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Question Number 200186 Answers: 2 Comments: 0
Question Number 200183 Answers: 0 Comments: 0
Question Number 200175 Answers: 2 Comments: 1
$${find}\:{all}\:{values}\:{of}\:{x}\:{if}\:{x}^{\mathrm{2}} \equiv\mathrm{4}{mod}\left(\mathrm{5}\right)\:{and}\:\mathrm{0}\leqslant{x}\leqslant\mathrm{11}\:? \\ $$
Question Number 200169 Answers: 1 Comments: 0
$$\mathrm{Rationalise}\:\mathrm{the}\:\mathrm{deniminator}\:\mathrm{of}\:\mathrm{the} \\ $$$$\mathrm{following}\:\mathrm{fraction}: \\ $$$$\frac{\mathrm{1}}{\:\sqrt{\mathrm{6}}\:−\:\sqrt{\mathrm{3}}\:+\:\sqrt{\mathrm{2}}\:+\:\mathrm{1}}\:=\:? \\ $$
Question Number 200168 Answers: 1 Comments: 2
$$\mathrm{If}\:\:\mathrm{f}\left(\mathrm{x}\right)\:=\:\mathrm{2}^{\boldsymbol{\mathrm{x}}} \:+\:\mathrm{86}\:\:\mathrm{and}\:\:\mathrm{g}\left(\mathrm{x}\right)\:=\:\mathrm{3x}^{\mathrm{2}} \:+\:\mathrm{x}\:−\:\mathrm{4} \\ $$$$\mathrm{Then}\:\mathrm{find}:\:\:\mathrm{g}\left[\mathrm{f}^{−\mathrm{1}} \left(\mathrm{g}\left(\mathrm{14}\right)\right)\right]\:=\:? \\ $$
Question Number 200167 Answers: 3 Comments: 0
$$\mathrm{Given}\:\:\:\mathrm{f}:\mathbb{R}\rightarrow\mathbb{R}\:\:\mathrm{is}\:\mathrm{a}\:\mathrm{quadratic}\:\mathrm{polynomial} \\ $$$$\mathrm{f}\left(\mathrm{1}\right)\:=\:\mathrm{1}\:,\:\mathrm{f}\left(\mathrm{2}\right)\:=\:\frac{\mathrm{1}}{\mathrm{2}}\:\:\mathrm{and}\:\:\mathrm{f}\left(\mathrm{3}\right)\:=\:\frac{\mathrm{1}}{\mathrm{3}} \\ $$$$\mathrm{Find}:\:\:\mathrm{f}\left(\mathrm{4}\right)\:=\:? \\ $$
Question Number 200159 Answers: 1 Comments: 2
Question Number 200155 Answers: 2 Comments: 0
Question Number 200139 Answers: 2 Comments: 0
$$\mathrm{If} \\ $$$$\mathrm{x}\::\:\mathrm{y}\::\:\mathrm{z}\:=\:\frac{\mathrm{1}}{\mathrm{7}}\::\:\frac{\mathrm{1}}{\mathrm{3}}\::\:\frac{\mathrm{1}}{\mathrm{21}} \\ $$$$\mathrm{5x}\:−\:\mathrm{2y}\:+\:\mathrm{z}\:=\:\mathrm{16} \\ $$$$ \\ $$$$\mathrm{Find}:\:\:\:\mathrm{y}\:=\:? \\ $$
Question Number 200137 Answers: 1 Comments: 5
Question Number 200134 Answers: 0 Comments: 0
Question Number 200133 Answers: 1 Comments: 0
Question Number 200129 Answers: 0 Comments: 0
Question Number 200130 Answers: 2 Comments: 0
$$\:\:{solve}\:{by}\:{contour}\:{integrstion} \\ $$$$\:\:\int_{\mathrm{0}} ^{\mathrm{2}\pi} \frac{{dx}}{\mathrm{1}+{a}\mathrm{cos}{x}}\: \\ $$
Question Number 200125 Answers: 0 Comments: 0
$$\mathrm{NO}_{\mathrm{2}} \left(\mathrm{g}\right)\:\Rightarrow\:\mathrm{2NO}\:\left(\mathrm{g}\right)+\mathrm{O}_{\mathrm{2}} \:\left(\mathrm{g}\right)\:\mathrm{at}\:\mathrm{300}°\mathrm{C} \\ $$$$\mathrm{The}\:\mathrm{initial}\:\mathrm{concentration}\:\mathrm{of}\:\mathrm{NO}_{\mathrm{2}} \:\mathrm{is}\: \\ $$$$\mathrm{0}.\mathrm{01}\:\mathrm{mol}/\mathrm{L}\:\mathrm{and}\:\mathrm{its}\:\mathrm{concentration}\: \\ $$$$\mathrm{after}\:\mathrm{150}\:\mathrm{s}\:\mathrm{is}\:.\mathrm{0055}\:\mathrm{mol}/\mathrm{L}.\:\mathrm{What}\:\mathrm{are} \\ $$$$\:\mathrm{the}\:\mathrm{average}\:\mathrm{rates}\:\mathrm{of}\:\mathrm{the}\:\mathrm{above} \\ $$$$\:\mathrm{reaction}\:\mathrm{during}\:\mathrm{the}\:\mathrm{first}\:\mathrm{150}\:\mathrm{s}\:\mathrm{and} \\ $$$$\:\mathrm{during}\:\mathrm{the}\:\mathrm{second}\:\mathrm{150}\:\mathrm{s}? \\ $$
Question Number 200122 Answers: 0 Comments: 0
Question Number 200121 Answers: 0 Comments: 0
Question Number 200120 Answers: 1 Comments: 0
Question Number 200110 Answers: 1 Comments: 0
Question Number 200109 Answers: 1 Comments: 0
Question Number 200104 Answers: 0 Comments: 0
Question Number 200103 Answers: 1 Comments: 0
$$\:\:\:\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\mathrm{sin}\:\sqrt{\mathrm{x}+\mathrm{1}}−\mathrm{sin}\:\sqrt{\mathrm{x}}\:=? \\ $$
Question Number 200102 Answers: 1 Comments: 0
Question Number 200092 Answers: 1 Comments: 1
Question Number 200087 Answers: 1 Comments: 2
$$\:\:\mathrm{if}\:\omega\:\neq\:\mathrm{1}\:\mathrm{is}\:\mathrm{a}\:\mathrm{root}\:\mathrm{of}\:\mathrm{unity}\:\mathrm{aand}\:\mathrm{z}\:\mathrm{is}\:\mathrm{a}\: \\ $$$$\mathrm{complex}\:\mathrm{number}\:\mathrm{such}\:\mathrm{that}\:\mid{z}\mid\:=\:\mathrm{1}\:\mathrm{then} \\ $$$$\:\:\mid\frac{\mathrm{2}+\mathrm{3}\omega+\mathrm{4}{z}\omega^{\mathrm{2}} }{\mathrm{4}\omega+\mathrm{3}\omega^{\mathrm{2}} {z}+\mathrm{2}{z}}\mid=\:? \\ $$
Question Number 200085 Answers: 1 Comments: 2
$$\mathrm{perimetre}\:\mathrm{of}\:\:\mathrm{White}\:\mathrm{triangle}? \\ $$
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