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Question Number 194240    Answers: 2   Comments: 0

Question Number 194238    Answers: 1   Comments: 0

Question Number 194237    Answers: 0   Comments: 1

how to evaluate 𝚺_(n=0) ^∞ (((βˆ’1)^n )/(k^n n!(zn+1)))

$$\boldsymbol{\mathrm{how}}\:\boldsymbol{\mathrm{to}}\:\boldsymbol{\mathrm{evaluate}}\: \\ $$$$\underset{{n}=\mathrm{0}} {\overset{\infty} {\boldsymbol{\sum}}}\frac{\left(βˆ’\mathrm{1}\right)^{{n}} }{{k}^{{n}} {n}!\left({zn}+\mathrm{1}\right)} \\ $$

Question Number 194236    Answers: 1   Comments: 0

Question Number 194226    Answers: 3   Comments: 0

If x^2 βˆ’ 65x = 64(√x) then (√(x βˆ’ (√x) )) = ?

$$ \\ $$$$\mathrm{If}\:{x}^{\mathrm{2}} \:βˆ’\:\mathrm{65}{x}\:=\:\mathrm{64}\sqrt{{x}}\:\mathrm{then}\:\sqrt{{x}\:βˆ’\:\sqrt{{x}}\:}\:=\:? \\ $$

Question Number 194219    Answers: 1   Comments: 0

Question Number 194218    Answers: 1   Comments: 2

Question Number 194216    Answers: 1   Comments: 0

Question Number 194211    Answers: 1   Comments: 0

(1/x^2 ) +(1/y^2 ) = (1/3) (d^2 y/dx^2 ) =?

$$\:\:\:\:\:\frac{\mathrm{1}}{\mathrm{x}^{\mathrm{2}} }\:+\frac{\mathrm{1}}{\mathrm{y}^{\mathrm{2}} }\:=\:\frac{\mathrm{1}}{\mathrm{3}} \\ $$$$\:\:\:\:\:\frac{\mathrm{d}^{\mathrm{2}} \mathrm{y}}{\mathrm{dx}^{\mathrm{2}} }\:=? \\ $$

Question Number 194208    Answers: 0   Comments: 0

Question Number 194209    Answers: 0   Comments: 0

((1+kx))^(1/3) +x = 1 has two real roots . β‡’ k=? kx+1= 1βˆ’3x+3x^2 βˆ’x^( 3) x^( 3) βˆ’3x^( 2) + (k+3)x=0 x=0 x^( 2) βˆ’3x +k+3=0 1: Ξ”=0 9 βˆ’ 4k βˆ’12=0 k= ((βˆ’3)/4) 2: k=βˆ’3 β‡’ x=0 is a root of x^( 2) βˆ’3x+k+3=0 ∴ k= ((βˆ’3)/4) or k=βˆ’3

$$ \\ $$$$\:\:\:\:\:\:\sqrt[{\mathrm{3}}]{\mathrm{1}+{kx}}\:+{x}\:=\:\mathrm{1}\:\:\:{has} \\ $$$$\:\:\:\:\:\:{two}\:{real}\:{roots}\:.\:\:\Rightarrow\:{k}=? \\ $$$$\:\:\:{kx}+\mathrm{1}=\:\mathrm{1}βˆ’\mathrm{3}{x}+\mathrm{3}{x}^{\mathrm{2}} βˆ’{x}^{\:\mathrm{3}} \\ $$$$\:\:\: \\ $$$$\:\:\:\:\:{x}^{\:\mathrm{3}} \:βˆ’\mathrm{3}{x}^{\:\mathrm{2}} +\:\left({k}+\mathrm{3}\right){x}=\mathrm{0} \\ $$$$\:\:\:\:\:{x}=\mathrm{0} \\ $$$$\:\:\:\:\:{x}^{\:\mathrm{2}} βˆ’\mathrm{3}{x}\:+{k}+\mathrm{3}=\mathrm{0} \\ $$$$\:\:\:\:\mathrm{1}:\:\:\Delta=\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:\:\mathrm{9}\:βˆ’\:\mathrm{4}{k}\:βˆ’\mathrm{12}=\mathrm{0} \\ $$$$\:\:\:\:\:\:\:\:\:\:{k}=\:\frac{βˆ’\mathrm{3}}{\mathrm{4}} \\ $$$$\:\:\:\:\:\:\mathrm{2}:\:\:{k}=βˆ’\mathrm{3}\:\Rightarrow\:{x}=\mathrm{0}\:{is}\:{a}\:{root}\:{of} \\ $$$$\:\:\:\:\:\:{x}^{\:\mathrm{2}} βˆ’\mathrm{3}{x}+{k}+\mathrm{3}=\mathrm{0} \\ $$$$\:\:\:\:\therefore\:\:\:\:\:\:{k}=\:\frac{βˆ’\mathrm{3}}{\mathrm{4}}\:\:\:\:{or}\:\:\:{k}=βˆ’\mathrm{3} \\ $$

Question Number 194207    Answers: 0   Comments: 0

Solve for x x^(xβˆ’4) =(√(3 ))

$$\:\:\:\:\mathrm{Solve}\:\mathrm{for}\:\mathrm{x}\: \\ $$$$\:\:\:\:\mathrm{x}^{\mathrm{x}βˆ’\mathrm{4}} \:\:=\sqrt{\mathrm{3}\:} \\ $$

Question Number 194206    Answers: 1   Comments: 0

Question Number 194204    Answers: 1   Comments: 0

Question Number 194201    Answers: 1   Comments: 3

Question Number 194197    Answers: 1   Comments: 0

Question Number 194194    Answers: 0   Comments: 0

Question Number 194193    Answers: 0   Comments: 0

Question Number 194191    Answers: 1   Comments: 0

Question Number 194190    Answers: 0   Comments: 1

Explanation Why: While f(ax+b)+f(cx+d)=ex+g then f(x)=Ax^2 +Bx+C ΒΏ

$${Explanation}\:{Why}: \\ $$$${While}\:{f}\left({ax}+{b}\right)+{f}\left({cx}+{d}\right)={ex}+{g} \\ $$$${then}\:{f}\left({x}\right)={Ax}^{\mathrm{2}} +{Bx}+{C}\:ΒΏ \\ $$

Question Number 194185    Answers: 1   Comments: 0

lim_( xβ†’ 0^( βˆ’) ) { (( x^( 2) +2cos(x) + βŒŠβˆ’((tan(x))/x) βŒ‹)/(ax^( 4) )) } = 1 a = ? a: (1/(12)) b: βˆ’(1/2) c: 12 d: βˆ’12

$$ \\ $$$$\:\:\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\mathrm{lim}_{\:{x}\rightarrow\:\mathrm{0}^{\:βˆ’} } \:\left\{\:\frac{\:{x}^{\:\mathrm{2}} \:+\mathrm{2}{cos}\left({x}\right)\:+\:\lfloorβˆ’\frac{{tan}\left({x}\right)}{{x}}\:\rfloor}{{ax}^{\:\mathrm{4}} }\:\right\}\:=\:\mathrm{1}\:\:\:\:\:\:\:\:\:\:\:\: \\ $$$$ \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{a}\:=\:? \\ $$$$\:\:\:\:\:\:\:\:{a}:\:\:\:\frac{\mathrm{1}}{\mathrm{12}}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{b}:\:\:βˆ’\frac{\mathrm{1}}{\mathrm{2}}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{c}:\:\:\:\mathrm{12}\:\:\:\:\:\:\:\:\:\:\:\:\:\:{d}:\:\:βˆ’\mathrm{12}\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\: \\ $$

Question Number 194183    Answers: 1   Comments: 0

Σ_(n=1) ^∞ (1/(n(n+15)(n+30)))

$$\underset{{n}=\mathrm{1}} {\overset{\infty} {\sum}}\:\frac{\mathrm{1}}{{n}\left({n}+\mathrm{15}\right)\left({n}+\mathrm{30}\right)} \\ $$

Question Number 194176    Answers: 3   Comments: 0

Hello everyone I try to solve 4^(x+1) +2^(2βˆ’x) =65 Thx in advance

$${Hello}\:{everyone} \\ $$$${I}\:{try}\:{to}\:{solve}\:\mathrm{4}^{{x}+\mathrm{1}} +\mathrm{2}^{\mathrm{2}βˆ’{x}} =\mathrm{65} \\ $$$${Thx}\:{in}\:{advance} \\ $$

Question Number 194170    Answers: 0   Comments: 0

Question Number 194169    Answers: 0   Comments: 0

Question Number 194174    Answers: 1   Comments: 0

Know f(x^(βˆ’1) )=f^(βˆ’1) (x) (f^(βˆ’1) (x)=(1/(f(x)))) Find f(x)ΒΏ

$${Know}\:{f}\left({x}^{βˆ’\mathrm{1}} \right)={f}^{βˆ’\mathrm{1}} \left({x}\right)\:\left({f}^{βˆ’\mathrm{1}} \left({x}\right)=\frac{\mathrm{1}}{{f}\left({x}\right)}\right) \\ $$$${Find}\:{f}\left({x}\right)ΒΏ \\ $$

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