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Question Number 211492    Answers: 1   Comments: 0

Question Number 211485    Answers: 1   Comments: 0

If ((a − b)/c) + ((b − c)/a) + ((c + a)/b) = 1 and a − b + c ≠ 0 then prove that (1/a) = (1/b) + (1/c) .

$$\mathrm{If}\:\frac{{a}\:−\:{b}}{{c}}\:+\:\frac{{b}\:−\:{c}}{{a}}\:+\:\frac{{c}\:+\:{a}}{{b}}\:=\:\mathrm{1}\:\mathrm{and}\: \\ $$$${a}\:−\:{b}\:+\:{c}\:\neq\:\mathrm{0}\:\mathrm{then}\:\mathrm{prove}\:\mathrm{that} \\ $$$$\frac{\mathrm{1}}{{a}}\:=\:\frac{\mathrm{1}}{{b}}\:+\:\frac{\mathrm{1}}{{c}}\:. \\ $$

Question Number 211708    Answers: 2   Comments: 0

Question Number 211486    Answers: 0   Comments: 0

Mathematical Analysis... f:R → R is diffrentiable function, f and f ′ , has no common zero on R . prove that the following set is finite. X = { x ∈ [0 , 1 ] ∣ f(x)=0 } −−−−−−−−−−−−

$$ \\ $$$$\:\:\:\:\:\:\:\:\:\:{Mathematical}\:\:\:\:\:{Analysis}... \\ $$$$\:\: \\ $$$$\:\:\:\:\:\:{f}:\mathbb{R}\:\rightarrow\:\mathbb{R}\:{is}\:{diffrentiable}\:{function}, \\ $$$$\:\:\:\:\:{f}\:\:{and}\:\:{f}\:'\:,\:{has}\:{no}\:{common}\:{zero} \\ $$$$\:\:\:\:\:{on}\:\:\mathbb{R}\:. \\ $$$$\:\:\:\:\:\:{prove}\:{that}\:{the}\:{following}\:{set}\:{is}\:{finite}. \\ $$$$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{X}\:=\:\left\{\:{x}\:\in\:\left[\mathrm{0}\:,\:\mathrm{1}\:\right]\:\mid\:{f}\left({x}\right)=\mathrm{0}\:\right\} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:−−−−−−−−−−−− \\ $$

Question Number 211482    Answers: 0   Comments: 0

25^(((1/2) + log_(1/2) 27 + log_(25) 27)) =?

$$\:\mathrm{25}^{\left(\frac{\mathrm{1}}{\mathrm{2}}\:+\:{log}_{\frac{\mathrm{1}}{\mathrm{2}}} \mathrm{27}\:+\:{log}_{\mathrm{25}} \mathrm{27}\right)} =? \\ $$

Question Number 211467    Answers: 1   Comments: 0

Solve the following equation ⌊ x ⌋ + (√(x −(√x) )) = ⌊ x+ (1/x) ⌋ ⌊ x ⌋ is floor of , x ,

$$ \\ $$$$\:\:\:{Solve}\:{the}\:{following}\:{equation} \\ $$$$ \\ $$$$\:\:\:\:\:\lfloor\:{x}\:\rfloor\:+\:\sqrt{{x}\:−\sqrt{{x}}\:}\:=\:\lfloor\:{x}+\:\frac{\mathrm{1}}{{x}}\:\rfloor \\ $$$$ \\ $$$$\:\:\:\:\:\lfloor\:{x}\:\rfloor\:{is}\:{floor}\:{of}\:,\:\:{x}\:\:,\: \\ $$

Question Number 211457    Answers: 2   Comments: 0

Question Number 211456    Answers: 2   Comments: 0

Question Number 211455    Answers: 2   Comments: 0

Question Number 211454    Answers: 2   Comments: 0

Question Number 211453    Answers: 1   Comments: 0

Question Number 211451    Answers: 0   Comments: 0

Question Number 211445    Answers: 1   Comments: 0

Question Number 211443    Answers: 1   Comments: 0

Question Number 211437    Answers: 3   Comments: 1

Question Number 211434    Answers: 1   Comments: 0

0.9999....=?(a/b)

$$\mathrm{0}.\mathrm{9999}....=?\frac{{a}}{{b}} \\ $$

Question Number 211430    Answers: 0   Comments: 1

determiner les valeurs demandees en finction des donnes :a, b ,angle F2 (h=MH)

$$\mathrm{determiner}\:\mathrm{les}\:\mathrm{valeurs}\:\mathrm{demandees} \\ $$$$\mathrm{en}\:\mathrm{finction}\:\mathrm{des}\:\mathrm{donnes}\::\boldsymbol{\mathrm{a}},\:\boldsymbol{\mathrm{b}}\:,\mathrm{angle}\:\:\boldsymbol{\mathrm{F}}\mathrm{2} \\ $$$$\left(\mathrm{h}=\boldsymbol{\mathrm{MH}}\right) \\ $$

Question Number 211421    Answers: 1   Comments: 0

if a_n = n^4 ∫_n ^(n+1) ((x dx)/(1+x^5 )) then (1) Σa_n is convergent or divergent?? (2) lim_(n→∞) a_(n ) = ??

$$\:\:\:\:\mathrm{if}\:\mathrm{a}_{\mathrm{n}} \:=\:\mathrm{n}^{\mathrm{4}} \int_{\mathrm{n}} ^{\mathrm{n}+\mathrm{1}} \:\frac{\mathrm{x}\:\mathrm{dx}}{\mathrm{1}+\mathrm{x}^{\mathrm{5}} }\:\:\mathrm{then} \\ $$$$\:\:\:\:\left(\mathrm{1}\right)\:\Sigma\mathrm{a}_{\mathrm{n}} \:\mathrm{is}\:\mathrm{convergent}\:\mathrm{or}\:\mathrm{divergent}?? \\ $$$$\:\:\:\:\left(\mathrm{2}\right)\:\underset{\mathrm{n}\rightarrow\infty} {\mathrm{lim}}\:\mathrm{a}_{\mathrm{n}\:} \:=\:?? \\ $$

Question Number 211419    Answers: 1   Comments: 0

Question Number 211418    Answers: 2   Comments: 0

Question Number 211417    Answers: 0   Comments: 0

Question Number 211416    Answers: 1   Comments: 1

Question Number 211415    Answers: 0   Comments: 1

Question Number 211414    Answers: 1   Comments: 0

Question Number 211405    Answers: 0   Comments: 1

Question Number 211402    Answers: 1   Comments: 0

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