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AllQuestion and Answers: Page 218

Question Number 196860    Answers: 0   Comments: 0

Question Number 196852    Answers: 1   Comments: 0

Question Number 196850    Answers: 0   Comments: 0

Question Number 196848    Answers: 0   Comments: 1

Question Number 196846    Answers: 1   Comments: 0

2xy′′ + (1−4x)y′ + (2x−1)y = y

$$\mathrm{2}{xy}''\:+\:\left(\mathrm{1}−\mathrm{4}{x}\right){y}'\:+\:\left(\mathrm{2}{x}−\mathrm{1}\right){y}\:=\:{y} \\ $$

Question Number 196845    Answers: 0   Comments: 0

Question Number 196843    Answers: 1   Comments: 0

Question Number 196832    Answers: 0   Comments: 1

∫xe^(1/(2x)) dx=?

$$\int{x}\mathrm{e}^{\frac{\mathrm{1}}{\mathrm{2}{x}}} {dx}=? \\ $$

Question Number 196829    Answers: 1   Comments: 0

Question Number 196828    Answers: 2   Comments: 0

Question Number 196817    Answers: 1   Comments: 0

Question Number 196816    Answers: 1   Comments: 0

Question Number 196815    Answers: 1   Comments: 0

!6×(((!5+9!!!!!+7!!!−16))^(1/4) /(!10))=?

$$!\mathrm{6}×\frac{\sqrt[{\mathrm{4}}]{!\mathrm{5}+\mathrm{9}!!!!!+\mathrm{7}!!!−\mathrm{16}}}{!\mathrm{10}}=? \\ $$

Question Number 196836    Answers: 1   Comments: 1

Question Number 196806    Answers: 2   Comments: 0

$$\:\:\:\:\:\cancel{\underline{\underbrace{ }}} \\ $$

Question Number 196793    Answers: 1   Comments: 0

Question Number 196761    Answers: 0   Comments: 0

A tightly wound toroidal coil with a square cross section and an inner radius of 15cm has 500 turns of copper wire and carries an insulated filamentary ccurrent of 0.800A. what is the strength of the magnetic field inside the toroid at the inner radius?

$$\mathrm{A}\:\mathrm{tightly}\:\mathrm{wound}\:\mathrm{toroidal}\:\mathrm{coil}\:\mathrm{with}\:\mathrm{a}\:\mathrm{square} \\ $$$$\mathrm{cross}\:\mathrm{section}\:\mathrm{and}\:\mathrm{an}\:\mathrm{inner}\:\mathrm{radius}\:\mathrm{of}\:\mathrm{15cm}\:\mathrm{has} \\ $$$$\mathrm{500}\:\mathrm{turns}\:\mathrm{of}\:\mathrm{copper}\:\mathrm{wire}\:\mathrm{and}\:\mathrm{carries}\:\mathrm{an}\:\mathrm{insulated} \\ $$$$\mathrm{filamentary}\:\mathrm{ccurrent}\:\mathrm{of}\:\mathrm{0}.\mathrm{800A}.\:\mathrm{what}\:\mathrm{is}\:\mathrm{the} \\ $$$$\mathrm{strength}\:\mathrm{of}\:\mathrm{the}\:\mathrm{magnetic}\:\mathrm{field}\:\mathrm{inside}\:\mathrm{the} \\ $$$$\mathrm{toroid}\:\mathrm{at}\:\mathrm{the}\:\mathrm{inner}\:\mathrm{radius}? \\ $$

Question Number 196760    Answers: 0   Comments: 0

f: R→R f(f(x+y))=f(x)+f(y) Find f(x)=¿

$${f}:\:{R}\rightarrow{R} \\ $$$${f}\left({f}\left({x}+{y}\right)\right)={f}\left({x}\right)+{f}\left({y}\right) \\ $$$${Find}\:{f}\left({x}\right)=¿ \\ $$

Question Number 196758    Answers: 1   Comments: 0

Question Number 196757    Answers: 1   Comments: 0

Question Number 196756    Answers: 0   Comments: 0

Question Number 196755    Answers: 0   Comments: 0

Question Number 196738    Answers: 0   Comments: 13

Question Number 196735    Answers: 2   Comments: 0

Question Number 196734    Answers: 1   Comments: 0

Question Number 196728    Answers: 1   Comments: 1

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