The surface area of a cylinder is:
A=2πr^2 +2πrh
As h→0, the shape becomes a 2D circle,
so should lim_(h→0) A = πr^2 ???
Or is it that as h→0, it creates a circle
of 3 dimensions with infintesimally small
height, so it has two circles making it:
lim_(h→0) A = 2πr^2 ???
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