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Question Number 13200 Answers: 2 Comments: 0

(6)^(1/(5)^(1/(2)^(1/(√3)) ) ) = x How to write x in standard form?

$$\sqrt[{\sqrt[{\sqrt[{\sqrt{\mathrm{3}}}]{\mathrm{2}}}]{\mathrm{5}}}]{\mathrm{6}}\:=\:{x} \\ $$$$\mathrm{How}\:\mathrm{to}\:\mathrm{write}\:{x}\:\mathrm{in}\:\mathrm{standard}\:\mathrm{form}? \\ $$

Question Number 13194 Answers: 1 Comments: 0

Question Number 13191 Answers: 0 Comments: 4

Can we ask here Chemistry or Physics doubts because I am preparing for JEE?

$$\mathrm{Can}\:\mathrm{we}\:\mathrm{ask}\:\mathrm{here}\:\mathrm{Chemistry}\:\mathrm{or}\:\mathrm{Physics} \\ $$$$\mathrm{doubts}\:\mathrm{because}\:\mathrm{I}\:\mathrm{am}\:\mathrm{preparing}\:\mathrm{for}\:\mathrm{JEE}? \\ $$

Question Number 13166 Answers: 2 Comments: 0

Find the values of x and y x^2 − 2xy − y^2 = 14 ............ equation (i) 2x^2 + 3xy + y^2 = − 2 ............ equation (ii)

$$\mathrm{Find}\:\mathrm{the}\:\mathrm{values}\:\mathrm{of}\:\:\mathrm{x}\:\:\mathrm{and}\:\:\mathrm{y} \\ $$$$ \\ $$$$\mathrm{x}^{\mathrm{2}} \:−\:\mathrm{2xy}\:−\:\mathrm{y}^{\mathrm{2}} \:=\:\mathrm{14}\:\:\:\:\:\:\:\:\:............\:\:\mathrm{equation}\:\left(\mathrm{i}\right) \\ $$$$\mathrm{2x}^{\mathrm{2}} \:+\:\mathrm{3xy}\:+\:\mathrm{y}^{\mathrm{2}} \:=\:−\:\mathrm{2}\:\:\:\:\:............\:\mathrm{equation}\:\left(\mathrm{ii}\right) \\ $$

Question Number 13155 Answers: 2 Comments: 0

Question Number 13154 Answers: 2 Comments: 0

Find the smallest number such that when divided by 18 the remainder is 17, When divided by 20 the remainder is 19. and when divided by 24 the remainder is 23.

$$\mathrm{Find}\:\mathrm{the}\:\mathrm{smallest}\:\mathrm{number}\:\mathrm{such}\:\mathrm{that}\:\mathrm{when}\:\mathrm{divided}\:\mathrm{by}\:\mathrm{18}\:\mathrm{the}\:\mathrm{remainder}\:\mathrm{is}\:\mathrm{17}, \\ $$$$\mathrm{When}\:\mathrm{divided}\:\mathrm{by}\:\mathrm{20}\:\mathrm{the}\:\mathrm{remainder}\:\mathrm{is}\:\mathrm{19}.\:\mathrm{and}\:\mathrm{when}\:\mathrm{divided}\:\mathrm{by}\:\mathrm{24}\:\mathrm{the}\:\mathrm{remainder}\: \\ $$$$\mathrm{is}\:\mathrm{23}.\: \\ $$

Question Number 13153 Answers: 1 Comments: 3

Question Number 13152 Answers: 1 Comments: 0

Solve: 5^(log(x)) + logx^5 = 25

$$\mathrm{Solve}:\:\:\mathrm{5}^{\mathrm{log}\left(\mathrm{x}\right)} \:+\:\mathrm{logx}^{\mathrm{5}} \:=\:\mathrm{25} \\ $$

Question Number 13151 Answers: 1 Comments: 0

Question Number 13145 Answers: 1 Comments: 0

((64))^(1/(3)^(1/(√5)) ) = x How to write x into fraction exponent form?

$$\sqrt[{\sqrt[{\sqrt{\mathrm{5}}}]{\mathrm{3}}}]{\mathrm{64}}\:=\:{x} \\ $$$$\mathrm{How}\:\mathrm{to}\:\mathrm{write}\:{x}\:\mathrm{into}\:\mathrm{fraction}\:\mathrm{exponent}\:\mathrm{form}? \\ $$

Question Number 13143 Answers: 0 Comments: 1

Find the point (x,y) which lies 8 unit from the origin, along the terminal line of 155°.

$$\mathrm{Find}\:\mathrm{the}\:\mathrm{point}\:\left(\mathrm{x},\mathrm{y}\right)\:\mathrm{which}\:\mathrm{lies}\:\mathrm{8}\:\mathrm{unit}\:\mathrm{from}\:\mathrm{the}\:\mathrm{origin},\:\:\mathrm{along}\:\mathrm{the}\:\mathrm{terminal}\:\mathrm{line} \\ $$$$\mathrm{of}\:\mathrm{155}°.\: \\ $$

Question Number 13142 Answers: 0 Comments: 1

Find the height PQ of a tower of an observant at a point O, 135 m from the foot of the tower. Determine the angle of elevation of the tower.

$$\mathrm{Find}\:\mathrm{the}\:\mathrm{height}\:\mathrm{PQ}\:\mathrm{of}\:\mathrm{a}\:\mathrm{tower}\:\mathrm{of}\:\mathrm{an}\:\mathrm{observant}\:\mathrm{at}\:\mathrm{a}\:\mathrm{point}\:\mathrm{O},\:\mathrm{135}\:\mathrm{m}\:\mathrm{from}\:\mathrm{the} \\ $$$$\mathrm{foot}\:\mathrm{of}\:\mathrm{the}\:\mathrm{tower}.\:\mathrm{Determine}\:\mathrm{the}\:\mathrm{angle}\:\mathrm{of}\:\mathrm{elevation}\:\mathrm{of}\:\mathrm{the}\:\mathrm{tower}. \\ $$

Question Number 13141 Answers: 1 Comments: 3

Question Number 13140 Answers: 2 Comments: 1

Question Number 13223 Answers: 0 Comments: 1

If a, b, c are sides of triangle show that (1 + ((b−c)/a))^a (1 + ((c−a)/b))^b (1 + ((a−b)/c))^c < 1

$$\mathrm{If}\:{a},\:{b},\:{c}\:\mathrm{are}\:\mathrm{sides}\:\mathrm{of}\:\mathrm{triangle}\:\mathrm{show}\:\mathrm{that} \\ $$$$\left(\mathrm{1}\:+\:\frac{{b}−{c}}{{a}}\right)^{{a}} \left(\mathrm{1}\:+\:\frac{{c}−{a}}{{b}}\right)^{{b}} \left(\mathrm{1}\:+\:\frac{{a}−{b}}{{c}}\right)^{{c}} \:<\:\mathrm{1} \\ $$

Question Number 13128 Answers: 0 Comments: 0

If [x] stands for the greatest integer function, the value of ∫_( 4) ^( 10) (([x^2 ])/([x^2 −28x+196]+[x^2 ])) dx is

$$\mathrm{If}\:\:\left[{x}\right]\:\mathrm{stands}\:\mathrm{for}\:\mathrm{the}\:\mathrm{greatest}\:\mathrm{integer} \\ $$$$\mathrm{function},\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\: \\ $$$$\underset{\:\mathrm{4}} {\overset{\:\:\:\:\mathrm{10}} {\int}}\:\frac{\left[{x}^{\mathrm{2}} \right]}{\left[{x}^{\mathrm{2}} −\mathrm{28}{x}+\mathrm{196}\right]+\left[{x}^{\mathrm{2}} \right]}\:{dx}\:\mathrm{is} \\ $$

Question Number 13127 Answers: 0 Comments: 0

Question Number 13121 Answers: 1 Comments: 0

Find the value of : (2/(15)) + (2/(35)) + (2/(63)) + (2/(99)) + ... + (2/(9999))

$$\mathrm{Find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\::\:\:\frac{\mathrm{2}}{\mathrm{15}}\:+\:\frac{\mathrm{2}}{\mathrm{35}}\:+\:\frac{\mathrm{2}}{\mathrm{63}}\:+\:\frac{\mathrm{2}}{\mathrm{99}}\:+\:...\:+\:\frac{\mathrm{2}}{\mathrm{9999}} \\ $$

Question Number 13117 Answers: 1 Comments: 0

Question Number 13107 Answers: 1 Comments: 0

A man moves 20m north then 12m east and finally 15m south. His displacement from the starting point is ?

$$\mathrm{A}\:\mathrm{man}\:\mathrm{moves}\:\mathrm{20m}\:\mathrm{north}\:\mathrm{then}\:\mathrm{12m}\:\mathrm{east}\:\mathrm{and}\:\mathrm{finally}\:\mathrm{15m}\:\mathrm{south}.\:\:\mathrm{His}\:\mathrm{displacement} \\ $$$$\mathrm{from}\:\mathrm{the}\:\mathrm{starting}\:\mathrm{point}\:\mathrm{is}\:? \\ $$

Question Number 13103 Answers: 2 Comments: 0

∫_( −1) ^2 (( ∣ x ∣ )/x) dx =

$$\:\underset{\:−\mathrm{1}} {\overset{\mathrm{2}} {\int}}\:\frac{\:\mid\:{x}\:\mid\:}{{x}}\:{dx}\:=\: \\ $$

Question Number 13102 Answers: 0 Comments: 4

Find the sum of the nth term : 1^6 + 2^6 + 3^6 + 4^6 + ... + n^6

$$\mathrm{Find}\:\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{the}\:\mathrm{nth}\:\mathrm{term}\:\::\:\:\mathrm{1}^{\mathrm{6}} \:+\:\mathrm{2}^{\mathrm{6}} \:+\:\mathrm{3}^{\mathrm{6}} \:+\:\mathrm{4}^{\mathrm{6}} \:+\:...\:+\:\mathrm{n}^{\mathrm{6}} \\ $$

Question Number 13099 Answers: 2 Comments: 0

If f(x + 5) = g(2x −1) Find 2f^(−1) (x) (A) g^(−1) (x) + 11 (D) g^(−1) (x/2) + 6 (B) g^(−1) (x) + 9 (E) g^(−1) (2x) + 6 (C) g^(−1) (x) + 6

$$\mathrm{If}\:{f}\left({x}\:+\:\mathrm{5}\right)\:=\:{g}\left(\mathrm{2}{x}\:−\mathrm{1}\right) \\ $$$$\mathrm{Find}\:\mathrm{2}{f}^{−\mathrm{1}} \left({x}\right) \\ $$$$ \\ $$$$\left(\mathrm{A}\right)\:{g}^{−\mathrm{1}} \left({x}\right)\:+\:\mathrm{11}\:\:\:\:\:\:\:\:\left(\mathrm{D}\right)\:{g}^{−\mathrm{1}} \left({x}/\mathrm{2}\right)\:+\:\mathrm{6} \\ $$$$\left(\mathrm{B}\right)\:{g}^{−\mathrm{1}} \left({x}\right)\:+\:\mathrm{9}\:\:\:\:\:\:\:\:\:\:\:\left(\mathrm{E}\right)\:{g}^{−\mathrm{1}} \left(\mathrm{2}{x}\right)\:+\:\mathrm{6} \\ $$$$\left(\mathrm{C}\right)\:{g}^{−\mathrm{1}} \left({x}\right)\:+\:\mathrm{6} \\ $$

Question Number 13098 Answers: 1 Comments: 0

Question Number 13097 Answers: 1 Comments: 0

S=Σ_(x_2 =1) ^x_1 Σ_(x_3 =1) ^x_2 ∙∙∙Σ_(x_n =1) ^x_(n−1) Σ_(t=1) ^x_n t Can you evaluate S?

$${S}=\underset{{x}_{\mathrm{2}} =\mathrm{1}} {\overset{{x}_{\mathrm{1}} } {\sum}}\underset{{x}_{\mathrm{3}} =\mathrm{1}} {\overset{{x}_{\mathrm{2}} } {\sum}}\centerdot\centerdot\centerdot\underset{{x}_{{n}} =\mathrm{1}} {\overset{{x}_{{n}−\mathrm{1}} } {\sum}}\underset{{t}=\mathrm{1}} {\overset{{x}_{{n}} } {\sum}}{t} \\ $$$$\mathrm{Can}\:\mathrm{you}\:\mathrm{evaluate}\:{S}? \\ $$

Question Number 13091 Answers: 1 Comments: 0

A motor car moves with a velocity of 20m/s on a rough horizontal road and covers a displacement of 50m. Find the coefficient of dynamic friction between the tyre and the ground (g = 10m/s^2 ).

$$\mathrm{A}\:\mathrm{motor}\:\mathrm{car}\:\mathrm{moves}\:\mathrm{with}\:\mathrm{a}\:\mathrm{velocity}\:\mathrm{of}\:\mathrm{20m}/\mathrm{s}\:\mathrm{on}\:\mathrm{a}\:\mathrm{rough}\:\mathrm{horizontal}\:\mathrm{road}\:\mathrm{and} \\ $$$$\mathrm{covers}\:\mathrm{a}\:\mathrm{displacement}\:\mathrm{of}\:\mathrm{50m}.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{coefficient}\:\mathrm{of}\:\mathrm{dynamic}\:\mathrm{friction}\:\mathrm{between} \\ $$$$\mathrm{the}\:\mathrm{tyre}\:\mathrm{and}\:\mathrm{the}\:\mathrm{ground}\:\:\left(\mathrm{g}\:=\:\mathrm{10m}/\mathrm{s}^{\mathrm{2}} \right). \\ $$

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