=\mathrm{1} \\ $$

Question Number 188657    Answers: 3   Comments: 0

Question Number 188653    Answers: 0   Comments: 1

In how many different ways can the letters of the word ABRAKADABRA be arranged?

$$\mathrm{In}\:\mathrm{how}\:\mathrm{many}\:\mathrm{different}\:\mathrm{ways}\:\mathrm{can}\:\mathrm{the} \\ $$$$\mathrm{letters}\:\mathrm{of}\:\mathrm{the}\:\mathrm{word}\:\mathrm{ABRAKADABRA} \\ $$$$\mathrm{be}\:\mathrm{arranged}? \\ $$

Question Number 188651    Answers: 1   Comments: 0

Given f(x)=x^5 +ax^4 +bx^3 +cx^2 +dx+c and f(1)=f(2)=f(3)=f(4)=f(5). Find a.

$$\:\:\mathrm{Given}\:\mathrm{f}\left(\mathrm{x}\right)=\mathrm{x}^{\mathrm{5}} +\mathrm{ax}^{\mathrm{4}} +\mathrm{bx}^{\mathrm{3}} +\mathrm{cx}^{\mathrm{2}} +\mathrm{dx}+\mathrm{c} \\ $$$$\:\mathrm{and}\:\mathrm{f}\left(\mathrm{1}\right)=\mathrm{f}\left(\mathrm{2}\right)=\mathrm{f}\left(\mathrm{3}\right)=\mathrm{f}\left(\mathrm{4}\right)=\mathrm{f}\left(\mathrm{5}\right). \\ $$$$\:\mathrm{Find}\:\mathrm{a}. \\ $$

Question Number 188648    Answers: 1   Comments: 0

Question Number 188647    Answers: 0   Comments: 1

Question Number 188646    Answers: 2   Comments: 0

Question Number 188645    Answers: 1   Comments: 0

Question Number 188642    Answers: 0   Comments: 0

Question Number 188635    Answers: 1   Comments: 0

Question Number 188625    Answers: 1   Comments: 0

Question Number 188623    Answers: 1   Comments: 4

Question Number 188621    Answers: 2   Comments: 0

Question Number 188619    Answers: 0   Comments: 1

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