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Question Number 189302 Answers: 1 Comments: 2

Q: find the number of the solutions for : ( x_( 1) + x_( 2) )^( 3) + x_( 3) + x_( 4) + x_( 5) =11 Hint: ( x_( i) ∈ Z^( +) ∪ { 0 } )

$$ \\ $$$$\:\:\:\:{Q}:\:\:\:\:\mathrm{find}\:\mathrm{the}\:\mathrm{number}\:\mathrm{of}\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{the}\:\:\mathrm{solutions}\:\:\mathrm{for}\:: \\ $$$$ \\ $$$$\:\:\left(\:{x}_{\:\mathrm{1}} \:+\:{x}_{\:\mathrm{2}} \:\right)^{\:\mathrm{3}} \:+\:{x}_{\:\mathrm{3}} \:+\:{x}_{\:\mathrm{4}} \:+\:{x}_{\:\mathrm{5}} \:=\mathrm{11} \\ $$$$\:\:\: \\ $$$$\:\:\:\:{Hint}:\:\:\:\left(\:{x}_{\:{i}} \:\:\in\:\:\mathbb{Z}^{\:\:+} \:\:\cup\:\left\{\:\mathrm{0}\:\right\}\:\:\right) \\ $$$$\: \\ $$

Question Number 189293 Answers: 1 Comments: 0

Question Number 189292 Answers: 0 Comments: 2

Question Number 189291 Answers: 0 Comments: 0

Question Number 189290 Answers: 1 Comments: 0

Question Number 189285 Answers: 2 Comments: 0

f(x) is continous function on R and lim_(x→1) ((f(((x+1)/x))−6)/((((x−1)/x))^2 ))=2 Evalute : lim_(x→1) (((√(f(x)+x))−x)/((x−1)))=¿

$${f}\left({x}\right)\:{is}\:{continous}\:{function}\:{on}\:{R} \\ $$$${and}\:\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\frac{{f}\left(\frac{{x}+\mathrm{1}}{{x}}\right)−\mathrm{6}}{\left(\frac{{x}−\mathrm{1}}{{x}}\right)^{\mathrm{2}} }=\mathrm{2} \\ $$$${Evalute}\::\:\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\frac{\sqrt{{f}\left({x}\right)+{x}}−{x}}{\left({x}−\mathrm{1}\right)}=¿ \\ $$

Question Number 189270 Answers: 2 Comments: 1

Question Number 189269 Answers: 1 Comments: 0

Question Number 189267 Answers: 3 Comments: 1

Question Number 189266 Answers: 1 Comments: 0

∫_0 ^(π/2) (((tan x))^(1/3) /(1+sin 2x)) dx =?

$$\:\:\underset{\mathrm{0}} {\overset{\pi/\mathrm{2}} {\int}}\:\frac{\sqrt[{\mathrm{3}}]{\mathrm{tan}\:\mathrm{x}}}{\mathrm{1}+\mathrm{sin}\:\mathrm{2x}}\:\mathrm{dx}\:=? \\ $$

Question Number 189263 Answers: 0 Comments: 1

evaluate ∫∫_E ∫15Zdv, where E is the region between 2x+y+z=4 and 4x+4y+2z=20 which is in front of the region in the yz plane bounded by z=2y^2 and z=(√(4y))

$$\boldsymbol{{evaluate}}\:\int\int_{\boldsymbol{\mathrm{E}}} \int\mathrm{15}{Zdv},\:{where}\:{E} \\ $$$$\:{is}\:{the}\:{region}\:{between}\:\mathrm{2}{x}+{y}+{z}=\mathrm{4} \\ $$$$\:{and}\:\mathrm{4}{x}+\mathrm{4}{y}+\mathrm{2}{z}=\mathrm{20}\:{which}\:{is}\:{in}\: \\ $$$${front}\:{of}\:{the}\:{region}\:{in}\:{the}\:{yz}\:{plane}\: \\ $$$${bounded}\:{by}\:{z}=\mathrm{2}{y}^{\mathrm{2}} \:{and}\:{z}=\sqrt{\mathrm{4}{y}} \\ $$

Question Number 189257 Answers: 1 Comments: 0

determine the surface area of the portion of z=13−4x^2 −4y^2 that is above z=1 with x≤0 and y≥0

Question Number 189256 Answers: 1 Comments: 0

Prove that sin10° = (1/2)(√(2−(√(2+(√(2+(√(2−(√(2+(√(2+(√(2−(√(2+(√(2+(√(2−(√(2+(√(2+(√(2−...........∞))))))))))))))))))))))))))

$${Prove}\:{that} \\ $$$$\mathrm{sin10}°\:=\:\frac{\mathrm{1}}{\mathrm{2}}\sqrt{\mathrm{2}−\sqrt{\mathrm{2}+\sqrt{\mathrm{2}+\sqrt{\mathrm{2}−\sqrt{\mathrm{2}+\sqrt{\mathrm{2}+\sqrt{\mathrm{2}−\sqrt{\mathrm{2}+\sqrt{\mathrm{2}+\sqrt{\mathrm{2}−\sqrt{\mathrm{2}+\sqrt{\mathrm{2}+\sqrt{\mathrm{2}−...........\infty}}}}}}}}}}}}} \\ $$

Question Number 189254 Answers: 1 Comments: 0

Question Number 189250 Answers: 0 Comments: 1

Question Number 189248 Answers: 2 Comments: 0

Question Number 189242 Answers: 0 Comments: 0

Question Number 189233 Answers: 1 Comments: 2

1•Evaluer :Aire(A′B′C′D′) 2•En deduire:((Aire(A′B′C′D′))/(Aire(ABCD)))

$$\mathrm{1}\bullet{Evaluer}\::\boldsymbol{{Aire}}\left(\boldsymbol{{A}}'\boldsymbol{{B}}'\boldsymbol{{C}}'\boldsymbol{{D}}'\right) \\ $$$$\mathrm{2}\bullet{En}\:{deduire}:\frac{\boldsymbol{{Aire}}\left(\boldsymbol{{A}}'\boldsymbol{{B}}'\boldsymbol{{C}}'\boldsymbol{{D}}'\right)}{\boldsymbol{{Aire}}\left(\boldsymbol{{ABCD}}\right)} \\ $$

Question Number 189223 Answers: 0 Comments: 2

who did discoer the light′s speed and by which method?

$${who}\:{did}\:{discoer}\:{the}\:{light}'{s}\:{speed}\:{and} \\ $$$${by}\:{which}\:{method}? \\ $$

Question Number 189212 Answers: 0 Comments: 0

Question Number 189208 Answers: 2 Comments: 0

Question Number 189468 Answers: 2 Comments: 4

If tan ((x/2))= csc x−sin x , then tan^2 ((x/2))=?

$$\:\:\:\mathrm{If}\:\mathrm{tan}\:\left(\frac{\mathrm{x}}{\mathrm{2}}\right)=\:\mathrm{csc}\:\mathrm{x}−\mathrm{sin}\:\mathrm{x}\:,\:\mathrm{then} \\ $$$$\:\:\mathrm{tan}\:^{\mathrm{2}} \left(\frac{\mathrm{x}}{\mathrm{2}}\right)=? \\ $$

Question Number 189465 Answers: 1 Comments: 0

Question Number 189464 Answers: 1 Comments: 0

Question Number 189201 Answers: 1 Comments: 0

In △ABC holds: (√2) a cos (B/2) cos (C/2) = s ⇒ sec (2B) + tan (2B) = ((c + b)/(c − b))

$$\mathrm{In}\:\:\:\bigtriangleup\mathrm{ABC}\:\:\:\mathrm{holds}: \\ $$$$\sqrt{\mathrm{2}}\:\mathrm{a}\:\mathrm{cos}\:\frac{\mathrm{B}}{\mathrm{2}}\:\mathrm{cos}\:\frac{\mathrm{C}}{\mathrm{2}}\:=\:\mathrm{s} \\ $$$$\Rightarrow\:\mathrm{sec}\:\left(\mathrm{2B}\right)\:+\:\mathrm{tan}\:\left(\mathrm{2B}\right)\:=\:\frac{\mathrm{c}\:+\:\mathrm{b}}{\mathrm{c}\:−\:\mathrm{b}} \\ $$

Question Number 189189 Answers: 1 Comments: 0

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