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Question Number 193180 Answers: 3 Comments: 0

If a + b = 1001 & HCF(a, b) = 13 then how many set of a & b.

$$\mathrm{If}\:{a}\:+\:{b}\:=\:\mathrm{1001}\:\&\:\mathrm{HCF}\left({a},\:{b}\right)\:=\:\mathrm{13}\: \\ $$$$\mathrm{then}\:\mathrm{how}\:\mathrm{many}\:\mathrm{set}\:\mathrm{of}\:{a}\:\&\:{b}. \\ $$

Question Number 193179 Answers: 0 Comments: 0

f(θ) = ((v^2 sinθcosθ+vcos (√(v^2 sin^2 θ+Hg )) )/g) f(θ)_(max) =?

$$\:\:{f}\left(\theta\right)\:=\:\frac{{v}^{\mathrm{2}} \mathrm{sin}\theta\mathrm{cos}\theta+{v}\mathrm{cos}\:\sqrt{{v}^{\mathrm{2}} \mathrm{sin}^{\mathrm{2}} \theta+{Hg}\:}\:}{{g}} \\ $$$$\:\:\:{f}\left(\theta\right)_{{max}} =? \\ $$

Question Number 193175 Answers: 3 Comments: 0

please solve for x if 2x^2 =2^x

$${please}\:{solve}\:{for}\:{x}\:{if} \\ $$$$\mathrm{2}{x}^{\mathrm{2}} =\mathrm{2}^{{x}} \\ $$

Question Number 193171 Answers: 0 Comments: 0

Question Number 193170 Answers: 1 Comments: 0

solve : 7^x =−2

$$\mathrm{solve}\::\:\mathrm{7}^{\mathrm{x}} =−\mathrm{2} \\ $$

Question Number 193162 Answers: 1 Comments: 2

Question Number 193161 Answers: 1 Comments: 0

Question Number 193153 Answers: 0 Comments: 0

Question Number 193149 Answers: 1 Comments: 0

Question Number 193139 Answers: 3 Comments: 0

Solve the inequalities: ∣x−(1/2)∣>1 Thank you

$$\mathrm{Solve}\:\mathrm{the}\:\mathrm{inequalities}: \\ $$$$\mid\mathrm{x}−\frac{\mathrm{1}}{\mathrm{2}}\mid>\mathrm{1} \\ $$$$ \\ $$$$\mathrm{Thank}\:\mathrm{you} \\ $$

Question Number 193138 Answers: 2 Comments: 0

Show that for all a,b∈R i) ab≤(1/2)(a^2 +b^2 ) ii) (((a+b)/2))^2 ≤(a^2 +b^2 ) iii) (√(ab))≤(1/2)(a+b), for a,b≥0 such that a and b have square roots. Help

$$\mathrm{Show}\:\mathrm{that}\:\mathrm{for}\:\mathrm{all}\:\mathrm{a},\mathrm{b}\in\mathbb{R} \\ $$$$\left.\mathrm{i}\right)\:\mathrm{ab}\leqslant\frac{\mathrm{1}}{\mathrm{2}}\left(\mathrm{a}^{\mathrm{2}} +\mathrm{b}^{\mathrm{2}} \right) \\ $$$$\left.\mathrm{ii}\right)\:\left(\frac{\mathrm{a}+\mathrm{b}}{\mathrm{2}}\right)^{\mathrm{2}} \leqslant\left(\mathrm{a}^{\mathrm{2}} +\mathrm{b}^{\mathrm{2}} \right) \\ $$$$\left.\mathrm{iii}\right)\:\sqrt{\mathrm{ab}}\leqslant\frac{\mathrm{1}}{\mathrm{2}}\left(\mathrm{a}+\mathrm{b}\right),\:\mathrm{for}\:\mathrm{a},\mathrm{b}\geqslant\mathrm{0}\:\mathrm{such}\:\mathrm{that} \\ $$$$\mathrm{a}\:\mathrm{and}\:\mathrm{b}\:\mathrm{have}\:\mathrm{square}\:\mathrm{roots}. \\ $$$$ \\ $$$$\mathrm{Help} \\ $$

Question Number 193137 Answers: 2 Comments: 0

1) Prove that: ∣a+b+c∣≥∣a∣−∣b∣−∣c∣ 2) Find all x∈R that satify the follow− ing inequalities i) ∣x^2 −4∣<5 ii) ∣x∣+∣x+2∣<5 Help!

$$\left.\mathrm{1}\right)\:\mathrm{Prove}\:\mathrm{that}: \\ $$$$\mid\mathrm{a}+\mathrm{b}+\mathrm{c}\mid\geqslant\mid\mathrm{a}\mid−\mid\mathrm{b}\mid−\mid\mathrm{c}\mid \\ $$$$ \\ $$$$\left.\mathrm{2}\right)\:\mathrm{Find}\:\mathrm{all}\:\mathrm{x}\in\mathbb{R}\:\mathrm{that}\:\mathrm{satify}\:\mathrm{the}\:\mathrm{follow}− \\ $$$$\mathrm{ing}\:\mathrm{inequalities}\: \\ $$$$\left.\mathrm{i}\right)\:\mid\mathrm{x}^{\mathrm{2}} −\mathrm{4}\mid<\mathrm{5} \\ $$$$\left.\mathrm{ii}\right)\:\mid\mathrm{x}\mid+\mid\mathrm{x}+\mathrm{2}\mid<\mathrm{5} \\ $$$$ \\ $$$$\mathrm{Help}! \\ $$

Question Number 193117 Answers: 3 Comments: 0

lim_(x→0) (cosx)^(1/x)

$$\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\left(\mathrm{cosx}\right)^{\frac{\mathrm{1}}{\mathrm{x}}} \\ $$

Question Number 193116 Answers: 2 Comments: 0

Show that for all a,b,c,d ∈ R with a,b,c,d ≥ 0 1) (√(ab))(√(cd)) ≤ (1/4)(a^2 +b^2 +c^2 +d^2 ) 2) (abcd)^(1/4) ≤ (1/4)(a+b+c+d) Help!

$$\mathrm{Show}\:\mathrm{that}\:\mathrm{for}\:\mathrm{all}\:\mathrm{a},\mathrm{b},\mathrm{c},\mathrm{d}\:\in\:\mathbb{R}\:\mathrm{with} \\ $$$$\mathrm{a},\mathrm{b},\mathrm{c},\mathrm{d}\:\geqslant\:\mathrm{0}\: \\ $$$$\left.\mathrm{1}\right)\:\sqrt{\mathrm{ab}}\sqrt{\mathrm{cd}}\:\leqslant\:\frac{\mathrm{1}}{\mathrm{4}}\left(\mathrm{a}^{\mathrm{2}} +\mathrm{b}^{\mathrm{2}} +\mathrm{c}^{\mathrm{2}} +\mathrm{d}^{\mathrm{2}} \right) \\ $$$$\left.\mathrm{2}\right)\:\left(\mathrm{abcd}\right)^{\frac{\mathrm{1}}{\mathrm{4}}} \:\leqslant\:\frac{\mathrm{1}}{\mathrm{4}}\left(\mathrm{a}+\mathrm{b}+\mathrm{c}+\mathrm{d}\right) \\ $$$$ \\ $$$$\mathrm{Help}! \\ $$

Question Number 193111 Answers: 2 Comments: 0

⇃

$$\:\:\:\:\:\:\downharpoonleft\underline{\:} \\ $$

Question Number 193109 Answers: 1 Comments: 0

Question Number 193105 Answers: 0 Comments: 1

Question Number 193099 Answers: 1 Comments: 0

Question Number 193093 Answers: 1 Comments: 0

Question Number 193080 Answers: 1 Comments: 0

Show that for a,b∈R, ∣a−b∣≥∣a∣−∣b∣ (Hint: write a=(a−b)+b

$$\mathrm{Show}\:\mathrm{that}\:\mathrm{for}\:\mathrm{a},\mathrm{b}\in\mathbb{R}, \\ $$$$\mid\mathrm{a}−\mathrm{b}\mid\geqslant\mid\mathrm{a}\mid−\mid\mathrm{b}\mid \\ $$$$ \\ $$$$\left(\mathrm{Hint}:\:\mathrm{write}\:\mathrm{a}=\left(\mathrm{a}−\mathrm{b}\right)+\mathrm{b}\right. \\ $$

Question Number 193079 Answers: 0 Comments: 2

Find all x∈R that satisfy the following inequalities: a) ∣4x−3∣≤11 b) ∣x−2∣>∣x+1∣ c) ∣x∣ + ∣x+2∣ + ∣2−x∣≤8

$$\mathrm{Find}\:\mathrm{all}\:\mathrm{x}\in\mathbb{R}\:\mathrm{that}\:\mathrm{satisfy}\:\mathrm{the}\:\mathrm{following} \\ $$$$\mathrm{inequalities}: \\ $$$$\left.\mathrm{a}\right)\:\mid\mathrm{4x}−\mathrm{3}\mid\leqslant\mathrm{11} \\ $$$$\left.\mathrm{b}\right)\:\mid\mathrm{x}−\mathrm{2}\mid>\mid\mathrm{x}+\mathrm{1}\mid \\ $$$$\left.\mathrm{c}\right)\:\mid\mathrm{x}\mid\:+\:\mid\mathrm{x}+\mathrm{2}\mid\:+\:\mid\mathrm{2}−\mathrm{x}\mid\leqslant\mathrm{8} \\ $$

Question Number 193078 Answers: 1 Comments: 0

1) Prove that if ε>0 and a,x∈R, then ∣a−x∣<ε iff x−ε<a<x+ε help

$$\left.\mathrm{1}\right)\:\mathrm{Prove}\:\mathrm{that}\:\mathrm{if}\:\varepsilon>\mathrm{0}\:\mathrm{and}\:\mathrm{a},\mathrm{x}\in\mathbb{R},\:\mathrm{then} \\ $$$$\mid\mathrm{a}−\mathrm{x}\mid<\varepsilon\:\mathrm{iff}\:\mathrm{x}−\varepsilon<\mathrm{a}<\mathrm{x}+\varepsilon \\ $$$$ \\ $$$$\mathrm{help} \\ $$

Question Number 193087 Answers: 1 Comments: 0

Question Number 193073 Answers: 1 Comments: 0

Question Number 193130 Answers: 3 Comments: 1

Solve for x x^2 −c=(√(c−x))

$$\mathrm{Solve}\:\mathrm{for}\:{x} \\ $$$${x}^{\mathrm{2}} −{c}=\sqrt{{c}−{x}} \\ $$

Question Number 193069 Answers: 1 Comments: 0

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