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Question Number 189763 Answers: 0 Comments: 0

Question Number 189761 Answers: 3 Comments: 0

(x/(1×2)) + (x/(2×3)) + (x/(3×4)) + ......+ (x/(1998×1999)) + (x/(1999×2000)) = 1 x = ????

$$ \\ $$$$\:\:\frac{\boldsymbol{{x}}}{\mathrm{1}×\mathrm{2}}\:+\:\frac{\boldsymbol{{x}}}{\mathrm{2}×\mathrm{3}}\:+\:\frac{\boldsymbol{{x}}}{\mathrm{3}×\mathrm{4}}\:+\:......+\:\frac{\boldsymbol{{x}}}{\mathrm{1998}×\mathrm{1999}}\:+\:\frac{\boldsymbol{{x}}}{\mathrm{1999}×\mathrm{2000}}\:=\:\mathrm{1}\:\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\boldsymbol{{x}}\:=\:???? \\ $$$$ \\ $$

Question Number 189757 Answers: 2 Comments: 0

Find: lim_(x→(𝛑/2)) (((√2) ∣ sin 4x ∣)/( (√(1 − cos 4x)))) = ? Find: lim_(x→𝛑) (((√2) ∣ sin 6x ∣)/( (√(1 − cos 6x)))) = ?

$$\mathrm{Find}:\:\:\:\:\:\underset{\boldsymbol{\mathrm{x}}\rightarrow\frac{\boldsymbol{\pi}}{\mathrm{2}}} {\mathrm{lim}}\:\frac{\sqrt{\mathrm{2}}\:\mid\:\mathrm{sin}\:\mathrm{4x}\:\mid}{\:\sqrt{\mathrm{1}\:−\:\mathrm{cos}\:\mathrm{4x}}}\:\:\:=\:\:\:? \\ $$$$\mathrm{Find}:\:\:\:\:\:\underset{\boldsymbol{\mathrm{x}}\rightarrow\boldsymbol{\pi}} {\mathrm{lim}}\:\frac{\sqrt{\mathrm{2}}\:\mid\:\mathrm{sin}\:\mathrm{6x}\:\mid}{\:\sqrt{\mathrm{1}\:−\:\mathrm{cos}\:\mathrm{6x}}}\:\:\:=\:\:\:? \\ $$

Question Number 189756 Answers: 0 Comments: 0

Question Number 189755 Answers: 0 Comments: 0

Question Number 189754 Answers: 0 Comments: 0

Question Number 189753 Answers: 0 Comments: 0

Question Number 189748 Answers: 2 Comments: 2

x−(√x)+1=0 x=??

$$ \\ $$$$\:\:\:\:\:\boldsymbol{{x}}−\sqrt{\boldsymbol{{x}}}+\mathrm{1}=\mathrm{0} \\ $$$$\:\:\:\:\:\:\boldsymbol{{x}}=?? \\ $$

Question Number 189747 Answers: 0 Comments: 0

Question Number 189743 Answers: 2 Comments: 0

Question Number 189740 Answers: 0 Comments: 0

A photographer has matted and framed 15 photographs. He needs to select 10 for the arts festival. How many ways can he arrange the photos for the festival?

$$\mathrm{A}\:\mathrm{photographer}\:\mathrm{has}\:\mathrm{matted}\:\mathrm{and}\:\mathrm{framed}\:\mathrm{15}\:\mathrm{photographs}. \\ $$$$\mathrm{He}\:\mathrm{needs}\:\mathrm{to}\:\mathrm{select}\:\mathrm{10}\:\mathrm{for}\:\mathrm{the}\:\mathrm{arts}\:\mathrm{festival}. \\ $$$$\mathrm{How}\:\mathrm{many}\:\mathrm{ways}\:\mathrm{can}\:\mathrm{he}\:\mathrm{arrange}\:\mathrm{the}\:\mathrm{photos} \\ $$$$\mathrm{for}\:\mathrm{the}\:\mathrm{festival}? \\ $$

Question Number 189739 Answers: 1 Comments: 0

A jar is full of candy, 8 pieces are yellow, 12 pieces are red, 6 pieces are orange and 4 pieces are blue. What is the probability that you pick out a piece that is not yellow, put it back and then pick out a yellow piece?

$$\mathrm{A}\:\mathrm{jar}\:\mathrm{is}\:\mathrm{full}\:\mathrm{of}\:\mathrm{candy},\:\mathrm{8}\:\mathrm{pieces}\:\mathrm{are}\:\mathrm{yellow},\:\mathrm{12}\:\mathrm{pieces} \\ $$$$\mathrm{are}\:\mathrm{red},\:\mathrm{6}\:\mathrm{pieces}\:\mathrm{are}\:\mathrm{orange}\:\mathrm{and}\:\mathrm{4}\:\mathrm{pieces} \\ $$$$\mathrm{are}\:\mathrm{blue}.\:\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{probability}\:\mathrm{that}\:\mathrm{you}\:\mathrm{pick} \\ $$$$\mathrm{out}\:\mathrm{a}\:\mathrm{piece}\:\mathrm{that}\:\mathrm{is}\:\mathrm{not}\:\mathrm{yellow},\:\mathrm{put}\:\mathrm{it}\:\mathrm{back} \\ $$$$\mathrm{and}\:\mathrm{then}\:\mathrm{pick}\:\mathrm{out}\:\mathrm{a}\:\mathrm{yellow}\:\mathrm{piece}? \\ $$

Question Number 189752 Answers: 1 Comments: 0

∫^∞ _0 x^2 .e^(−x^2 ) dx=¿

$$\underset{\mathrm{0}} {\int}^{\infty} {x}^{\mathrm{2}} .{e}^{−{x}^{\mathrm{2}} } {dx}=¿ \\ $$

Question Number 189720 Answers: 1 Comments: 0