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Question Number 199932 Answers: 2 Comments: 0

1. If 3 ∙ ab^(−) + bc^(−) = 115 Find: max(a+b+c)=? 2. a,b,c∈N If (a/2) + (b/3) = (c/4) Find: min(a+b+c)=?

$$\mathrm{1}. \\ $$$$\mathrm{If}\:\:\:\mathrm{3}\:\centerdot\:\overline {\mathrm{ab}}\:+\:\overline {\mathrm{bc}}\:=\:\mathrm{115} \\ $$$$\mathrm{Find}:\:\:\:\mathrm{max}\left(\mathrm{a}+\mathrm{b}+\mathrm{c}\right)=? \\ $$$$ \\ $$$$\mathrm{2}. \\ $$$$\mathrm{a},\mathrm{b},\mathrm{c}\in\mathbb{N} \\ $$$$\mathrm{If}\:\:\:\frac{\mathrm{a}}{\mathrm{2}}\:\:+\:\:\frac{\mathrm{b}}{\mathrm{3}}\:\:=\:\:\frac{\mathrm{c}}{\mathrm{4}} \\ $$$$\mathrm{Find}:\:\:\:\mathrm{min}\left(\mathrm{a}+\mathrm{b}+\mathrm{c}\right)=? \\ $$

Question Number 199923 Answers: 2 Comments: 0

Question Number 199922 Answers: 2 Comments: 0

Question Number 199921 Answers: 1 Comments: 0

Question Number 199916 Answers: 0 Comments: 0

Question Number 199915 Answers: 1 Comments: 0

Question Number 199913 Answers: 0 Comments: 0

To calculate the mean and median of the distribution, you can follow these steps: 1. Calculate the midpoint for each weight range: - For 118-126: Midpoint = (118 + 126) / 2 = 122 - For 127-135: Midpoint = (127 + 135) / 2 = 131 - For 136-144: Midpoint = (136 + 144) / 2 = 140 - For 145-153: Midpoint = (145 + 153) / 2 = 149 - For 154-162: Midpoint = (154 + 162) / 2 = 158 - For 163-171: Midpoint = (163 + 171) / 2 = 167 - For 172-180: Midpoint = (172 + 180) / 2 = 176 2. Multiply each midpoint by its corresponding frequency to find the sum of the products. - (122 * 3) + (131 * 5) + (140 * 9) + (149 * 12) + (158 * 5) + (167 * 4) + (176 * 2) 3. Sum the frequencies to find the total number of data points. - 3 + 5 + 9 + 12 + 5 + 4 + 2 = 40 4. Calculate the mean (average) by dividing the sum of the products by the total number of data points: - Mean = (Sum of products) / (Total number of data points) 5. To find the median, you can start by listing the weights in ascending order. Then, locate the middle value. Since there are 40 data points (an even number), the median will be the average of the 20th and 21st values. - Arrange the midpoints in ascending order: 122, 131, 140, 149, 158, 167, 176. - The 20th value is 149, and the 21st value is 158. - Median = (149 + 158) / 2 Now, you can calculate the mean and median based on the given data.

$$ \\ $$To calculate the mean and median of the distribution, you can follow these steps: 1. Calculate the midpoint for each weight range: - For 118-126: Midpoint = (118 + 126) / 2 = 122 - For 127-135: Midpoint = (127 + 135) / 2 = 131 - For 136-144: Midpoint = (136 + 144) / 2 = 140 - For 145-153: Midpoint = (145 + 153) / 2 = 149 - For 154-162: Midpoint = (154 + 162) / 2 = 158 - For 163-171: Midpoint = (163 + 171) / 2 = 167 - For 172-180: Midpoint = (172 + 180) / 2 = 176 2. Multiply each midpoint by its corresponding frequency to find the sum of the products. - (122 * 3) + (131 * 5) + (140 * 9) + (149 * 12) + (158 * 5) + (167 * 4) + (176 * 2) 3. Sum the frequencies to find the total number of data points. - 3 + 5 + 9 + 12 + 5 + 4 + 2 = 40 4. Calculate the mean (average) by dividing the sum of the products by the total number of data points: - Mean = (Sum of products) / (Total number of data points) 5. To find the median, you can start by listing the weights in ascending order. Then, locate the middle value. Since there are 40 data points (an even number), the median will be the average of the 20th and 21st values. - Arrange the midpoints in ascending order: 122, 131, 140, 149, 158, 167, 176. - The 20th value is 149, and the 21st value is 158. - Median = (149 + 158) / 2 Now, you can calculate the mean and median based on the given data.

Question Number 199911 Answers: 3 Comments: 6

Question Number 199908 Answers: 2 Comments: 0

lim_(x→0) (((2^x +3^x +5^x )/3))^(3/x) =?

$$\:\:\:\:\:\underset{{x}\rightarrow\mathrm{0}} {\mathrm{lim}}\left(\frac{\mathrm{2}^{\mathrm{x}} +\mathrm{3}^{\mathrm{x}} +\mathrm{5}^{\mathrm{x}} }{\mathrm{3}}\right)^{\frac{\mathrm{3}}{\mathrm{x}}} =?\: \\ $$

Question Number 199907 Answers: 1 Comments: 0

∫ (dx/( (√x) + (x)^(1/3) )) =?

$$\:\:\:\:\:\int\:\frac{\mathrm{dx}}{\:\sqrt{\mathrm{x}}\:+\:\sqrt[{\mathrm{3}}]{\mathrm{x}}}\:=?\: \\ $$

Question Number 199903 Answers: 2 Comments: 1

∫((x^2 dx)/( (√(x^2 −16)))) = ?

$$\int\frac{{x}^{\mathrm{2}} {dx}}{\:\sqrt{{x}^{\mathrm{2}} −\mathrm{16}}}\:=\:? \\ $$

Question Number 199900 Answers: 2 Comments: 0

Question Number 199899 Answers: 1 Comments: 0

Question Number 199898 Answers: 1 Comments: 0

Question Number 199876 Answers: 0 Comments: 0

Question Number 199864 Answers: 1 Comments: 0

Find the remainder Σ_(n=1) ^(2019) n^4 when divide by 53

$$\:\:\:\mathrm{Find}\:\mathrm{the}\:\mathrm{remainder}\:\underset{\mathrm{n}=\mathrm{1}} {\overset{\mathrm{2019}} {\sum}}\mathrm{n}^{\mathrm{4}} \:\mathrm{when} \\ $$$$\:\:\mathrm{divide}\:\mathrm{by}\:\mathrm{53}\: \\ $$

Question Number 199863 Answers: 1 Comments: 0

−5+(−8)+(−11)+...+(−230)

$$−\mathrm{5}+\left(−\mathrm{8}\right)+\left(−\mathrm{11}\right)+...+\left(−\mathrm{230}\right) \\ $$

Question Number 199862 Answers: 0 Comments: 0

consider the taylor expansion of the function (1/(1+x^3 )) centered at x = 1/2 then the radius of convergence of the power series repersentation of the function is

$$\mathrm{consider}\:\mathrm{the}\:\mathrm{taylor}\:\mathrm{expansion}\:\mathrm{of}\:\mathrm{the}\:\mathrm{function}\:\frac{\mathrm{1}}{\mathrm{1}+\mathrm{x}^{\mathrm{3}} } \\ $$$$\mathrm{centered}\:\mathrm{at}\:\mathrm{x}\:=\:\mathrm{1}/\mathrm{2}\:\mathrm{then}\:\mathrm{the}\:\mathrm{radius}\:\mathrm{of}\:\mathrm{convergence} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{power}\:\mathrm{series}\:\mathrm{repersentation}\:\mathrm{of}\:\mathrm{the}\:\mathrm{function}\:\mathrm{is} \\ $$

Question Number 199858 Answers: 3 Comments: 0