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Question Number 199983 Answers: 1 Comments: 0

find lim_(x→∞) sin (((πx)/(5+3x))) by sequeeze theorem

$$\:\:\:\mathrm{find}\:\underset{{x}\rightarrow\infty} {\mathrm{lim}}\:\mathrm{sin}\:\left(\frac{\pi\mathrm{x}}{\mathrm{5}+\mathrm{3x}}\right)\: \\ $$$$\:\:\mathrm{by}\:\mathrm{sequeeze}\:\mathrm{theorem} \\ $$

Question Number 199996 Answers: 0 Comments: 0

Calculate the first order energy correction for 1−dimensional non−degenerate anharmonic oscillator whose harmiltonian is HL

$$\mathrm{Calculate}\:\mathrm{the}\:\mathrm{first}\:\mathrm{order}\:\mathrm{energy}\:\mathrm{correction}\:\mathrm{for} \\ $$$$\mathrm{1}−\mathrm{dimensional}\:\mathrm{non}−\mathrm{degenerate}\:\mathrm{anharmonic} \\ $$$$\mathrm{oscillator}\:\mathrm{whose}\:\mathrm{harmiltonian}\:\mathrm{is}\:\mathscr{H}\underline{\mathscr{L}} \\ $$

Question Number 199968 Answers: 1 Comments: 1

determiner x ?

$$\mathrm{determiner}\:\boldsymbol{\mathrm{x}}\:\:? \\ $$

Question Number 199959 Answers: 0 Comments: 4

how do I calculate for 7.86! without calculator?

$$\:\boldsymbol{{how}}\:\boldsymbol{{do}}\:\boldsymbol{{I}}\:\boldsymbol{{calculate}}\:\boldsymbol{{for}} \\ $$$$\:\mathrm{7}.\mathrm{86}!\:\boldsymbol{{without}}\:\boldsymbol{{calculator}}? \\ $$

Question Number 199956 Answers: 1 Comments: 0

Question Number 199952 Answers: 1 Comments: 0

Question Number 199942 Answers: 1 Comments: 0

Question Number 199940 Answers: 2 Comments: 3

Question Number 199934 Answers: 2 Comments: 0

$$\:\:\:\cancel{\underline{\underbrace{ }}\:} \\ $$$$ \\ $$

Question Number 199932 Answers: 2 Comments: 0

1. If 3 ∙ ab^(−) + bc^(−) = 115 Find: max(a+b+c)=? 2. a,b,c∈N If (a/2) + (b/3) = (c/4) Find: min(a+b+c)=?

$$\mathrm{1}. \\ $$$$\mathrm{If}\:\:\:\mathrm{3}\:\centerdot\:\overline {\mathrm{ab}}\:+\:\overline {\mathrm{bc}}\:=\:\mathrm{115} \\ $$$$\mathrm{Find}:\:\:\:\mathrm{max}\left(\mathrm{a}+\mathrm{b}+\mathrm{c}\right)=? \\ $$$$ \\ $$$$\mathrm{2}. \\ $$$$\mathrm{a},\mathrm{b},\mathrm{c}\in\mathbb{N} \\ $$$$\mathrm{If}\:\:\:\frac{\mathrm{a}}{\mathrm{2}}\:\:+\:\:\frac{\mathrm{b}}{\mathrm{3}}\:\:=\:\:\frac{\mathrm{c}}{\mathrm{4}} \\ $$$$\mathrm{Find}:\:\:\:\mathrm{min}\left(\mathrm{a}+\mathrm{b}+\mathrm{c}\right)=? \\ $$

Question Number 199923 Answers: 2 Comments: 0

Question Number 199922 Answers: 2 Comments: 0

Question Number 199921 Answers: 1 Comments: 0

Question Number 199916 Answers: 0 Comments: 0

Question Number 199915 Answers: 1 Comments: 0

Question Number 199913 Answers: 0 Comments: 0

To calculate the mean and median of the distribution, you can follow these steps: 1. Calculate the midpoint for each weight range: - For 118-126: Midpoint = (118 + 126) / 2 = 122 - For 127-135: Midpoint = (127 + 135) / 2 = 131 - For 136-144: Midpoint = (136 + 144) / 2 = 140 - For 145-153: Midpoint = (145 + 153) / 2 = 149 - For 154-162: Midpoint = (154 + 162) / 2 = 158 - For 163-171: Midpoint = (163 + 171) / 2 = 167 - For 172-180: Midpoint = (172 + 180) / 2 = 176 2. Multiply each midpoint by its corresponding frequency to find the sum of the products. - (122 * 3) + (131 * 5) + (140 * 9) + (149 * 12) + (158 * 5) + (167 * 4) + (176 * 2) 3. Sum the frequencies to find the total number of data points. - 3 + 5 + 9 + 12 + 5 + 4 + 2 = 40 4. Calculate the mean (average) by dividing the sum of the products by the total number of data points: - Mean = (Sum of products) / (Total number of data points) 5. To find the median, you can start by listing the weights in ascending order. Then, locate the middle value. Since there are 40 data points (an even number), the median will be the average of the 20th and 21st values. - Arrange the midpoints in ascending order: 122, 131, 140, 149, 158, 167, 176. - The 20th value is 149, and the 21st value is 158. - Median = (149 + 158) / 2 Now, you can calculate the mean and median based on the given data.

$$ \\ $$To calculate the mean and median of the distribution, you can follow these steps: 1. Calculate the midpoint for each weight range: - For 118-126: Midpoint = (118 + 126) / 2 = 122 - For 127-135: Midpoint = (127 + 135) / 2 = 131 - For 136-144: Midpoint = (136 + 144) / 2 = 140 - For 145-153: Midpoint = (145 + 153) / 2 = 149 - For 154-162: Midpoint = (154 + 162) / 2 = 158 - For 163-171: Midpoint = (163 + 171) / 2 = 167 - For 172-180: Midpoint = (172 + 180) / 2 = 176 2. Multiply each midpoint by its corresponding frequency to find the sum of the products. - (122 * 3) + (131 * 5) + (140 * 9) + (149 * 12) + (158 * 5) + (167 * 4) + (176 * 2) 3. Sum the frequencies to find the total number of data points. - 3 + 5 + 9 + 12 + 5 + 4 + 2 = 40 4. Calculate the mean (average) by dividing the sum of the products by the total number of data points: - Mean = (Sum of products) / (Total number of data points) 5. To find the median, you can start by listing the weights in ascending order. Then, locate the middle value. Since there are 40 data points (an even number), the median will be the average of the 20th and 21st values. - Arrange the midpoints in ascending order: 122, 131, 140, 149, 158, 167, 176. - The 20th value is 149, and the 21st value is 158. - Median = (149 + 158) / 2 Now, you can calculate the mean and median based on the given data.

Question Number 199911 Answers: 3 Comments: 6