Question and Answers Forum

AllQuestion and Answers: Page 1976

Question Number 10237 Answers: 1 Comments: 0

(1) 4H_2 O (2) FeSO_4 + K_2 Cr_2 O_7 help in balancing ironically and atomically.

$$\left(\mathrm{1}\right)\:\mathrm{4H}_{\mathrm{2}} \mathrm{O}\:\: \\ $$$$\left(\mathrm{2}\right)\:\mathrm{FeSO}_{\mathrm{4}} \:+\:\mathrm{K}_{\mathrm{2}} \mathrm{Cr}_{\mathrm{2}} \mathrm{O}_{\mathrm{7}} \\ $$$$\mathrm{help}\:\mathrm{in}\:\mathrm{balancing}\:\mathrm{ironically}\:\mathrm{and}\:\mathrm{atomically}. \\ $$

Question Number 10236 Answers: 1 Comments: 0

An electron moves in a vacuum between two electrode having a p.d of 3000v, calculate the velocity acquired by the electon if the ratio of its charge to mass is 1.8×10^(11) Ckg^(−1)

$$\mathrm{An}\:\mathrm{electron}\:\mathrm{moves}\:\mathrm{in}\:\mathrm{a}\:\mathrm{vacuum}\:\mathrm{between} \\ $$$$\mathrm{two}\:\mathrm{electrode}\:\mathrm{having}\:\mathrm{a}\:\mathrm{p}.\mathrm{d}\:\mathrm{of}\:\mathrm{3000v},\:\mathrm{calculate} \\ $$$$\mathrm{the}\:\mathrm{velocity}\:\mathrm{acquired}\:\mathrm{by}\:\mathrm{the}\:\mathrm{electon}\:\mathrm{if}\:\mathrm{the}\:\mathrm{ratio} \\ $$$$\mathrm{of}\:\mathrm{its}\:\mathrm{charge}\:\mathrm{to}\:\mathrm{mass}\:\mathrm{is}\:\mathrm{1}.\mathrm{8}×\mathrm{10}^{\mathrm{11}} \mathrm{Ckg}^{−\mathrm{1}} \\ $$

Question Number 10232 Answers: 1 Comments: 0

x∈Z, A∈R A=^4 (√(3−∣x−4∣)) ⇒Σx=?

$$\mathrm{x}\in\mathrm{Z},\:\mathrm{A}\in\mathrm{R} \\ $$$$\mathrm{A}=^{\mathrm{4}} \sqrt{\mathrm{3}−\mid\mathrm{x}−\mathrm{4}\mid}\:\Rightarrow\Sigma\mathrm{x}=? \\ $$

Question Number 10228 Answers: 0 Comments: 4

B is the matrix ⌈ 3 1 −3⌉ ∣ 1 2a 1 ∣ ⌊ 0 2 a ⌋ i.find the value of a for which B is singular ii.determine whether or not ⌈x ⌉ ⌈ −3.5⌉ B ∣y ∣ = ∣ 5.5∣ has the ⌊ z ⌋ ⌊ 5 ⌋ solution for each of the value of obtai ned in (i) above

$$\:\:\:\:\:\:\:\:\mathrm{B}\:\mathrm{is}\:\mathrm{the}\:\mathrm{matrix}\: \\ $$$$\:\:\:\:\:\:\:\lceil\:\:\mathrm{3}\:\:\:\:\:\:\mathrm{1}\:\:−\mathrm{3}\rceil \\ $$$$\:\:\:\:\:\:\:\mid\:\:\mathrm{1}\:\:\:\:\:\:\mathrm{2a}\:\:\:\mathrm{1}\:\:\mid \\ $$$$\:\:\:\:\:\:\:\lfloor\:\:\mathrm{0}\:\:\:\:\:\:\:\mathrm{2}\:\:\:\:\mathrm{a}\:\rfloor \\ $$$$\:\mathrm{i}.\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{a}\:\mathrm{for}\:\mathrm{which}\:\mathrm{B}\:\mathrm{is}\: \\ $$$$\:\:\:\:\mathrm{singular} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\mathrm{ii}.\mathrm{determine}\:\mathrm{whether}\:\mathrm{or}\:\mathrm{not}\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\lceil\mathrm{x}\:\rceil\:\:\:\:\:\:\:\:\:\lceil\:−\mathrm{3}.\mathrm{5}\rceil \\ $$$$\:\:\:\mathrm{B}\:\:\:\:\:\:\:\:\mid\mathrm{y}\:\:\mid\:\:=\:\:\:\:\mid\:\:\:\:\:\:\mathrm{5}.\mathrm{5}\mid\:\:\mathrm{has}\:\mathrm{the}\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\lfloor\:\mathrm{z}\:\:\rfloor\:\:\:\:\:\:\:\:\lfloor\:\:\:\:\:\:\:\mathrm{5}\:\:\rfloor \\ $$$$\mathrm{solution}\:\mathrm{for}\:\mathrm{each}\:\mathrm{of}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{obtai} \\ $$$$\mathrm{ned}\:\mathrm{in}\:\left(\mathrm{i}\right)\:\mathrm{above} \\ $$

Question Number 10227 Answers: 1 Comments: 0

An aeroplane leaves a port P(51°S, 29°E) and after flying 7597 km due north it reached another port R. calculate the. (i) Latitude of R correct to the nearest degree (ii) Radius of parallel of latitude through R to the nearest whole number.

$$\mathrm{An}\:\mathrm{aeroplane}\:\mathrm{leaves}\:\mathrm{a}\:\mathrm{port}\:\mathrm{P}\left(\mathrm{51}°\mathrm{S},\:\:\mathrm{29}°\mathrm{E}\right)\:\mathrm{and} \\ $$$$\mathrm{after}\:\mathrm{flying}\:\mathrm{7597}\:\mathrm{km}\:\mathrm{due}\:\mathrm{north}\:\mathrm{it}\:\mathrm{reached}\: \\ $$$$\mathrm{another}\:\mathrm{port}\:\mathrm{R}.\:\mathrm{calculate}\:\mathrm{the}. \\ $$$$\left(\mathrm{i}\right)\:\mathrm{Latitude}\:\mathrm{of}\:\mathrm{R}\:\mathrm{correct}\:\mathrm{to}\:\mathrm{the}\:\mathrm{nearest}\:\mathrm{degree} \\ $$$$\left(\mathrm{ii}\right)\:\mathrm{Radius}\:\mathrm{of}\:\mathrm{parallel}\:\mathrm{of}\:\mathrm{latitude}\:\mathrm{through}\:\mathrm{R} \\ $$$$\mathrm{to}\:\mathrm{the}\:\mathrm{nearest}\:\mathrm{whole}\:\mathrm{number}. \\ $$

Question Number 10223 Answers: 3 Comments: 0

Question Number 10222 Answers: 2 Comments: 1

solve simultaneously. m^4 + n^4 = 9m^2 n^2 + 1 ...... (i) m + n = 4 ........ (ii)

$$\mathrm{solve}\:\mathrm{simultaneously}. \\ $$$$\mathrm{m}^{\mathrm{4}} \:+\:\mathrm{n}^{\mathrm{4}} \:=\:\mathrm{9m}^{\mathrm{2}} \mathrm{n}^{\mathrm{2}} \:+\:\mathrm{1}\:\:\:\:\:\:\:......\:\left(\mathrm{i}\right) \\ $$$$\mathrm{m}\:+\:\mathrm{n}\:=\:\mathrm{4}\:........\:\left(\mathrm{ii}\right) \\ $$

Question Number 10216 Answers: 2 Comments: 0

(((√2) +(√4)+...+(√(28)))/((√3)+(√6)+...+(√(42))))=(√x) ⇒x=?

$$\frac{\sqrt{\mathrm{2}}\:+\sqrt{\mathrm{4}}+...+\sqrt{\mathrm{28}}}{\sqrt{\mathrm{3}}+\sqrt{\mathrm{6}}+...+\sqrt{\mathrm{42}}}=\sqrt{\mathrm{x}}\:\Rightarrow\mathrm{x}=? \\ $$

Question Number 10214 Answers: 1 Comments: 1

How many moles of oxygen atom are in 0.50 mol of Ca(ClO3)2

$$\mathrm{How}\:\mathrm{many}\:\mathrm{moles}\:\mathrm{of}\:\mathrm{oxygen}\:\mathrm{atom}\:\mathrm{are}\:\mathrm{in} \\ $$$$\mathrm{0}.\mathrm{50}\:\mathrm{mol}\:\mathrm{of}\:\mathrm{Ca}\left(\mathrm{ClO3}\right)\mathrm{2} \\ $$

Question Number 10213 Answers: 2 Comments: 0

4a−b=60 2(√a)−(√b)=6 ⇒a+b=?

$$\mathrm{4a}−\mathrm{b}=\mathrm{60} \\ $$$$\mathrm{2}\sqrt{\mathrm{a}}−\sqrt{\mathrm{b}}=\mathrm{6} \\ $$$$\Rightarrow\mathrm{a}+\mathrm{b}=? \\ $$

Question Number 10212 Answers: 3 Comments: 0

x+y=12 x×y=16 ⇒(√(x/y))−(√(y/x)) =?

$$\mathrm{x}+\mathrm{y}=\mathrm{12} \\ $$$$\mathrm{x}×\mathrm{y}=\mathrm{16} \\ $$$$\Rightarrow\sqrt{\frac{\mathrm{x}}{\mathrm{y}}}−\sqrt{\frac{\mathrm{y}}{\mathrm{x}}}\:=? \\ $$

Question Number 10211 Answers: 0 Comments: 2

without solving for x in f(x)=0, show me a different way to find the roots of f(x)=x^2 −x−1

$$\mathrm{without}\:\mathrm{solving}\:\mathrm{for}\:{x}\:\mathrm{in}\:{f}\left({x}\right)=\mathrm{0}, \\ $$$$\mathrm{show}\:\mathrm{me}\:\mathrm{a}\:\mathrm{different}\:\mathrm{way}\:\mathrm{to}\:\mathrm{find}\:\mathrm{the} \\ $$$$\mathrm{roots}\:\mathrm{of}\:{f}\left({x}\right)={x}^{\mathrm{2}} −{x}−\mathrm{1} \\ $$

Question Number 10206 Answers: 1 Comments: 0

^3 (√(49+^3 (√(49+^3 (√(49....)) )))) =x (√(4(√(4(√(4(√(4....)))))))) =y ⇒x^2 −y=?

$$\:^{\mathrm{3}} \sqrt{\mathrm{49}+^{\mathrm{3}} \sqrt{\mathrm{49}+^{\mathrm{3}} \sqrt{\mathrm{49}....}\:}}\:=\mathrm{x} \\ $$$$\sqrt{\mathrm{4}\sqrt{\mathrm{4}\sqrt{\mathrm{4}\sqrt{\mathrm{4}....}}}}\:=\mathrm{y} \\ $$$$\Rightarrow\mathrm{x}^{\mathrm{2}} −\mathrm{y}=? \\ $$

Question Number 10204 Answers: 1 Comments: 0

x^2 p^2 +xyp−6y^2 =0

$${x}^{\mathrm{2}} {p}^{\mathrm{2}} +{xyp}−\mathrm{6}{y}^{\mathrm{2}} =\mathrm{0} \\ $$

Question Number 10200 Answers: 0 Comments: 0

Question Number 10198 Answers: 0 Comments: 0

An aeroplane leaves a port (51^° S, 29^° E) and after flying 759 km due north. it reaches another point R. calculate: (i) Latitude of R correct to the nearest degree (ii) Radius of the parallel of latitude through R to the nearest whole number.

$$\mathrm{An}\:\mathrm{aeroplane}\:\mathrm{leaves}\:\mathrm{a}\:\mathrm{port}\:\left(\mathrm{51}^{°} \mathrm{S},\:\:\mathrm{29}^{°} \mathrm{E}\right)\:\mathrm{and} \\ $$$$\mathrm{after}\:\mathrm{flying}\:\mathrm{759}\:\mathrm{km}\:\mathrm{due}\:\mathrm{north}.\:\mathrm{it}\:\mathrm{reaches} \\ $$$$\mathrm{another}\:\mathrm{point}\:\mathrm{R}.\:\mathrm{calculate}: \\ $$$$\left(\mathrm{i}\right)\:\mathrm{Latitude}\:\mathrm{of}\:\mathrm{R}\:\mathrm{correct}\:\mathrm{to}\:\mathrm{the}\:\mathrm{nearest}\:\mathrm{degree} \\ $$$$\left(\mathrm{ii}\right)\:\mathrm{Radius}\:\mathrm{of}\:\mathrm{the}\:\mathrm{parallel}\:\mathrm{of}\:\mathrm{latitude}\:\mathrm{through} \\ $$$$\mathrm{R}\:\mathrm{to}\:\mathrm{the}\:\mathrm{nearest}\:\mathrm{whole}\:\mathrm{number}. \\ $$

Question Number 10197 Answers: 1 Comments: 0

^3 (√(x−2))+^3 (√(8x−16))=16⇒x=?

$$\:^{\mathrm{3}} \sqrt{\mathrm{x}−\mathrm{2}}+^{\mathrm{3}} \sqrt{\mathrm{8x}−\mathrm{16}}=\mathrm{16}\Rightarrow\mathrm{x}=? \\ $$

Question Number 10196 Answers: 0 Comments: 0

Question Number 10195 Answers: 1 Comments: 1

The number of integral solutions of the equation 7(y+(1/y))−2(y^2 +(1/y^2 ))=9 are?

$${The}\:{number}\:{of}\:{integral}\:{solutions}\:{of}\:{the}\:{equation}\: \\ $$$$\mathrm{7}\left({y}+\frac{\mathrm{1}}{{y}}\right)−\mathrm{2}\left({y}^{\mathrm{2}} +\frac{\mathrm{1}}{{y}^{\mathrm{2}} }\right)=\mathrm{9}\:\mathrm{are}? \\ $$

Question Number 10193 Answers: 1 Comments: 0

x=^3 (√(11+(√(57)))) +^3 (√(11−(√(57)))) ⇒ x^3 −12x=?

$$\mathrm{x}=^{\mathrm{3}} \sqrt{\mathrm{11}+\sqrt{\mathrm{57}}}\:\:+\:^{\mathrm{3}} \sqrt{\mathrm{11}−\sqrt{\mathrm{57}}} \\ $$$$\Rightarrow\:\mathrm{x}^{\mathrm{3}} −\mathrm{12x}=? \\ $$

Question Number 10191 Answers: 1 Comments: 0

∫_0 ^( π) sin(x)^(cos(x)) dx

$$\int_{\mathrm{0}} ^{\:\pi} \mathrm{sin}\left({x}\right)^{\mathrm{cos}\left({x}\right)} {dx} \\ $$

Question Number 10190 Answers: 0 Comments: 3

Question Number 10188 Answers: 0 Comments: 1

Question Number 10186 Answers: 0 Comments: 0

Prove ln (1+(1/n))^n =[1−(1/(2(n+1)))+(1/(2∙3(n+1)^2 ))−(1/(3∙4(n+1)^3 ))+..]

$$\mathrm{Prove} \\ $$$$\mathrm{ln}\:\left(\mathrm{1}+\frac{\mathrm{1}}{{n}}\right)^{{n}} =\left[\mathrm{1}−\frac{\mathrm{1}}{\mathrm{2}\left({n}+\mathrm{1}\right)}+\frac{\mathrm{1}}{\mathrm{2}\centerdot\mathrm{3}\left({n}+\mathrm{1}\right)^{\mathrm{2}} }−\frac{\mathrm{1}}{\mathrm{3}\centerdot\mathrm{4}\left({n}+\mathrm{1}\right)^{\mathrm{3}} }+..\right] \\ $$

Question Number 10181 Answers: 0 Comments: 0

Let A be a subset of {0;1;∙∙∙;1997} containing more than 1000 elements. Prove that A contains either a power of 2 or two distinct integers whose sum is a power of 2.

$${Let}\:{A}\:{be}\:{a}\:{subset}\:{of}\:\left\{\mathrm{0};\mathrm{1};\centerdot\centerdot\centerdot;\mathrm{1997}\right\}\: \\ $$$${containing}\:{more}\:{than}\:\mathrm{1000}\:{elements}. \\ $$$${Prove}\:{that}\:{A}\:{contains}\:{either}\:{a}\:{power} \\ $$$${of}\:\mathrm{2}\:{or}\:{two}\:{distinct}\:{integers}\:{whose}\: \\ $$$${sum}\:{is}\:{a}\:{power}\:{of}\:\mathrm{2}. \\ $$

Question Number 10175 Answers: 1 Comments: 0

Pg 1971 Pg 1972 Pg 1973 Pg 1974 Pg 1975 Pg 1976 Pg 1977 Pg 1978 Pg 1979 Pg 1980

Contact: info@tinkutara.com