a_m =Σ_(h=m) ^∞ ((1/h))^2 =(π^2 /6)−Σ_(h=1) ^m ((1/h))^2
a_m ≈𝛙^((1)) (m+1)
𝛙^((n)) (z)=((d^(n+1) )/dz^(n+1) )ln(𝚪(z)) , C\Z_(≤0)
aka polygamma function
1. lim_(m→∞) m𝛙^((1)) (m+1)=1.
and...
2. lim_(m→∞) m^2 𝛙^((1)) (m+1)=∞ div
m^2 𝛙^((1)) (m+1)≈m−𝛜
lim_(m→∞) m^2 𝛙^((1)) (m+1)≈lim_(m→∞) (m−𝛜)=∞
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