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Question Number 191062 Answers: 1 Comments: 0

Question Number 191061 Answers: 0 Comments: 0

Question Number 191060 Answers: 1 Comments: 0

Question Number 191057 Answers: 0 Comments: 1

Question Number 191052 Answers: 1 Comments: 0

A particle Q is moving with constant velocity (−5i+3j)m/s. At time t=5sec , Q is at the same point with position vector (−i−5j)m. Find the distance of Q from the origin at time t=2sec

$${A}\:{particle}\:{Q}\:{is}\:{moving}\:{with}\:{constant} \\ $$$${velocity}\:\left(−\mathrm{5}{i}+\mathrm{3}{j}\right){m}/{s}.\:{At}\:{time}\: \\ $$$${t}=\mathrm{5}{sec}\:,\:{Q}\:{is}\:{at}\:{the}\:{same}\:{point}\:{with} \\ $$$${position}\:{vector}\:\left(−{i}−\mathrm{5}{j}\right){m}.\:{Find}\:{the} \\ $$$${distance}\:{of}\:{Q}\:{from}\:{the}\:{origin}\:{at}\: \\ $$$${time}\:{t}=\mathrm{2}{sec} \\ $$

Question Number 191049 Answers: 1 Comments: 1

Question Number 191041 Answers: 1 Comments: 2

Question Number 191030 Answers: 1 Comments: 0

Question Number 191028 Answers: 2 Comments: 0

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Question Number 191024 Answers: 1 Comments: 0

Question Number 191022 Answers: 0 Comments: 1

Question Number 191019 Answers: 1 Comments: 0

1−((1−((1−(⋰/5))/5))/5) =?

$$\mathrm{1}−\frac{\mathrm{1}−\frac{\mathrm{1}−\frac{\iddots}{\mathrm{5}}}{\mathrm{5}}}{\mathrm{5}}\:\:=? \\ $$

Question Number 191009 Answers: 3 Comments: 0

Question Number 191007 Answers: 1 Comments: 1

which quantities is the preassure? scalar or vector?

$${which}\:{quantities}\:{is}\:{the}\:{preassure}? \\ $$$${scalar}\:\:{or}\:{vector}? \\ $$

Question Number 190998 Answers: 3 Comments: 6

Question Number 190996 Answers: 0 Comments: 0

If lim_(x→3) (((√(3x))−3)/( (√(2x−4))−(√2))) = A andlim_(x→3) (((√(3x))+x−6)/( (√(4x−8))+1−x)) = pA then p =?

$$\:\:\:\mathrm{If}\:\underset{{x}\rightarrow\mathrm{3}} {\mathrm{lim}}\:\frac{\sqrt{\mathrm{3x}}−\mathrm{3}}{\:\sqrt{\mathrm{2x}−\mathrm{4}}−\sqrt{\mathrm{2}}}\:=\:\mathrm{A} \\ $$$$\:\:\:\mathrm{and}\underset{{x}\rightarrow\mathrm{3}} {\mathrm{lim}}\:\frac{\sqrt{\mathrm{3x}}+\mathrm{x}−\mathrm{6}}{\:\sqrt{\mathrm{4x}−\mathrm{8}}+\mathrm{1}−\mathrm{x}}\:=\:\mathrm{pA} \\ $$$$\:\:\:\mathrm{then}\:\mathrm{p}\:=?\: \\ $$

Question Number 190993 Answers: 3 Comments: 0

sin^2 x ∙cos^2 x=?

$${sin}^{\mathrm{2}} {x}\:\centerdot{cos}^{\mathrm{2}} {x}=? \\ $$

Question Number 190987 Answers: 1 Comments: 0

Question Number 190985 Answers: 0 Comments: 0

Question Number 190984 Answers: 2 Comments: 0

∫_0 ^3 ∫_0 ^2 x^2 ydydx

$$\:\:\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\int_{\mathrm{0}} ^{\mathrm{3}} \int_{\mathrm{0}} ^{\mathrm{2}} \mathrm{x}^{\mathrm{2}} \mathrm{ydydx}\: \\ $$$$ \\ $$

Question Number 190983 Answers: 0 Comments: 0

∫_(x= ) ^ ∫_(y= ) ^( −x) ∫_(z= ) ^( −x−y) xdzdydx

$$ \\ $$$$\:\:\:\:\int_{\boldsymbol{{x}}= } ^{ } \int_{\boldsymbol{{y}}= } ^{ −\boldsymbol{{x}}} \int_{\boldsymbol{{z}}= } ^{ −\boldsymbol{{x}}−\boldsymbol{{y}}} \boldsymbol{{xdzdydx}} \\ $$$$ \\ $$

Question Number 190982 Answers: 1 Comments: 1

p(x)=2x^2 y^3 −3xy+10 a_0 =? a_1 =? a_2 =? a_(10) =?

$${p}\left({x}\right)=\mathrm{2}{x}^{\mathrm{2}} {y}^{\mathrm{3}} −\mathrm{3}{xy}+\mathrm{10} \\ $$$${a}_{\mathrm{0}} =?\:\:{a}_{\mathrm{1}} =?\:\:\:\:\:{a}_{\mathrm{2}} =?\:\:{a}_{\mathrm{10}} =? \\ $$

Question Number 190972 Answers: 3 Comments: 0

Question Number 190962 Answers: 0 Comments: 1

A massless spring with a spring constant K=10Nm^(−1) is suspended from rigid support carries a mass m=100g at it lower end the system is subjected to resistive force −pv.it observed that the system oscillates and its energy to one third of it initial value in one and half minutes calculates the value of p

$$\mathrm{A}\:\mathrm{massless}\:\mathrm{spring}\:\mathrm{with}\:\mathrm{a}\:\mathrm{spring}\:\mathrm{constant} \\ $$$$\mathrm{K}=\mathrm{10Nm}^{−\mathrm{1}} \:\mathrm{is}\:\mathrm{suspended}\:\mathrm{from}\:\mathrm{rigid}\:\mathrm{support} \\ $$$$\mathrm{carries}\:\mathrm{a}\:\mathrm{mass}\:\mathrm{m}=\mathrm{100g}\:\mathrm{at}\:\mathrm{it}\:\mathrm{lower}\:\mathrm{end} \\ $$$$\mathrm{the}\:\mathrm{system}\:\mathrm{is}\:\mathrm{subjected}\:\mathrm{to}\:\mathrm{resistive}\:\mathrm{force} \\ $$$$−\mathrm{pv}.\mathrm{it}\:\mathrm{observed}\:\mathrm{that}\:\mathrm{the}\:\mathrm{system}\:\mathrm{oscillates} \\ $$$$\mathrm{and}\:\mathrm{its}\:\mathrm{energy}\:\mathrm{to}\:\mathrm{one}\:\mathrm{third}\:\mathrm{of}\:\mathrm{it}\:\mathrm{initial}\:\mathrm{value} \\ $$$$\mathrm{in}\:\mathrm{one}\:\mathrm{and}\:\mathrm{half}\:\mathrm{minutes}\:\mathrm{calculates}\:\mathrm{the}\: \\ $$$$\mathrm{value}\:\mathrm{of}\:\:\mathrm{p} \\ $$

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