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AllQuestion and Answers: Page 210

Question Number 199888 Answers: 0 Comments: 0

Question Number 199854 Answers: 1 Comments: 0

Question Number 199847 Answers: 0 Comments: 6

Find all possible value (a/(a+b+d )) +(b/(a+b+c)) + (c/(b+c+d))+(d/(a+c+d)) when a,b,c,d vary over positive reals

$$\:\mathrm{Find}\:\mathrm{all}\:\mathrm{possible}\:\mathrm{value}\: \\ $$$$\:\frac{\mathrm{a}}{\mathrm{a}+\mathrm{b}+\mathrm{d}\:}\:+\frac{\mathrm{b}}{\mathrm{a}+\mathrm{b}+\mathrm{c}}\:+\:\frac{\mathrm{c}}{\mathrm{b}+\mathrm{c}+\mathrm{d}}+\frac{\mathrm{d}}{\mathrm{a}+\mathrm{c}+\mathrm{d}}\: \\ $$$$\:\mathrm{when}\:\mathrm{a},\mathrm{b},\mathrm{c},\mathrm{d}\:\mathrm{vary}\:\mathrm{over}\:\mathrm{positive} \\ $$$$\:\mathrm{reals}\: \\ $$

Question Number 199844 Answers: 2 Comments: 0

solve (d^2 /dx^2 ) x

$$\mathrm{solve}\:\frac{\mathrm{d}^{\mathrm{2}} }{\mathrm{dx}^{\mathrm{2}} }\:\mathrm{x} \\ $$

Question Number 199840 Answers: 1 Comments: 0

Question Number 199838 Answers: 1 Comments: 0

Question Number 199837 Answers: 1 Comments: 0

Question Number 199836 Answers: 0 Comments: 3

Question Number 199843 Answers: 1 Comments: 0

lim_(x→0) ((1/(ln(1+x) ))−(1/(ln(x+(√(1+x^2 )) )))) = ??

$$\:\:\:\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\:\left(\frac{\mathrm{1}}{\mathrm{ln}\left(\mathrm{1}+{x}\right)\:}−\frac{\mathrm{1}}{\mathrm{ln}\left({x}+\sqrt{\mathrm{1}+{x}^{\mathrm{2}} }\:\right)}\right)\:=\:?? \\ $$

Question Number 199834 Answers: 1 Comments: 1

Let C be the circle with the center (2,3) and radius 5 a) show that P(5,7) lies on C and find the equation of the tangent at P b) show that the line 3x−4y+31=0 is a tangent to C

$$\boldsymbol{{Let}}\:\boldsymbol{{C}}\:\boldsymbol{{be}}\:\boldsymbol{{the}}\:\boldsymbol{{circle}}\:\boldsymbol{{with}}\:\boldsymbol{{the}}\:\boldsymbol{{center}}\:\left(\mathrm{2},\mathrm{3}\right)\:\boldsymbol{{and}}\:\boldsymbol{{radius}}\:\mathrm{5} \\ $$$$\left.\boldsymbol{{a}}\right)\:\boldsymbol{{show}}\:\boldsymbol{{that}}\:\boldsymbol{{P}}\left(\mathrm{5},\mathrm{7}\right)\:\boldsymbol{{lies}}\:\boldsymbol{{on}}\:\boldsymbol{{C}}\:\boldsymbol{{and}}\:\boldsymbol{{find}}\:\boldsymbol{{the}} \\ $$$$\boldsymbol{{equation}}\:\boldsymbol{{of}}\:\boldsymbol{{the}}\:\boldsymbol{{tangent}}\:\boldsymbol{{at}}\:\boldsymbol{{P}} \\ $$$$\left.\boldsymbol{{b}}\right)\:\boldsymbol{{show}}\:\boldsymbol{{that}}\:\boldsymbol{{the}}\:\boldsymbol{{line}}\:\mathrm{3}\boldsymbol{{x}}−\mathrm{4}\boldsymbol{{y}}+\mathrm{31}=\mathrm{0}\:\boldsymbol{{is}}\:\boldsymbol{{a}}\:\boldsymbol{{tangent}}\:\boldsymbol{{to}}\:\boldsymbol{{C}} \\ $$

Question Number 199830 Answers: 1 Comments: 0

Si cos x+sin x=((1+(√3))/2) , halle el valor de la expresion R= 16(sin^6 x+cos^6 x)+3(sec^2 x+csc^2 x)

$$\:\:\mathrm{Si}\:\mathrm{cos}\:\mathrm{x}+\mathrm{sin}\:\mathrm{x}=\frac{\mathrm{1}+\sqrt{\mathrm{3}}}{\mathrm{2}}\:, \\ $$$$\:\mathrm{halle}\:\mathrm{el}\:\mathrm{valor}\:\mathrm{de}\:\mathrm{la}\:\mathrm{expresion}\: \\ $$$$\:\mathrm{R}=\:\mathrm{16}\left(\mathrm{sin}\:^{\mathrm{6}} \mathrm{x}+\mathrm{cos}\:^{\mathrm{6}} \mathrm{x}\right)+\mathrm{3}\left(\mathrm{sec}\:^{\mathrm{2}} \mathrm{x}+\mathrm{csc}^{\mathrm{2}} \:\mathrm{x}\right) \\ $$

Question Number 199821 Answers: 0 Comments: 2

ABFE Care determiner x en fonction de a etb BC=a DE= b

$$\mathrm{ABFE}\:\:\mathrm{Care} \\ $$$$\mathrm{determiner}\:\boldsymbol{\mathrm{x}}\:\mathrm{en}\:\mathrm{fonction}\:\mathrm{de}\:\mathrm{a}\:\mathrm{etb} \\ $$$$\mathrm{BC}=\boldsymbol{\mathrm{a}}\:\:\:\:\:\:\mathrm{DE}=\:\boldsymbol{\mathrm{b}} \\ $$

Question Number 199825 Answers: 1 Comments: 0

Question Number 199817 Answers: 2 Comments: 0

Question Number 199801 Answers: 1 Comments: 0

Question Number 199783 Answers: 1 Comments: 0

∫xdx=?

$$\int{xdx}=? \\ $$

Question Number 199781 Answers: 1 Comments: 0

f : R−{0,1} → R f(x)+f((1/(1−x)))= ((2(1−2x))/(x(1−x))) for x≠ 0 and x≠ 1

$$\: \\ $$$$ \mathrm{f}\::\:\mathrm{R}−\left\{\mathrm{0},\mathrm{1}\right\}\:\rightarrow\:\mathrm{R}\: \\ $$$$\:\: \\ $$$$ \mathrm{f}\left(\mathrm{x}\right)+\mathrm{f}\left(\frac{\mathrm{1}}{\mathrm{1}−\mathrm{x}}\right)=\:\frac{\mathrm{2}\left(\mathrm{1}−\mathrm{2x}\right)}{\mathrm{x}\left(\mathrm{1}−\mathrm{x}\right)}\: \\ $$$$\:\mathrm{for}\:\mathrm{x}\neq\:\mathrm{0}\:\mathrm{and}\:\mathrm{x}\neq\:\mathrm{1}\: \\ $$$$ \\ $$

Question Number 199775 Answers: 2 Comments: 0

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Question Number 199769 Answers: 0 Comments: 0

62n7z7

$$\mathrm{62}{n}\mathrm{7}{z}\mathrm{7} \\ $$

Question Number 199766 Answers: 1 Comments: 0

Question Number 199753 Answers: 1 Comments: 0

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