Question and Answers Forum

All Questions   Topic List

AllQuestion and Answers: Page 203

Question Number 201991    Answers: 2   Comments: 0

Solve ((1/x) − (1/x^3 ))^(1/2) + ((1/x^2 ) − (1/x^3 ))^(1/2) = 1

$$\boldsymbol{\mathrm{Solve}} \\ $$$$\left(\frac{\mathrm{1}}{{x}}\:−\:\frac{\mathrm{1}}{{x}^{\mathrm{3}} }\right)^{\frac{\mathrm{1}}{\mathrm{2}}} \:+\:\left(\frac{\mathrm{1}}{{x}^{\mathrm{2}} }\:−\:\frac{\mathrm{1}}{{x}^{\mathrm{3}} }\right)^{\frac{\mathrm{1}}{\mathrm{2}}} \:=\:\mathrm{1} \\ $$

Question Number 201989    Answers: 1   Comments: 0

Question Number 201952    Answers: 1   Comments: 0

(gof)_x =2x−1 (fog)_x ^(−1) =3x+2 (fof)_3 =?

$$\left({gof}\right)_{{x}} =\mathrm{2}{x}−\mathrm{1}\:\: \\ $$$$\left({fog}\right)_{{x}} ^{−\mathrm{1}} =\mathrm{3}{x}+\mathrm{2} \\ $$$$\left({fof}\right)_{\mathrm{3}} =? \\ $$

Question Number 201950    Answers: 0   Comments: 0

Question Number 201949    Answers: 1   Comments: 0

Question Number 201947    Answers: 1   Comments: 0

Question Number 201941    Answers: 2   Comments: 1

x^4 −((17)/(18))x^2 +((40)/3)x+((1625)/(144))=0 Find roots. (Two are real and two are complex)★

$${x}^{\mathrm{4}} −\frac{\mathrm{17}}{\mathrm{18}}{x}^{\mathrm{2}} +\frac{\mathrm{40}}{\mathrm{3}}{x}+\frac{\mathrm{1625}}{\mathrm{144}}=\mathrm{0} \\ $$$${Find}\:{roots}.\:\left({Two}\:{are}\:{real}\:{and}\:{two}\:\right. \\ $$$$\left.{are}\:{complex}\right)\bigstar \\ $$

Question Number 201940    Answers: 1   Comments: 0

tan^3 (xy^2 +y)=x find (dy/dx)

$$\boldsymbol{{tan}}^{\mathrm{3}} \left(\boldsymbol{{xy}}^{\mathrm{2}} +\boldsymbol{{y}}\right)=\boldsymbol{{x}}\:\:\boldsymbol{{find}}\:\frac{\boldsymbol{{dy}}}{\boldsymbol{{dx}}} \\ $$

Question Number 201936    Answers: 0   Comments: 1

Question Number 201934    Answers: 0   Comments: 1

Question Number 201931    Answers: 1   Comments: 0

if (a−2)^2 = 4a find: 5a + 4 + ((16)/(5a + 4)) = ?

$$\mathrm{if}\:\:\:\left(\mathrm{a}−\mathrm{2}\right)^{\mathrm{2}} \:=\:\mathrm{4a} \\ $$$$\mathrm{find}:\:\:\:\mathrm{5a}\:+\:\mathrm{4}\:+\:\frac{\mathrm{16}}{\mathrm{5a}\:+\:\mathrm{4}}\:=\:? \\ $$

Question Number 201925    Answers: 0   Comments: 2

Question Number 201914    Answers: 0   Comments: 1

Question Number 201912    Answers: 0   Comments: 2

$$ \\ $$

Question Number 201907    Answers: 1   Comments: 0

Question Number 201906    Answers: 2   Comments: 0

Question Number 201902    Answers: 0   Comments: 0

Question Number 201901    Answers: 0   Comments: 0

Question Number 201899    Answers: 0   Comments: 0

Question Number 201890    Answers: 2   Comments: 0

Question Number 201892    Answers: 1   Comments: 0

Question Number 201888    Answers: 1   Comments: 0

Question Number 201898    Answers: 2   Comments: 0

Question Number 201882    Answers: 1   Comments: 1

Question Number 201877    Answers: 0   Comments: 0

Question Number 201873    Answers: 1   Comments: 0

  Pg 198      Pg 199      Pg 200      Pg 201      Pg 202      Pg 203      Pg 204      Pg 205      Pg 206      Pg 207   

Terms of Service

Privacy Policy

Contact: info@tinkutara.com