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Question Number 195998 Answers: 0 Comments: 0

We can transform to get rid of the ((...))^(1/3) a^(1/3) +b^(1/3) =c^(1/3) (a^(1/3) +b^(1/3) )^3 =c a+b+3a^(1/3) b^(1/3) (a^(1/3) +b^(1/3) )=c 3a^(1/3) b^(1/3) c^(1/3) =c−a−b 27abc=(c−a−b)^3 Is it possible to do the same for a^(1/3) +b^(1/3) =c^(1/3) +d^(1/3) I found no path yet...

Question Number 195997 Answers: 0 Comments: 0

Question Number 195995 Answers: 1 Comments: 0

Δ={(x^ y z), x^2 +y^2 ≤1, x≥0,0<z<y+1} calculer I=∫∫∫_Δ xyzdxdydz please i need help

$$\Delta=\left\{\left(\bar {{x}}\:{y}\:{z}\right),\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} \leqslant\mathrm{1},\:{x}\geqslant\mathrm{0},\mathrm{0}<{z}<{y}+\mathrm{1}\right\} \\ $$$${calculer}\:\boldsymbol{{I}}=\int\int\int_{\Delta} {xyzdxdydz} \\ $$$${please}\:{i}\:{need}\:{help} \\ $$

Question Number 195996 Answers: 2 Comments: 0

Question Number 195982 Answers: 2 Comments: 0

lim_(x→1) [(1/(2(1−(√x))))−(1/(3(1−(x)^(1/3) )))]=? with out l′pital rule

$$\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\left[\frac{\mathrm{1}}{\mathrm{2}\left(\mathrm{1}−\sqrt{{x}}\right)}−\frac{\mathrm{1}}{\mathrm{3}\left(\mathrm{1}−\sqrt[{\mathrm{3}}]{{x}}\right)}\right]=? \\ $$$${with}\:{out}\:{l}'{pital}\:{rule} \\ $$

Question Number 196026 Answers: 1 Comments: 0

∫^( +∞) _( 0) (((lnt)^2 )/(1+t^2 ))dt

$$\underset{\:\mathrm{0}} {\int}^{\:+\infty} \frac{\left({lnt}\right)^{\mathrm{2}} }{\mathrm{1}+{t}^{\mathrm{2}} }{dt} \\ $$

Question Number 195964 Answers: 1 Comments: 0

the family A has 5 members and the family B has 4 members. there are 6 personsfrom other families. in how many ways can you arrange these 15 persons around a round table such that no member from family A and no member from family B are next to each other?

$${the}\:{family}\:{A}\:{has}\:\mathrm{5}\:{members}\:{and}\:{the} \\ $$$${family}\:{B}\:{has}\:\mathrm{4}\:{members}.\:{there}\:{are}\: \\ $$$$\mathrm{6}\:{personsfrom}\:{other}\:{families}. \\ $$$${in}\:{how}\:{many}\:{ways}\:{can}\:{you}\:{arrange} \\ $$$${these}\:\mathrm{15}\:{persons}\:{around}\:{a}\:{round}\:{table} \\ $$$${such}\:{that}\:{no}\:{member}\:{from}\:{family}\:{A} \\ $$$${and}\:{no}\:{member}\:{from}\:{family}\:{B}\:{are} \\ $$$${next}\:{to}\:{each}\:{other}? \\ $$

Question Number 195972 Answers: 0 Comments: 0

Question Number 195971 Answers: 3 Comments: 0

if f′(x)=((f(x+a)−f(x))/a), find f(x).

$${if}\:{f}'\left({x}\right)=\frac{{f}\left({x}+{a}\right)−{f}\left({x}\right)}{{a}},\:{find}\:{f}\left({x}\right). \\ $$

Question Number 195973 Answers: 0 Comments: 0

Question Number 195954 Answers: 3 Comments: 0

Question Number 195953 Answers: 0 Comments: 0

Question Number 195952 Answers: 2 Comments: 0

Ω = Σ_(m=1) ^∞ Σ_(n=1) ^∞ (((−1)^( n+1) )/(m^2 n + mn^( 2) )) = ? −−−−−

$$ \\ $$$$\:\:\:\:\Omega\:=\:\underset{{m}=\mathrm{1}} {\overset{\infty} {\sum}}\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\frac{\left(−\mathrm{1}\right)^{\:{n}+\mathrm{1}} }{{m}^{\mathrm{2}} {n}\:+\:{mn}^{\:\mathrm{2}} }\:\:=\:?\:\:\:\:\:\:\:\:\: \\ $$$$\:\:\:\:\:\:−−−−− \\ $$

Question Number 195948 Answers: 0 Comments: 0

An object is said to cross a thousand kilimeters in planks constant. How many times faster is the object to the speed of light. plank′s time = 10^(−44) sec.

$$\mathrm{An}\:\mathrm{object}\:\mathrm{is}\:\mathrm{said}\:\mathrm{to}\:\mathrm{cross}\:\mathrm{a}\:\mathrm{thousand}\: \\ $$$$\mathrm{kilimeters}\:\mathrm{in}\:\mathrm{planks}\:\mathrm{constant}.\:\mathrm{How}\:\mathrm{many} \\ $$$$\mathrm{times}\:\mathrm{faster}\:\mathrm{is}\:\mathrm{the}\:\mathrm{object}\:\mathrm{to}\:\mathrm{the}\:\mathrm{speed}\:\mathrm{of} \\ $$$$\mathrm{light}.\:\mathrm{plank}'\mathrm{s}\:\mathrm{time}\:=\:\mathrm{10}^{−\mathrm{44}} \mathrm{sec}. \\ $$

Question Number 195947 Answers: 2 Comments: 0