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Question Number 190005 Answers: 0 Comments: 0

Question Number 189998 Answers: 2 Comments: 0

tanA=(1/(n+1)) tanB=(n/(2n+1)) ⇒ A+B=?

$$\mathrm{tanA}=\frac{\mathrm{1}}{\mathrm{n}+\mathrm{1}} \\ $$$$\mathrm{tanB}=\frac{\mathrm{n}}{\mathrm{2n}+\mathrm{1}} \\ $$$$\Rightarrow\:\mathrm{A}+\mathrm{B}=?\: \\ $$

Question Number 189989 Answers: 1 Comments: 0

Question Number 189986 Answers: 1 Comments: 0

Question Number 189984 Answers: 0 Comments: 0

Question Number 189980 Answers: 1 Comments: 0

Question Number 189977 Answers: 1 Comments: 0

Question Number 189976 Answers: 2 Comments: 0

Question Number 189975 Answers: 1 Comments: 0

Question Number 189973 Answers: 3 Comments: 4

Question Number 189971 Answers: 1 Comments: 0

Question Number 189970 Answers: 1 Comments: 0

Question Number 189965 Answers: 3 Comments: 0

Question Number 190021 Answers: 0 Comments: 0

Find: lim_(n→∞) H_n (Σ_(k=1) ^n (1/(n+k)) -Σ_(k=1) ^n cot^(-1) (n+k))

$$\mathrm{Find}: \\ $$$$\underset{\boldsymbol{\mathrm{n}}\rightarrow\infty} {\mathrm{lim}}\:\mathrm{H}_{\boldsymbol{\mathrm{n}}} \:\left(\underset{\boldsymbol{\mathrm{k}}=\mathrm{1}} {\overset{\boldsymbol{\mathrm{n}}} {\sum}}\:\frac{\mathrm{1}}{\mathrm{n}+\mathrm{k}}\:-\underset{\boldsymbol{\mathrm{k}}=\mathrm{1}} {\overset{\boldsymbol{\mathrm{n}}} {\sum}}\:\mathrm{cot}^{-\mathrm{1}} \:\left(\mathrm{n}+\mathrm{k}\right)\right) \\ $$

Question Number 190019 Answers: 1 Comments: 3

Question Number 189952 Answers: 2 Comments: 0

(√2) sin(x) +cos(x)= −(√2)

$$\sqrt{\mathrm{2}}\:\mathrm{sin}\left(\mathrm{x}\right)\:+\mathrm{cos}\left(\mathrm{x}\right)=\:−\sqrt{\mathrm{2}}\: \\ $$

Question Number 189949 Answers: 1 Comments: 0

Question Number 189942 Answers: 1 Comments: 0

Question Number 189941 Answers: 2 Comments: 0

Question Number 189940 Answers: 0 Comments: 0

Question Number 189937 Answers: 0 Comments: 0

Question Number 189932 Answers: 0 Comments: 0

Question Number 189925 Answers: 2 Comments: 1

Question Number 189923 Answers: 1 Comments: 0

∫(dx/(a + btanx))

$$\int\frac{{dx}}{{a}\:+\:{btanx}} \\ $$

Question Number 189921 Answers: 2 Comments: 2

Question Number 189919 Answers: 1 Comments: 0

If x,y are real numbers satisfy ((x+40)/y)+((569)/(xy))=((26−y)/x) , then xy=?

$$\:{If}\:{x},{y}\:{are}\:{real}\:{numbers}\:{satisfy} \\ $$$$\:\frac{{x}+\mathrm{40}}{{y}}+\frac{\mathrm{569}}{{xy}}=\frac{\mathrm{26}−{y}}{{x}}\:,\:{then}\:{xy}=? \\ $$

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