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Question Number 190283 Answers: 0 Comments: 0
$$ \\ $$$$\:\:{calculate} \\ $$$$ \\ $$$$\:\:\:\:{laplace}\:\:{transform}\:\: \\ $$$$\:\:\:\:\:\:\:\mathscr{L}\:\:\:\left\{\:\:\frac{\:{e}^{\:−\frac{\mathrm{1}}{{x}}} }{\:\sqrt{{x}}\:}\:\:\right\}\:=\:?\: \\ $$$$ \\ $$
Question Number 190275 Answers: 1 Comments: 0
$$\:\mathrm{Find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{i}^{\mathrm{n}} \:\mathrm{for}\:\mathrm{every}\:\mathrm{positive} \\ $$$$\:\mathrm{integer}\:\mathrm{n},\:\mathrm{where}\:\mathrm{i}^{\mathrm{2}} \:=\:−\mathrm{1},\:\mathrm{i}^{\mathrm{3}} =\:\mathrm{i}^{\mathrm{2}} \mathrm{i},\:\mathrm{i}^{\mathrm{4}} \:=\:\mathrm{i}^{\mathrm{2}} \mathrm{i}^{\mathrm{2}} \:,\:{etc}. \\ $$
Question Number 190272 Answers: 0 Comments: 0
Question Number 190270 Answers: 1 Comments: 0
Question Number 190269 Answers: 1 Comments: 1
Question Number 190266 Answers: 1 Comments: 0
$${a}\:{ball}\:{is}\:{thrown}\:{vertically}\:{upward} \\ $$$${from}\:{a}\:{point}\:\mathrm{0}.\mathrm{5}{m}\:{above}\:{the}\:{ground}\:{with} \\ $$$${speed}\:{u}\:=\:\mathrm{7}{m}/{s} \\ $$$${find}\:{the}\:{height}\:{reached}\:{above}\:{ground} \\ $$$${g}\:=\:\mathrm{10}{m}/{s}^{\mathrm{2}} \\ $$
Question Number 190263 Answers: 0 Comments: 0
Question Number 190260 Answers: 1 Comments: 0
$${f}\::\:\left[\mathrm{1},\:\mathrm{3}\right]\:\rightarrow\mathbb{R}\:,\:{f}\left({x}\right)\:=\:\frac{\mathrm{1}}{{x}} \\ $$$${A}\left(\mathrm{1},\:\mathrm{1}\right) \\ $$$${B}\left(\mathrm{1},\:\frac{\mathrm{1}}{\mathrm{3}}\right) \\ $$$${B}'\left({b},\:\frac{\mathrm{1}}{{b}}\right)\:,\:{b}\:\geqslant\:\mathrm{1} \\ $$$${Find} \\ $$$${i}.\:{equation}\:{of}\:{line}\:{AB}' \\ $$$${ii}.\:{equation}\:{of}\:{tangent}\:{T}\:'\:{to}\:{C}_{{f}} \:{at}\:{point} \\ $$$${with}\:{x}\:=\:\frac{\mathrm{1}\:+\:{b}}{\mathrm{2}} \\ $$$${iii}.\:{Study}\:{relative}\:{positions}\:{of}\:{L}_{{AB}\:'} \:,\:{T}\:'\:{to}\:{C}_{{f}} \\ $$
Question Number 190259 Answers: 0 Comments: 4
$$\mathrm{solve}\:\mathrm{the}\:\mathrm{differential}\: \\ $$$$\mathrm{equation}. \\ $$$$\frac{\mathrm{d}^{\mathrm{2}} }{\mathrm{dt}^{\mathrm{2}} }\:\mathrm{x}\:+\:\omega^{\mathrm{2}} \mathrm{x}\left(\mathrm{t}\right)\:=\mathrm{0} \\ $$$$;\mathrm{x}\left(\mathrm{0}\right)=\mathrm{0};\mathrm{x}^{\mathrm{2}} \left(\mathrm{0}\right)=\upsilon_{\mathrm{o}} \\ $$
Question Number 190257 Answers: 0 Comments: 2
$$ \\ $$
Question Number 190253 Answers: 1 Comments: 0
Question Number 190249 Answers: 1 Comments: 0
$${if}\:\mathrm{8\%}\:{error}\:{is}\:{made}\:{on}\:{x},\: \\ $$$${what}\:{is}\:{the}\:{percentage}\:{error} \\ $$$${on}\:\lambda{x}^{\frac{\mathrm{1}}{\mathrm{5}}} \:? \\ $$
Question Number 190246 Answers: 0 Comments: 0
Question Number 190242 Answers: 0 Comments: 0
Question Number 190241 Answers: 1 Comments: 0
$${show}\:{that}\:{a}\circledast{b}={a}+{ab}+{b}\:{is}\:{a}\:{monoid}\:{when}\:{G}={Z} \\ $$
Question Number 190239 Answers: 0 Comments: 0
Question Number 190238 Answers: 0 Comments: 0
Question Number 190237 Answers: 0 Comments: 0
Question Number 190230 Answers: 2 Comments: 0
Question Number 190216 Answers: 2 Comments: 3
Question Number 190199 Answers: 1 Comments: 0
Question Number 190198 Answers: 1 Comments: 0
Question Number 190192 Answers: 3 Comments: 2
$${if}\:{a}>{b}>\mathrm{0},\:{find}\:{the}\:{minimum}\:{of} \\ $$$${a}^{\mathrm{2}} +\frac{\mathrm{1}}{\left({a}−{b}\right){b}}=? \\ $$
Question Number 190191 Answers: 1 Comments: 0
Question Number 190186 Answers: 0 Comments: 1
$$ \\ $$$$\:\:\:\:\begin{array}{|c|}{\:\:\:\:\:\:\:\:\:\mathrm{If}\:\:,\:\Omega=\:\int_{\mathrm{0}} ^{\:\frac{\pi}{\mathrm{2}}} \:\frac{\:\mathrm{4cos}^{\:\mathrm{2}} \:\left(\mathrm{4}{x}\right)}{\mathrm{3}\left(\mathrm{1}+\mathrm{sin}^{\:\mathrm{2}} \left(\mathrm{2}{x}\:\right)\right)}\mathrm{d}{x}=\:{a}\sqrt{\mathrm{2}}\:\:+\:{b}\:\:\:\:\:\:\:\:\:\:}\\\hline\end{array}\:\:\:\:\:\:\:\:\: \\ $$$$ \\ $$$$\:\:\:\:\:\:\Rightarrow\:\:\mathrm{Find}\:\:\mathrm{the}\:\:\mathrm{value}\:\mathrm{of}\:\:\:,\:\:{a}−\:{b}=? \\ $$$$ \\ $$
Question Number 190185 Answers: 0 Comments: 1
$$ \\ $$$$\:\:\:\:\:\:\mathrm{In}\:\mathrm{A}\overset{\Delta} {\mathrm{B}C}\:\::\:\: \\ $$$$ \\ $$$$\:\:\:\:\:\:\:\:\:\mathrm{If}\:,\:\mathrm{sin}\:\left(\hat {\mathrm{A}}\:\right)\:=\:\frac{\mathrm{1}}{\mathrm{2}\:\sqrt{\:\mathrm{2}+\:\sqrt{\mathrm{3}}}}\:\:\:\:\:\Rightarrow\:\:\:\:\:\hat {\mathrm{A}}\:=\:?\:\:\:\:\:\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\: \\ $$
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