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Question Number 192540 Answers: 0 Comments: 1
Question Number 192541 Answers: 0 Comments: 0
Question Number 192537 Answers: 1 Comments: 0
$$\:\begin{cases}{\mathrm{tan}\:\left(\alpha+\mathrm{2}\beta\right)=\sqrt{\mathrm{1}+\mathrm{2k}}}\\{\mathrm{tan}\:^{\mathrm{2}} \left(\alpha+\beta\right)\left\{\mathrm{1}+\mathrm{k}\:\mathrm{tan}\:^{\mathrm{2}} \beta\right\}=\mathrm{k}+\mathrm{tan}\:^{\mathrm{2}} \beta}\end{cases} \\ $$$$\:\mathrm{Find}\:\mathrm{cot}\:\mathrm{2}\beta\:. \\ $$
Question Number 192536 Answers: 1 Comments: 0
$$\:\:\mathrm{R}=\frac{\mathrm{3sin}\:\mathrm{5}°+\mathrm{4cos}\:\mathrm{5}°−\mathrm{5cos}\:\mathrm{58}°+\mathrm{35}\sqrt{\mathrm{2}}\:\mathrm{cos}\:\mathrm{13}°}{\mathrm{cos}\:\mathrm{5}°}=? \\ $$
Question Number 192545 Answers: 3 Comments: 0
Question Number 192514 Answers: 1 Comments: 2
Question Number 192508 Answers: 1 Comments: 1
Question Number 192503 Answers: 0 Comments: 0
Question Number 192497 Answers: 1 Comments: 0
$$\:\:\mathrm{tan}\:\mathrm{66}°+\mathrm{tan}\:\mathrm{12}°=\sqrt{\mathrm{3}}\:+\mathrm{tan}\:\mathrm{x} \\ $$$$\:\:\mathrm{x}=? \\ $$
Question Number 192492 Answers: 0 Comments: 0
Question Number 192481 Answers: 1 Comments: 0
Question Number 192477 Answers: 2 Comments: 0
$$\mathrm{Find}:\:\:\:\:\:\frac{\frac{\mathrm{25}}{\mathrm{42}}\:−\:\frac{\mathrm{5}}{\mathrm{16}}\:+\:\frac{\mathrm{10}}{\mathrm{9}}\:−\:\frac{\mathrm{2}}{\mathrm{3}}}{\frac{\mathrm{3}}{\mathrm{8}}\:+\:\frac{\mathrm{4}}{\mathrm{5}}\:−\:\frac{\mathrm{5}}{\mathrm{7}}\:−\:\frac{\mathrm{4}}{\mathrm{3}}}\:=\:? \\ $$
Question Number 192472 Answers: 1 Comments: 0
$$\mathrm{A}\:\mathrm{heat}\:\mathrm{transfer}\:\mathrm{of}\:\mathrm{9}.\mathrm{0}×\mathrm{10}^{\mathrm{5}} \mathrm{J}\:\mathrm{is}\:\mathrm{required} \\ $$$$\mathrm{to}\:\mathrm{convert}\:\mathrm{a}\:\mathrm{block}\:\mathrm{of}\:\mathrm{ice}\:\mathrm{at}\:\mathrm{20}°\mathrm{C}\:\mathrm{to} \\ $$$$\mathrm{water}\:\mathrm{at}\:\mathrm{15}°\mathrm{C},\:\mathrm{what}\:\mathrm{was}\:\mathrm{the}\:\mathrm{mass}\:\mathrm{of} \\ $$$$\mathrm{the}\:\mathrm{block}\:\mathrm{of}\:\mathrm{ice}\:? \\ $$
Question Number 192470 Answers: 1 Comments: 0
Question Number 192469 Answers: 2 Comments: 0
Question Number 192466 Answers: 2 Comments: 1
Question Number 192464 Answers: 0 Comments: 1
Question Number 192463 Answers: 3 Comments: 0
Question Number 192458 Answers: 1 Comments: 0
Question Number 192454 Answers: 0 Comments: 0
$${Evaluate}\:{the}\:{following}\:{improper}\:{intergrals} \\ $$$$\int_{\frac{\pi}{\mathrm{4}}} ^{\frac{\pi}{\mathrm{2}}} \mathrm{sec}\:{xdx}\:\:{if}\:{it}\:{convergent} \\ $$
Question Number 192453 Answers: 2 Comments: 0
$${Find}\:\:\:\:\:\underset{{n}\rightarrow\infty} {\mathrm{lim}}\:\left(\frac{\mathrm{1}}{{n}^{\mathrm{2}} }+\frac{\mathrm{2}}{{n}^{\mathrm{2}} }+\frac{\mathrm{3}}{{n}^{\mathrm{2}} }+...\frac{{n}}{{n}^{\mathrm{2}} }\right) \\ $$
Question Number 192452 Answers: 2 Comments: 0
$${Evaluate}\:\:\:\:\:\int_{\mathrm{0}} ^{\mathrm{1}} \mathrm{2}^{{x}\:} {dx}\:\:\: \\ $$$$ \\ $$
Question Number 192451 Answers: 0 Comments: 0
Question Number 192450 Answers: 1 Comments: 0
$$\mathrm{The}\:\mathrm{first}\:\mathrm{term}\:\mathrm{of}\:\mathrm{an}\:\mathrm{arithmetic}\:\mathrm{series} \\ $$$$\mathrm{is}\:\mathrm{7}\:\mathrm{and}\:\mathrm{the}\:\mathrm{last}\:\mathrm{is}\:\mathrm{70}.\:\mathrm{and}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{is} \\ $$$$\mathrm{385}.\:\mathrm{find}\:\mathrm{the}\:\mathrm{number}\:\mathrm{of}\:\mathrm{terms}\:\mathrm{in}\:\mathrm{the} \\ $$$$\mathrm{series}\:\mathrm{and}\:\mathrm{its}\:\mathrm{common}\:\mathrm{difference}. \\ $$
Question Number 192444 Answers: 1 Comments: 4
$$\mathrm{The}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{three}\:\mathrm{numbers}\:\mathrm{in}\:\mathrm{arith}- \\ $$$$\mathrm{metic}\:\mathrm{progression}\:\mathrm{is}\:\mathrm{18}\:\mathrm{and}\:\mathrm{sum}\:\mathrm{of} \\ $$$$\mathrm{square}\:\mathrm{is}\:\mathrm{206}.\:\mathrm{find}\:\mathrm{the}\:\mathrm{numbers} \\ $$
Question Number 192443 Answers: 1 Comments: 0
$$\mathrm{Find}\:\mathrm{the}\:\:\mathrm{sum}\:\mathrm{of}\:\mathrm{the}\:\mathrm{first}\:\mathrm{16th}\:\mathrm{term} \\ $$$$\:\mathrm{of}\:\mathrm{the}\:\mathrm{series}\:\mathrm{3}\frac{\mathrm{1}}{\mathrm{2}}\:+\:\mathrm{4}\frac{\mathrm{3}}{\mathrm{4}}\:+\:\mathrm{6}\:+\:\mathrm{7}\frac{\mathrm{1}}{\mathrm{4}}\:... \\ $$
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