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Question Number 15591 Answers: 1 Comments: 0

A projectile projected from the ground has its direction of motion making an angle (π/4) with the horizontal at a height 40 m. Its initial velocity of projection is 50 m/s, the angle of projection is?

$$\mathrm{A}\:\mathrm{projectile}\:\mathrm{projected}\:\mathrm{from}\:\mathrm{the}\:\mathrm{ground} \\ $$$$\mathrm{has}\:\mathrm{its}\:\mathrm{direction}\:\mathrm{of}\:\mathrm{motion}\:\mathrm{making}\:\mathrm{an} \\ $$$$\mathrm{angle}\:\frac{\pi}{\mathrm{4}}\:\mathrm{with}\:\mathrm{the}\:\mathrm{horizontal}\:\mathrm{at}\:\mathrm{a}\:\mathrm{height} \\ $$$$\mathrm{40}\:\mathrm{m}.\:\mathrm{Its}\:\mathrm{initial}\:\mathrm{velocity}\:\mathrm{of}\:\mathrm{projection}\:\mathrm{is} \\ $$$$\mathrm{50}\:\mathrm{m}/\mathrm{s},\:\mathrm{the}\:\mathrm{angle}\:\mathrm{of}\:\mathrm{projection}\:\mathrm{is}? \\ $$

Question Number 15578 Answers: 0 Comments: 0

What is the value of cot^2 ((π/(14))) + cot^2 (((3π)/(14))) + cot^2 (((5π)/(14))) ?

$$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of} \\ $$$$\mathrm{cot}^{\mathrm{2}} \:\left(\frac{\pi}{\mathrm{14}}\right)\:+\:\mathrm{cot}^{\mathrm{2}} \:\left(\frac{\mathrm{3}\pi}{\mathrm{14}}\right)\:+\:\mathrm{cot}^{\mathrm{2}} \:\left(\frac{\mathrm{5}\pi}{\mathrm{14}}\right)\:? \\ $$

Question Number 15572 Answers: 2 Comments: 1

Question Number 15570 Answers: 2 Comments: 1

Solve: 2^x = x^4

$$\mathrm{Solve}:\:\:\:\mathrm{2}^{\mathrm{x}} \:=\:\mathrm{x}^{\mathrm{4}} \\ $$

Question Number 15567 Answers: 2 Comments: 3

Question Number 15561 Answers: 0 Comments: 3

Question Number 15558 Answers: 1 Comments: 1

Question Number 15555 Answers: 1 Comments: 0

Prove that ((cos 8x − cos 7x)/(1 + 2 cos 5x)) = cos 3x − cos 2x

$$\mathrm{Prove}\:\mathrm{that} \\ $$$$\frac{\mathrm{cos}\:\mathrm{8}{x}\:−\:\mathrm{cos}\:\mathrm{7}{x}}{\mathrm{1}\:+\:\mathrm{2}\:\mathrm{cos}\:\mathrm{5}{x}}\:=\:\mathrm{cos}\:\mathrm{3}{x}\:−\:\mathrm{cos}\:\mathrm{2}{x} \\ $$

Question Number 15543 Answers: 2 Comments: 0

Q#13724 Reposted. E_ ^ xpansion of 1000! has 24 0′s at the end. Find the first non- zero digit from right. 1000!=....d0000...0 What is the the value of d?

$$\mathrm{Q}#\mathrm{13724}\:\mathcal{R}{eposted}. \\ $$$$\mathcal{E}_{\:} ^{\:} \mathrm{xpansion}\:\mathrm{of}\:\mathrm{1000}! \\ $$$$\mathrm{has}\:\mathrm{24}\:\:\mathrm{0}'\mathrm{s}\:\mathrm{at}\:\mathrm{the}\:\mathrm{end}.\:\mathrm{Find} \\ $$$$\mathrm{the}\:\mathrm{first}\:\mathrm{non}-\:\mathrm{zero}\:\mathrm{digit}\: \\ $$$$\mathrm{from}\:\mathrm{right}. \\ $$$$\mathrm{1000}!=....\mathrm{d0000}...\mathrm{0} \\ $$$$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{d}? \\ $$$$ \\ $$

Question Number 15541 Answers: 0 Comments: 1

If θ lies in the first quadrant which of the following is not true?

$$\mathrm{If}\:\theta\:\mathrm{lies}\:\mathrm{in}\:\mathrm{the}\:\mathrm{first}\:\mathrm{quadrant}\:\mathrm{which}\:\mathrm{of} \\ $$$$\mathrm{the}\:\mathrm{following}\:\mathrm{is}\:\mathrm{not}\:\mathrm{true}? \\ $$

Question Number 15539 Answers: 0 Comments: 0