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Question Number 190579 Answers: 1 Comments: 0

Question Number 190578 Answers: 1 Comments: 0

Question Number 190573 Answers: 1 Comments: 3

a^ 2+2ab+b^ 2

$$\hat {{a}}\mathrm{2}+\mathrm{2}{ab}+\hat {{b}}\mathrm{2} \\ $$

Question Number 190568 Answers: 0 Comments: 1

Question Number 190569 Answers: 1 Comments: 0

The number of 4−digit numbers that contain the number 6 and are divisible by 3 is ___

$$\:\mathrm{The}\:\mathrm{number}\:\mathrm{of}\:\mathrm{4}−\mathrm{digit}\: \\ $$$$\:\mathrm{numbers}\:\mathrm{that}\:\mathrm{contain}\:\mathrm{the} \\ $$$$\:\mathrm{number}\:\mathrm{6}\:\mathrm{and}\:\mathrm{are}\:\mathrm{divisible}\: \\ $$$$\:\mathrm{by}\:\mathrm{3}\:\mathrm{is}\:\_\_\_ \\ $$

Question Number 190565 Answers: 1 Comments: 0

Question Number 190564 Answers: 2 Comments: 0

Question Number 190563 Answers: 1 Comments: 0

Question Number 190557 Answers: 2 Comments: 0

Question Number 190552 Answers: 1 Comments: 1

∫_(1/2) ^2 ln(((ln(x+(1/x)))/(ln(x^2 −x+((17)/6)))))dx=?

$$\int_{\frac{\mathrm{1}}{\mathrm{2}}} ^{\mathrm{2}} {ln}\left(\frac{{ln}\left({x}+\frac{\mathrm{1}}{{x}}\right)}{{ln}\left({x}^{\mathrm{2}} −{x}+\frac{\mathrm{17}}{\mathrm{6}}\right)}\right){dx}=? \\ $$

Question Number 190546 Answers: 2 Comments: 0

Given x,y,z>0 and x^2 +y^2 +z^2 +x+2y+3z=23 find maximum of x+y+z.

$$\:\mathrm{Given}\:\mathrm{x},\mathrm{y},\mathrm{z}>\mathrm{0}\:\mathrm{and}\: \\ $$$$\:\mathrm{x}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} +\mathrm{z}^{\mathrm{2}} +\mathrm{x}+\mathrm{2y}+\mathrm{3z}=\mathrm{23}\: \\ $$$$\:\mathrm{find}\:\mathrm{maximum}\:\mathrm{of}\:\mathrm{x}+\mathrm{y}+\mathrm{z}. \\ $$

Question Number 190544 Answers: 1 Comments: 1

Given p,q,r,s sre distinc prime numbers such that pq−rs divisible by 30. minimum value of p+q+r+s =?

$$\mathrm{Given}\:\mathrm{p},\mathrm{q},\mathrm{r},\mathrm{s}\:\mathrm{sre}\:\mathrm{distinc}\:\mathrm{prime}\:\mathrm{numbers} \\ $$$$\:\mathrm{such}\:\mathrm{that}\:\mathrm{pq}−\mathrm{rs}\:\mathrm{divisible}\:\mathrm{by}\:\mathrm{30}. \\ $$$$\:\mathrm{minimum}\:\mathrm{value}\:\mathrm{of}\:\mathrm{p}+\mathrm{q}+\mathrm{r}+\mathrm{s}\:=? \\ $$

Question Number 190542 Answers: 0 Comments: 0

Question Number 190537 Answers: 1 Comments: 0

Question Number 190536 Answers: 1 Comments: 0

If p,q and r are the roots of equation x^3 −3x^2 +1 = 0 then find the value of ((3p−2))^(1/3) +((3q−2))^(1/3) +((3r−2))^(1/3)

$$\:\mathrm{If}\:\mathrm{p},\mathrm{q}\:\mathrm{and}\:\mathrm{r}\:\mathrm{are}\:\mathrm{the}\:\mathrm{roots}\:\mathrm{of}\:\mathrm{equation} \\ $$$$\:\mathrm{x}^{\mathrm{3}} −\mathrm{3x}^{\mathrm{2}} +\mathrm{1}\:=\:\mathrm{0}\:\mathrm{then}\:\mathrm{find}\:\mathrm{the}\:\mathrm{value} \\ $$$$\:\mathrm{of}\:\sqrt[{\mathrm{3}}]{\mathrm{3p}−\mathrm{2}}\:+\sqrt[{\mathrm{3}}]{\mathrm{3q}−\mathrm{2}}+\sqrt[{\mathrm{3}}]{\mathrm{3r}−\mathrm{2}}\: \\ $$

Question Number 190533 Answers: 1 Comments: 0

Question Number 190532 Answers: 1 Comments: 0

10x^2 −9xy+2y^2 =10 please how do I find the ratio of x:y

$$\mathrm{10x}^{\mathrm{2}} −\mathrm{9xy}+\mathrm{2y}^{\mathrm{2}} =\mathrm{10} \\ $$$$\:\mathrm{please}\:\mathrm{how}\:\mathrm{do}\:\mathrm{I}\:\mathrm{find}\:\mathrm{the}\:\mathrm{ratio}\:\mathrm{of} \\ $$$$\:\mathrm{x}:\mathrm{y} \\ $$

Question Number 190527 Answers: 1 Comments: 1

Question Number 190523 Answers: 1 Comments: 0

Question Number 190522 Answers: 1 Comments: 0

Question Number 190521 Answers: 1 Comments: 0

Question Number 190520 Answers: 2 Comments: 0

if a,b and c root of the x^3 −16x^2 −57x+1=0 thi find thd volue of a^(1/5) +b^(1/5) +c^(1/5) =?

$${if}\:{a},{b}\:{and}\:{c}\:{root}\:{of}\:{the} \\ $$$${x}^{\mathrm{3}} −\mathrm{16}{x}^{\mathrm{2}} −\mathrm{57}{x}+\mathrm{1}=\mathrm{0} \\ $$$${thi}\:{find}\:{thd}\:{volue}\:{of} \\ $$$${a}^{\frac{\mathrm{1}}{\mathrm{5}}} +{b}^{\frac{\mathrm{1}}{\mathrm{5}}} +{c}^{\frac{\mathrm{1}}{\mathrm{5}}} =? \\ $$

Question Number 190512 Answers: 1 Comments: 0

Question Number 190508 Answers: 3 Comments: 0

Question Number 190487 Answers: 1 Comments: 0

Question Number 190480 Answers: 1 Comments: 0

Proof that ((√2))^(√2) ∈R\Q

$$\mathrm{Proof}\:\mathrm{that}\:\left(\sqrt{\mathrm{2}}\right)^{\sqrt{\mathrm{2}}} \in\mathbb{R}\backslash\mathrm{Q} \\ $$

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