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Question Number 178173    Answers: 2   Comments: 0

Question Number 178166    Answers: 1   Comments: 0

8.5g of hydrated copper (ii) sulphate CuSO_4 .xH_2 O was heated to dryness.if 4.0g of anhydrous copper (ii) sulphate[CuSO_4 ] obtain Find number of molecule of water of crystallization

$$\mathrm{8}.\mathrm{5g}\:\mathrm{of}\:\mathrm{hydrated}\:\mathrm{copper}\:\left(\mathrm{ii}\right) \\ $$$$\mathrm{sulphate}\:\mathrm{CuSO}_{\mathrm{4}} .\mathrm{xH}_{\mathrm{2}} \mathrm{O}\:\mathrm{was}\:\mathrm{heated} \\ $$$$\mathrm{to}\:\mathrm{dryness}.\mathrm{if}\:\:\mathrm{4}.\mathrm{0g}\:\mathrm{of}\:\mathrm{anhydrous} \\ $$$$\mathrm{copper}\:\left(\mathrm{ii}\right)\:\mathrm{sulphate}\left[\mathrm{CuSO}_{\mathrm{4}} \right]\:\mathrm{obtain} \\ $$$$\mathrm{Find}\:\mathrm{number}\:\mathrm{of}\:\mathrm{molecule}\:\mathrm{of}\:\mathrm{water}\:\mathrm{of} \\ $$$$\mathrm{crystallization} \\ $$

Question Number 178165    Answers: 2   Comments: 0

2.86g of hydrated Sodium carbonate Na_2 CO_3 .nH_2 O was dissolved into water to make 250cm^3 solution of 0.04M Find the value of n

$$\mathrm{2}.\mathrm{86g}\:\mathrm{of}\:\mathrm{hydrated}\:\mathrm{Sodium}\:\mathrm{carbonate} \\ $$$$\boldsymbol{\mathrm{Na}}_{\mathrm{2}} \boldsymbol{\mathrm{CO}}_{\mathrm{3}} .\boldsymbol{\mathrm{nH}}_{\mathrm{2}} \boldsymbol{\mathrm{O}}\:\mathrm{was}\:\mathrm{dissolved} \\ $$$$\mathrm{into}\:\mathrm{water}\:\mathrm{to}\:\mathrm{make}\:\mathrm{250cm}^{\mathrm{3}} \:\mathrm{solution} \\ $$$$\mathrm{of}\:\:\mathrm{0}.\mathrm{04M}\:\mathrm{Find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{n} \\ $$

Question Number 178161    Answers: 3   Comments: 1

Question Number 178153    Answers: 1   Comments: 0

Question Number 178152    Answers: 0   Comments: 0

Question Number 178137    Answers: 1   Comments: 2

Let f(x)= (ax+1)^5 .(1+bx)^4 ; a,b ∈ N if times of x equal 62 so what are possible values of the sum a, b?

$${Let}\:{f}\left({x}\right)=\:\left({ax}+\mathrm{1}\right)^{\mathrm{5}} .\left(\mathrm{1}+{bx}\right)^{\mathrm{4}} \:;\:{a},{b}\:\in\:\mathbb{N} \\ $$$$\:{if}\:{times}\:{of}\:{x}\:{equal}\:\mathrm{62}\:{so}\:{what}\:{are}\:{possible}\:{values} \\ $$$$\:{of}\:{the}\:{sum}\:{a},\:{b}? \\ $$$$ \\ $$

Question Number 178136    Answers: 0   Comments: 0

Journey inside a regular hexagon The operation is to connect three dots of a regular hexagon′s heads. 1• How many types of geometric shapes will we get? 2• How many each type?

$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\boldsymbol{{Journey}}\:\boldsymbol{{inside}}\:\boldsymbol{{a}}\:\boldsymbol{{regular}}\:\boldsymbol{{hexagon}} \\ $$$$\:{The}\:{operation}\:{is}\:{to}\:{connect}\:{three}\:{dots}\:{of} \\ $$$$\:{a}\:{regular}\:{hexagon}'{s}\:{heads}. \\ $$$$\mathrm{1}\bullet\:{How}\:{many}\:{types}\:{of}\:{geometric}\:{shapes}\:{will}\:{we}\:{get}? \\ $$$$\mathrm{2}\bullet\:{How}\:{many}\:{each}\:{type}? \\ $$$$ \\ $$

Question Number 178134    Answers: 0   Comments: 8

Am not a friend with this isssue: 6 red, 1 black and 3 white balls We draw 3 balls in a raw, returning the drawn ball each time. How many different results which include at least one black ball. Way_1 : 1000−9^3 = 271 results That′s very ok Way_2 : 1×9×9_(very ok) ×3_(Omg, Why?) + 1×1×9×3_(the same confused above) + 1×1×1_(very ok and i like it.... but why not ×3) = 271 result Explanation_(about the story of ×3) ?

$${Am}\:{not}\:{a}\:{friend}\:{with}\:{this}\:{isssue}: \\ $$$$\mathrm{6}\:{red},\:\mathrm{1}\:{black}\:{and}\:\mathrm{3}\:{white}\:{balls} \\ $$$${We}\:{draw}\:\mathrm{3}\:{balls}\:{in}\:{a}\:{raw},\:{returning}\:{the} \\ $$$$\:{drawn}\:{ball}\:{each}\:{time}. \\ $$$${How}\:{many}\:{different}\:{results}\:{which}\:{include} \\ $$$$\:\boldsymbol{{at}}\:\boldsymbol{{least}}\:{one}\:{black}\:{ball}. \\ $$$$ \\ $$$$\:{Way}_{\mathrm{1}} :\:\mathrm{1000}−\mathrm{9}^{\mathrm{3}} =\:\mathrm{271}\:{results}\:{That}'{s}\:{very}\:{ok} \\ $$$$ \\ $$$$\:{Way}_{\mathrm{2}} :\:\mathrm{1}×\mathrm{9}×\mathrm{9}_{{very}\:{ok}} ×\mathrm{3}_{\boldsymbol{{Omg}},\:\boldsymbol{{Why}}?} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:+\:\mathrm{1}×\mathrm{1}×\mathrm{9}×\mathrm{3}_{{the}\:{same}\:{confused}\:{above}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:+\:\mathrm{1}×\mathrm{1}×\mathrm{1}_{{very}\:{ok}\:{and}\:{i}\:{like}\:{it}....\:{but}\:{why}\:{not}\:×\mathrm{3}} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\:\mathrm{271}\:{result} \\ $$$$ \\ $$$$\:{Explanation}_{{about}\:{the}\:{story}\:{of}\:×\mathrm{3}} ? \\ $$$$ \\ $$

Question Number 178131    Answers: 1   Comments: 2

Question Number 178115    Answers: 2   Comments: 0

(n/(390)) is a prime number less than 12 and one of the prime factor of n is not a prime factor of 390. Qty A: n Qty B: 3000

$$\frac{{n}}{\mathrm{390}}\:{is}\:{a}\:{prime}\:{number}\:{less}\:{than}\:\mathrm{12}\:{and}\: \\ $$$${one}\:{of}\:{the}\:{prime}\:{factor}\:{of}\:\:{n}\:{is}\:{not}\: \\ $$$${a}\:{prime}\:{factor}\:{of}\:\mathrm{390}. \\ $$$${Qty}\:{A}:\:{n} \\ $$$${Qty}\:{B}:\:\mathrm{3000} \\ $$

Question Number 178103    Answers: 0   Comments: 1

A sample of 18 integers has an average (arithemetic mean) equal to M and standard deviation equal to S. Two of the integers are equal to m. Quantity A: The standard devuaition of the 16 integers that are not equal to m. Quantity B: S

$${A}\:{sample}\:{of}\:\mathrm{18}\:{integers}\:{has}\:{an}\:{average}\: \\ $$$$\left({arithemetic}\:{mean}\right)\:{equal}\:{to}\:{M}\:{and}\:{standard} \\ $$$${deviation}\:{equal}\:{to}\:{S}.\:{Two}\:{of}\:{the}\:{integers} \\ $$$${are}\:{equal}\:{to}\:{m}. \\ $$$${Quantity}\:{A}:\:{The}\:{standard}\:{devuaition}\:{of} \\ $$$${the}\:\mathrm{16}\:{integers}\:{that}\:{are}\:{not}\:{equal}\:{to}\:{m}. \\ $$$${Quantity}\:{B}:\:{S} \\ $$

Question Number 178102    Answers: 0   Comments: 2

I am really learning here. I am studying for GRE

$${I}\:{am}\:{really}\:{learning}\:{here}.\:{I}\:{am}\:{studying} \\ $$$${for}\:{GRE} \\ $$

Question Number 178101    Answers: 0   Comments: 0

x and s are positive Quantity A: the amount of money invested for one year at x/2 percent simple interest that will earn 2x dollars in interest in that year. Quantity B: the amount of money invested for one year at x percent simple annual interest that will earn s dollars in interest in that year.

$${x}\:{and}\:{s}\:{are}\:{positive} \\ $$$${Quantity}\:{A}:\:{the}\:{amount}\:{of}\:{money}\:{invested} \\ $$$${for}\:{one}\:{year}\:{at}\:{x}/\mathrm{2}\:{percent}\:{simple}\:{interest} \\ $$$${that}\:{will}\:{earn}\:\mathrm{2}{x}\:{dollars}\:{in}\:{interest}\:{in}\:{that} \\ $$$${year}. \\ $$$${Quantity}\:{B}:\:{the}\:{amount}\:{of}\:{money}\:{invested} \\ $$$${for}\:{one}\:{year}\:{at}\:{x}\:{percent}\:{simple}\:{annual} \\ $$$${interest}\:{that}\:{will}\:{earn}\:{s}\:{dollars}\:{in}\:{interest} \\ $$$${in}\:{that}\:{year}. \\ $$$$ \\ $$$$ \\ $$

Question Number 181541    Answers: 4   Comments: 2

solve for f(x) such that f′(x)=f^(−1) (x)

$${solve}\:{for}\:{f}\left({x}\right)\:{such}\:{that} \\ $$$$\mathrm{f}'\left(\mathrm{x}\right)=\mathrm{f}^{−\mathrm{1}} \left(\mathrm{x}\right) \\ $$

Question Number 181540    Answers: 0   Comments: 0

Question Number 181602    Answers: 2   Comments: 0

if lim_(x→1) (((√(ax+b))−4)/((x−1)))=5 find a,b

$${if}\: \\ $$$$\underset{{x}\rightarrow\mathrm{1}} {{lim}}\frac{\sqrt{{ax}+{b}}−\mathrm{4}}{\left({x}−\mathrm{1}\right)}=\mathrm{5}\:\:\:\:{find}\:{a},{b} \\ $$

Question Number 178091    Answers: 0   Comments: 0

remainder when 7^9^9^9^9 is divided by 10

$${remainder}\:{when}\:\mathrm{7}^{\mathrm{9}^{\mathrm{9}^{\mathrm{9}^{\mathrm{9}} } } } \:{is}\:{divided}\:{by}\:\mathrm{10}\: \\ $$

Question Number 178087    Answers: 0   Comments: 1

un avion volant a hauteur h=4km du sol a vitesse supersonic (v) sachant que la vitesse du son a la hauteur h est de 300m/s et que le temps mis par le son emis par l avion depuis un point(c) est cspte par une prrsonne avec un retard de 3s −Determiner la vitesse( v)de l′ avion?

$${un}\:{avion}\:{volant}\:{a}\:{hauteur}\:{h}=\mathrm{4}{km}\:{du}\:{sol} \\ $$$${a}\:{vitesse}\:{supersonic}\:\:\left({v}\right)\: \\ $$$${sachant}\:{que}\:{la}\:{vitesse}\:{du}\:{son}\:{a}\:{la}\: \\ $$$${hauteur}\:{h}\:{est}\:{de}\:\mathrm{300}{m}/{s}\:{et} \\ $$$${que}\:{le}\:{temps}\:{mis}\:{par}\:{le}\:{son}\:{emis}\:{par} \\ $$$${l}\:{avion}\:{depuis}\:{un}\:{point}\left({c}\right)\:{est}\: \\ $$$${cspte}\:{par}\:{une}\:{prrsonne}\:{avec}\:{un} \\ $$$${retard}\:{de}\:\mathrm{3}{s} \\ $$$$−{Determiner}\:{la}\:{vitesse}\left(\:{v}\right){de}\:{l}'\:{avion}? \\ $$$$ \\ $$

Question Number 178114    Answers: 1   Comments: 1

n is an integer greater than 1. Quantity A: the number of positive divisor of 2n. Quantity B: twice the number of positive divisors of n

$${n}\:{is}\:{an}\:{integer}\:{greater}\:{than}\:\mathrm{1}. \\ $$$${Quantity}\:{A}:\:{the}\:{number}\:{of}\:{positive}\:{divisor} \\ $$$${of}\:\mathrm{2}{n}. \\ $$$${Quantity}\:{B}:\:{twice}\:{the}\:{number}\:{of}\:{positive} \\ $$$${divisors}\:{of}\:{n} \\ $$

Question Number 178113    Answers: 1   Comments: 0

8 yellow, 8 red, 8 green and 8 blue cards, each grouo is numbered from 1 to 8 . We want to know how many pulls contain at least one card with number 1 through pull processes 5 cards each time

$$\:\mathrm{8}\:{yellow},\:\mathrm{8}\:{red},\:\mathrm{8}\:{green}\:{and}\:\mathrm{8}\:{blue}\:{cards},\: \\ $$$${each}\:{grouo}\:{is}\:{numbered}\:{from}\:\mathrm{1}\:{to}\:\mathrm{8}\:. \\ $$$$\:{We}\:{want}\:{to}\:{know}\:{how}\:{many}\:{pulls}\:{contain} \\ $$$$\:{at}\:{least}\:{one}\:{card}\:{with}\:{number}\:\mathrm{1}\:{through} \\ $$$$\:{pull}\:{processes}\:\mathrm{5}\:{cards}\:{each}\:{time} \\ $$$$ \\ $$$$ \\ $$

Question Number 178074    Answers: 0   Comments: 3

question posted by spillover in 12.10.2022

$${question}\:{posted}\:{by}\:{spillover}\:{in} \\ $$$$\mathrm{12}.\mathrm{10}.\mathrm{2022} \\ $$

Question Number 178073    Answers: 1   Comments: 4

Question Number 178067    Answers: 0   Comments: 0

Question Number 178064    Answers: 1   Comments: 0

A group of n people is categorized as follows. 14 people are shorter than 5(1/2) feet 9 people are taller than 6 feet 12 people are under 21 years old. if each person in the group is in at least one of the three categories. then n can be any integer between a. 9 and 14 inclusive b. 12 and 21 inclusive c. 14 and 23 inclusive d. 21 and 26 inclusive e. 23 and 35 inclusive

$${A}\:{group}\:{of}\:{n}\:{people}\:{is}\:{categorized}\:{as}\:{follows}. \\ $$$$\mathrm{14}\:{people}\:{are}\:{shorter}\:{than}\:\mathrm{5}\frac{\mathrm{1}}{\mathrm{2}}\:{feet} \\ $$$$\mathrm{9}\:{people}\:{are}\:{taller}\:{than}\:\mathrm{6}\:{feet} \\ $$$$\mathrm{12}\:{people}\:{are}\:{under}\:\mathrm{21}\:{years}\:{old}. \\ $$$${if}\:{each}\:{person}\:{in}\:{the}\:{group}\:{is}\:{in}\:{at}\:{least} \\ $$$${one}\:{of}\:{the}\:{three}\:{categories}.\:{then}\:{n}\:{can}\:{be} \\ $$$${any}\:{integer}\:{between}\: \\ $$$${a}.\:\mathrm{9}\:{and}\:\mathrm{14}\:{inclusive} \\ $$$${b}.\:\mathrm{12}\:{and}\:\mathrm{21}\:{inclusive} \\ $$$${c}.\:\mathrm{14}\:{and}\:\mathrm{23}\:{inclusive} \\ $$$${d}.\:\mathrm{21}\:{and}\:\mathrm{26}\:{inclusive} \\ $$$${e}.\:\mathrm{23}\:{and}\:\mathrm{35}\:{inclusive} \\ $$$$ \\ $$

Question Number 178058    Answers: 0   Comments: 0

This app will soon be all over everywhere. I am certain. it is greatly helpful.

$${This}\:{app}\:{will}\:{soon}\:{be}\:{all}\:{over}\:{everywhere}. \\ $$$${I}\:{am}\:{certain}.\:{it}\:{is}\:{greatly}\:{helpful}. \\ $$

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