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Question Number 201433 Answers: 3 Comments: 0
$${A}\:{truck},\:{P},\:{travelling}\:{at}\:\mathrm{54}{km}/{h}\:{passes} \\ $$$${a}\:{point}\:{at}\:\mathrm{10}:\mathrm{30}\:{am}\:{while}\:{another}\:{truck}, \\ $$$${Q}\:{travelling}\:{at}\:\mathrm{90}{km}/{h}\:{passes}\:{through} \\ $$$${this}\:{same}\:{point}\:\mathrm{30}\:{minutes}\:{later}.\:{At} \\ $$$${what}\:{time}\:{will}\:{truck}\:{Q}\:{overtake}\:{P}? \\ $$
Question Number 201430 Answers: 1 Comments: 0
$$\mathrm{Find}: \\ $$$$\frac{\mathrm{2}}{\mathrm{35}}\:+\:\frac{\mathrm{2}}{\mathrm{63}}\:+\:\frac{\mathrm{2}}{\mathrm{99}}\:+\:\frac{\mathrm{2}}{\mathrm{143}}\:=\:? \\ $$
Question Number 201427 Answers: 2 Comments: 0
$$\begin{cases}{{sin}\left({x}+{y}\right)={cos}\left({x}−{y}\right)}\\{{tanx}−{tany}=\mathrm{1}}\end{cases} \\ $$$$\left({x},{y}\right)=\left(?,?\right) \\ $$
Question Number 201426 Answers: 1 Comments: 0
$${cosx}−\sqrt{\mathrm{3}}{sinx}=\mathrm{1} \\ $$$${x}=? \\ $$
Question Number 201425 Answers: 1 Comments: 0
$${prove}\:{that} \\ $$$$\frac{\mathrm{1}−{cosA}+{cosB}−{cos}\left({A}+{B}\right)}{\mathrm{1}+{cosA}−{cosB}−{cos}\left({A}+{B}\right)}={tan}\frac{{A}}{\mathrm{2}}\centerdot{cot}\frac{{B}}{\mathrm{2}} \\ $$
Question Number 201421 Answers: 1 Comments: 5
Question Number 201418 Answers: 2 Comments: 0
$$\:\:\:\:\:\:\mathrm{2025}^{\mathrm{2025}} \:=\:\mathrm{x}\:\left(\mathrm{mod}\:\mathrm{17}\:\right) \\ $$
Question Number 201411 Answers: 0 Comments: 1
Question Number 201408 Answers: 3 Comments: 0
Question Number 201401 Answers: 0 Comments: 0
Question Number 201393 Answers: 1 Comments: 1
$${by}\:{diffention}\:{find}\:{f}\:'\left({z}\right)\:{of}\:{f}\left({z}\right)\:=\:\sqrt[{\mathrm{3}}]{{z}} \\ $$
Question Number 201388 Answers: 2 Comments: 0
Question Number 201383 Answers: 0 Comments: 2
Question Number 201374 Answers: 1 Comments: 0
Question Number 201373 Answers: 2 Comments: 0
Question Number 201370 Answers: 0 Comments: 1
Question Number 201357 Answers: 0 Comments: 1
Question Number 201355 Answers: 1 Comments: 0
Question Number 201353 Answers: 1 Comments: 1
Question Number 201352 Answers: 3 Comments: 0
$$\:\:\:\mathrm{2023}^{\mathrm{2023}} \:=\:...\:\left(\mathrm{mod}\:\mathrm{13}\right) \\ $$
Question Number 201351 Answers: 2 Comments: 0
Question Number 201350 Answers: 2 Comments: 0
Question Number 201349 Answers: 1 Comments: 0
Question Number 201348 Answers: 1 Comments: 0
Question Number 201347 Answers: 1 Comments: 0
Question Number 201346 Answers: 0 Comments: 0
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