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Question Number 192105 Answers: 3 Comments: 0

Question Number 192104 Answers: 1 Comments: 0

Question Number 192103 Answers: 1 Comments: 0

Question Number 192099 Answers: 0 Comments: 1

demontrer l expression suivante

$$\mathrm{demontrer}\:\:\mathrm{l}\:\mathrm{expression}\:\mathrm{suivante} \\ $$

Question Number 192098 Answers: 1 Comments: 0

Question Number 192095 Answers: 0 Comments: 0

Prove a non−empty set S of a group G wrt binary operation ∗ is a sub− group of G. Iff 1) a,b ∈ S ⇒ a∗b∈S 2) a ∈ S ⇒ a^(−1) ∈ S. Hello

$$\mathrm{Prove}\:\mathrm{a}\:\mathrm{non}−\mathrm{empty}\:\mathrm{set}\:\mathrm{S}\:\mathrm{of}\:\mathrm{a}\:\mathrm{group} \\ $$$$\mathrm{G}\:\mathrm{wrt}\:\mathrm{binary}\:\mathrm{operation}\:\ast\:\mathrm{is}\:\mathrm{a}\:\mathrm{sub}− \\ $$$$\mathrm{group}\:\mathrm{of}\:\mathrm{G}.\:\mathrm{Iff}\: \\ $$$$\left.\mathrm{1}\right)\:\mathrm{a},\mathrm{b}\:\in\:\mathrm{S}\:\Rightarrow\:\mathrm{a}\ast\mathrm{b}\in\mathrm{S} \\ $$$$\left.\mathrm{2}\right)\:\mathrm{a}\:\in\:\mathrm{S}\:\Rightarrow\:\mathrm{a}^{−\mathrm{1}} \:\in\:\mathrm{S}. \\ $$$$ \\ $$$$ \\ $$$$\mathrm{Hello} \\ $$

Question Number 192094 Answers: 0 Comments: 0

Prove that the order of a subgroup S of a finite group G, always divide the order of group G.

$$\mathrm{Prove}\:\mathrm{that}\:\mathrm{the}\:\mathrm{order}\:\mathrm{of}\:\mathrm{a}\:\mathrm{subgroup} \\ $$$$\mathrm{S}\:\mathrm{of}\:\mathrm{a}\:\mathrm{finite}\:\mathrm{group}\:\mathrm{G},\:\mathrm{always}\:\mathrm{divide} \\ $$$$\mathrm{the}\:\mathrm{order}\:\mathrm{of}\:\mathrm{group}\:\mathrm{G}. \\ $$

Question Number 192087 Answers: 0 Comments: 3

Let {H_α } ∈ Ω, be a family of subgroup of a group G, then prove that ∩_(α ∈ Ω) H_α .

$$\mathrm{Let}\:\left\{\mathrm{H}_{\alpha} \right\}\:\in\:\Omega,\:\mathrm{be}\:\mathrm{a}\:\mathrm{family}\:\mathrm{of}\: \\ $$$$\mathrm{subgroup}\:\mathrm{of}\:\mathrm{a}\:\mathrm{group}\:\mathrm{G},\:\mathrm{then}\: \\ $$$$\mathrm{prove}\:\mathrm{that}\:\cap_{\alpha\:\in\:\Omega} \mathrm{H}_{\alpha} . \\ $$$$ \\ $$$$ \\ $$

Question Number 192084 Answers: 4 Comments: 0

f(x)+x∙f(−x)=x^2 +1 f((√2))=?

$${f}\left({x}\right)+{x}\centerdot{f}\left(−{x}\right)={x}^{\mathrm{2}} +\mathrm{1} \\ $$$${f}\left(\sqrt{\mathrm{2}}\right)=? \\ $$

Question Number 192083 Answers: 1 Comments: 0

f(x)=ax^2 +bx+c f(x−1)+f(x)+f(x+1)=x^2 +1 f(2)=?

$${f}\left({x}\right)={ax}^{\mathrm{2}} +{bx}+{c} \\ $$$${f}\left({x}−\mathrm{1}\right)+{f}\left({x}\right)+{f}\left({x}+\mathrm{1}\right)={x}^{\mathrm{2}} +\mathrm{1} \\ $$$${f}\left(\mathrm{2}\right)=? \\ $$

Question Number 192080 Answers: 1 Comments: 0

f^(−1) (((x+1)/x))=x^3 f^(−1) (x)+f(8)=?

$${f}^{−\mathrm{1}} \left(\frac{{x}+\mathrm{1}}{{x}}\right)={x}^{\mathrm{3}} \:\: \\ $$$${f}^{−\mathrm{1}} \left({x}\right)+{f}\left(\mathrm{8}\right)=? \\ $$

Question Number 192077 Answers: 1 Comments: 0

Let H be a non−empty subset of a group G, prove that the follow− ing are equivalent 1) H is a subgroup of G 2) for a,b ∈ H, ab^(−1) ∈ H 3) for a,b ∈ ab ∈ H 4) for a ∈ H, a^(−1) ∈ H Hint: prove 1)→2)→3)→4)→1) Help!!!

$$\mathrm{Let}\:\mathrm{H}\:\mathrm{be}\:\mathrm{a}\:\mathrm{non}−\mathrm{empty}\:\mathrm{subset}\:\mathrm{of} \\ $$$$\mathrm{a}\:\mathrm{group}\:\mathrm{G},\:\mathrm{prove}\:\mathrm{that}\:\mathrm{the}\:\mathrm{follow}− \\ $$$$\mathrm{ing}\:\mathrm{are}\:\mathrm{equivalent} \\ $$$$\left.\mathrm{1}\right)\:\mathrm{H}\:\mathrm{is}\:\mathrm{a}\:\mathrm{subgroup}\:\mathrm{of}\:\mathrm{G} \\ $$$$\left.\mathrm{2}\right)\:\mathrm{for}\:\mathrm{a},\mathrm{b}\:\in\:\mathrm{H},\:\mathrm{ab}^{−\mathrm{1}} \:\in\:\mathrm{H} \\ $$$$\left.\mathrm{3}\right)\:\mathrm{for}\:\mathrm{a},\mathrm{b}\:\in\:\mathrm{ab}\:\in\:\mathrm{H} \\ $$$$\left.\mathrm{4}\right)\:\mathrm{for}\:\mathrm{a}\:\in\:\mathrm{H},\:\mathrm{a}^{−\mathrm{1}} \:\in\:\mathrm{H} \\ $$$$ \\ $$$$\left.\mathrm{H}\left.\mathrm{i}\left.\mathrm{n}\left.\mathrm{t}\left.:\:\mathrm{prove}\:\mathrm{1}\right)\rightarrow\mathrm{2}\right)\rightarrow\mathrm{3}\right)\rightarrow\mathrm{4}\right)\rightarrow\mathrm{1}\right) \\ $$$$ \\ $$$$\mathrm{Help}!!! \\ $$

Question Number 192076 Answers: 1 Comments: 0

f(x)=x^2 +6x f^(−1) (x)=?

$${f}\left({x}\right)={x}^{\mathrm{2}} +\mathrm{6}{x}\:\:\:\:{f}^{−\mathrm{1}} \left({x}\right)=? \\ $$

Question Number 192073 Answers: 1 Comments: 0

Reponse a l exercice deja pose

$$\mathrm{Reponse}\:\mathrm{a}\:\:\mathrm{l}\:\mathrm{exercice}\:\mathrm{deja}\:\:\mathrm{pose} \\ $$

Question Number 192062 Answers: 2 Comments: 3

prove it : times_n ; (√(4+(√(4+(√(4+...+(√4))))) )) < 3

$${prove}\:{it}\::\: \\ $$$$\:\:\:{times\_n}\:\:\:;\:\:\:\sqrt{\mathrm{4}+\sqrt{\mathrm{4}+\sqrt{\mathrm{4}+...+\sqrt{\mathrm{4}}}}\:\:}\:<\:\mathrm{3} \\ $$

Question Number 192057 Answers: 1 Comments: 0

Simplify: (((√a) + (√a^2 ) + (√a^3 ) + (√a^4 ))/(((√a) + 1)∙(a + 1)))

$$\mathrm{Simplify}: \\ $$$$\frac{\sqrt{\mathrm{a}}\:\:+\:\:\sqrt{\mathrm{a}^{\mathrm{2}} }\:\:+\:\:\sqrt{\mathrm{a}^{\mathrm{3}} }\:\:+\:\:\sqrt{\mathrm{a}^{\mathrm{4}} }}{\left(\sqrt{\mathrm{a}}\:\:+\:\:\mathrm{1}\right)\centerdot\left(\mathrm{a}\:\:+\:\:\mathrm{1}\right)} \\ $$

Question Number 192054 Answers: 1 Comments: 0

If Q = ((2−x)/(y−1)) ; −5≤x<−1 , 5≤y<6 Find Q_(max) .

$$\:\:\:\mathrm{If}\:\mathrm{Q}\:=\:\frac{\mathrm{2}−\mathrm{x}}{\mathrm{y}−\mathrm{1}}\:;\:−\mathrm{5}\leqslant\mathrm{x}<−\mathrm{1}\:,\:\mathrm{5}\leqslant\mathrm{y}<\mathrm{6} \\ $$$$\:\:\:\mathrm{Find}\:\mathrm{Q}_{\mathrm{max}} .\: \\ $$

Question Number 192049 Answers: 2 Comments: 0

fog(x)=4x−1 g(x)=x−2 f(x)=?

$${fog}\left({x}\right)=\mathrm{4}{x}−\mathrm{1} \\ $$$${g}\left({x}\right)={x}−\mathrm{2} \\ $$$${f}\left({x}\right)=? \\ $$

Question Number 192048 Answers: 1 Comments: 0

if the combined function is h(x)=(√(3x^2 +1)) then find the tow other functions of its.

$${if}\:{the}\:{combined}\:{function}\:{is}\:{h}\left({x}\right)=\sqrt{\mathrm{3}{x}^{\mathrm{2}} +\mathrm{1}} \\ $$$${then}\:{find}\:{the}\:{tow}\:{other}\:{functions}\:{of}\:{its}. \\ $$

Question Number 192047 Answers: 1 Comments: 0

we have three digit number like XYZ that X+Y+Z=16, if we replace X by Z then it will be changed to ZYX number that ZYX=XYZ−594 find XYZ number.

$${we}\:{have}\:{three}\:{digit}\:{number}\:{like}\:{XYZ} \\ $$$${that}\:{X}+{Y}+{Z}=\mathrm{16},\:{if}\:{we}\:{replace}\:{X}\:{by}\:{Z} \\ $$$${then}\:{it}\:{will}\:{be}\:{changed}\:{to}\:{ZYX}\:{number}\: \\ $$$${that}\:{ZYX}={XYZ}−\mathrm{594} \\ $$$${find}\:{XYZ}\:{number}. \\ $$

Question Number 192033 Answers: 2 Comments: 0

Question Number 192044 Answers: 0 Comments: 0

Question Number 192045 Answers: 0 Comments: 0

(1/((1+(√2))(1+(2)^(1/4) )(1+(2)^(1/8) )(1+(2)^(1/(16)) )))×(((1−(2)^(1/(16)) )/(1−(2_ )^(1/(16)) ))) ⇒_ ((1−(2)^(1/(16)) )/((1+(√2))(1+(2)^(1/4) )(1+(2)^(1/8) )(1−(2)^(1/8) )))⇒(1/((1+(√2))(1+(2)^(1/4) )(1−(2)^(1/4) )))

Question Number 192024 Answers: 1 Comments: 0

Question Number 192023 Answers: 2 Comments: 0

Question Number 192046 Answers: 2 Comments: 0

tow type creams are in a box that one type of these have 25gr mass and another ones have 37gr mass, if the total mass of those is 870gr then find the number of each type of creams.

$${tow}\:{type}\:{creams}\:{are}\:{in}\:{a}\:{box}\:{that}\:{one}\: \\ $$$${type}\:{of}\:{these}\:{have}\:\mathrm{25}{gr}\:{mass}\:{and}\:{another} \\ $$$${ones}\:{have}\:\mathrm{37}{gr}\:{mass},\:{if}\:{the}\:{total}\:{mass} \\ $$$${of}\:{those}\:{is}\:\mathrm{870}{gr}\:{then}\:{find}\:{the}\:{number} \\ $$$${of}\:{each}\:{type}\:{of}\:{creams}. \\ $$

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