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AllQuestion and Answers: Page 1955

Question Number 9982 Answers: 2 Comments: 0

Question Number 9977 Answers: 1 Comments: 0

Question Number 9976 Answers: 1 Comments: 0

a^2 +b^2 +4a+6b+13=0 ⇒ a+b=?

$$\mathrm{a}^{\mathrm{2}} +\mathrm{b}^{\mathrm{2}} +\mathrm{4a}+\mathrm{6b}+\mathrm{13}=\mathrm{0}\:\: \\ $$$$\Rightarrow\:\mathrm{a}+\mathrm{b}=? \\ $$

Question Number 9975 Answers: 0 Comments: 4

∫_( −2 ) ^( −1) ((1/x)) dx

$$\int_{\:−\mathrm{2}\:} ^{\:−\mathrm{1}} \left(\frac{\mathrm{1}}{\mathrm{x}}\right)\:\mathrm{dx} \\ $$

Question Number 9970 Answers: 1 Comments: 0

Question Number 9969 Answers: 0 Comments: 0

Calculate the viscosity of water flowing steadily between two parallel plane. The distance between the plane is 1.9km, the third plane has a constant viscosity of 20 cm/sec when a force square 300N/m^3 is applied.

$$\mathrm{Calculate}\:\mathrm{the}\:\mathrm{viscosity}\:\mathrm{of}\:\mathrm{water}\:\mathrm{flowing}\:\mathrm{steadily} \\ $$$$\mathrm{between}\:\mathrm{two}\:\mathrm{parallel}\:\mathrm{plane}.\:\mathrm{The}\:\mathrm{distance}\: \\ $$$$\mathrm{between}\:\mathrm{the}\:\mathrm{plane}\:\mathrm{is}\:\mathrm{1}.\mathrm{9km},\:\mathrm{the}\:\mathrm{third}\:\mathrm{plane} \\ $$$$\mathrm{has}\:\mathrm{a}\:\mathrm{constant}\:\mathrm{viscosity}\:\mathrm{of}\:\mathrm{20}\:\mathrm{cm}/\mathrm{sec}\:\mathrm{when}\:\mathrm{a} \\ $$$$\mathrm{force}\:\mathrm{square}\:\mathrm{300N}/\mathrm{m}^{\mathrm{3}} \:\mathrm{is}\:\mathrm{applied}. \\ $$

Question Number 9962 Answers: 0 Comments: 2

a,b ∈Z^+ b^2 −a^2 =2b+7a+4 ⇒ a+b=?

$$\mathrm{a},\mathrm{b}\:\in\mathrm{Z}^{+} \\ $$$$\mathrm{b}^{\mathrm{2}} −\mathrm{a}^{\mathrm{2}} =\mathrm{2b}+\mathrm{7a}+\mathrm{4} \\ $$$$\Rightarrow\:\mathrm{a}+\mathrm{b}=? \\ $$

Question Number 9959 Answers: 1 Comments: 0

∣x^2 −25∣=4∣x−5∣ ⇒Σx=?

$$\mid\mathrm{x}^{\mathrm{2}} −\mathrm{25}\mid=\mathrm{4}\mid\mathrm{x}−\mathrm{5}\mid\:\:\:\Rightarrow\Sigma\mathrm{x}=? \\ $$

Question Number 9960 Answers: 1 Comments: 0

Question Number 9954 Answers: 1 Comments: 0

A sound wave of velocity 350 m/s is directed towards the surface of water . If the ratio of the wave length of sound in water to that in air is 425:100, calculate the velocity of the wave in water.

$$\mathrm{A}\:\mathrm{sound}\:\mathrm{wave}\:\mathrm{of}\:\mathrm{velocity}\:\mathrm{350}\:\mathrm{m}/\mathrm{s}\:\mathrm{is}\:\mathrm{directed} \\ $$$$\mathrm{towards}\:\mathrm{the}\:\mathrm{surface}\:\mathrm{of}\:\mathrm{water}\:.\:\mathrm{If}\:\mathrm{the}\:\mathrm{ratio}\:\mathrm{of} \\ $$$$\mathrm{the}\:\mathrm{wave}\:\mathrm{length}\:\mathrm{of}\:\mathrm{sound}\:\mathrm{in}\:\mathrm{water}\:\mathrm{to}\:\mathrm{that}\:\mathrm{in}\: \\ $$$$\mathrm{air}\:\mathrm{is}\:\mathrm{425}:\mathrm{100},\:\mathrm{calculate}\:\mathrm{the}\:\mathrm{velocity}\:\mathrm{of}\:\mathrm{the}\: \\ $$$$\mathrm{wave}\:\mathrm{in}\:\mathrm{water}. \\ $$

Question Number 9953 Answers: 1 Comments: 0

x−y =8 xy=7 ⇒ x^2 −y^2 =?

$$\mathrm{x}−\mathrm{y}\:=\mathrm{8} \\ $$$$\mathrm{xy}=\mathrm{7}\:\:\Rightarrow\:\mathrm{x}^{\mathrm{2}} −\mathrm{y}^{\mathrm{2}} \:=? \\ $$

Question Number 9952 Answers: 0 Comments: 0

∫e^(xy^(2 ) ) dy _ help solve

$$\int{e}^{{xy}^{\mathrm{2}\:} } {dy}\:\:\:\:\:\:\:_{} {help}\:{solve} \\ $$

Question Number 9951 Answers: 1 Comments: 0

∫(√(tan x))dx

$$\int\sqrt{{tan}\:{x}}{dx} \\ $$

Question Number 9947 Answers: 1 Comments: 2

Question Number 10129 Answers: 1 Comments: 0

Write in polar form . (1) 3x − y + 5 = 0 (2) x^2 = (√(x^2 + y^2 ))

$$\mathrm{Write}\:\mathrm{in}\:\mathrm{polar}\:\mathrm{form}\:. \\ $$$$\left(\mathrm{1}\right)\:\:\mathrm{3x}\:−\:\mathrm{y}\:\:+\:\mathrm{5}\:=\:\mathrm{0} \\ $$$$\left(\mathrm{2}\right)\:\:\mathrm{x}^{\mathrm{2}} \:=\:\sqrt{\mathrm{x}^{\mathrm{2}} \:+\:\mathrm{y}^{\mathrm{2}} } \\ $$

Question Number 9941 Answers: 1 Comments: 0

Prove that. tan^(−1) [(p/(p + 2q))] + tan^(−1) [(q/(p + q))] = (π/4)

$$\mathrm{Prove}\:\mathrm{that}. \\ $$$$\mathrm{tan}^{−\mathrm{1}} \left[\frac{\mathrm{p}}{\mathrm{p}\:+\:\mathrm{2q}}\right]\:+\:\mathrm{tan}^{−\mathrm{1}} \left[\frac{\mathrm{q}}{\mathrm{p}\:+\:\mathrm{q}}\right]\:=\:\frac{\pi}{\mathrm{4}} \\ $$

Question Number 9936 Answers: 0 Comments: 0

Two parallel plate capacitor seperated by a di electric of thickness 5mm. They acquire a charge of 55 milli coloumb, when a voltage 180 volt is connected accross them. calculate electric field strength.

$$\mathrm{Two}\:\mathrm{parallel}\:\mathrm{plate}\:\mathrm{capacitor}\:\mathrm{seperated}\:\mathrm{by}\:\mathrm{a} \\ $$$$\mathrm{di}\:\mathrm{electric}\:\mathrm{of}\:\mathrm{thickness}\:\mathrm{5mm}.\:\mathrm{They}\:\mathrm{acquire} \\ $$$$\mathrm{a}\:\mathrm{charge}\:\mathrm{of}\:\mathrm{55}\:\mathrm{milli}\:\mathrm{coloumb},\:\mathrm{when}\:\mathrm{a}\:\mathrm{voltage} \\ $$$$\mathrm{180}\:\mathrm{volt}\:\mathrm{is}\:\mathrm{connected}\:\mathrm{accross}\:\mathrm{them}.\: \\ $$$$\mathrm{calculate}\:\mathrm{electric}\:\mathrm{field}\:\mathrm{strength}. \\ $$

Question Number 9929 Answers: 1 Comments: 0