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Question Number 17976 Answers: 1 Comments: 0

A driver is 5.2 below the surface of water of density 1000kg/m. if the atmospheric pressure is 1.02 × 10^5 Pa. calculate the pressure on the driver.

$$\mathrm{A}\:\mathrm{driver}\:\mathrm{is}\:\mathrm{5}.\mathrm{2}\:\mathrm{below}\:\mathrm{the}\:\mathrm{surface}\:\mathrm{of}\:\mathrm{water}\:\mathrm{of}\:\mathrm{density}\:\mathrm{1000kg}/\mathrm{m}.\:\:\mathrm{if}\:\mathrm{the} \\ $$$$\mathrm{atmospheric}\:\mathrm{pressure}\:\mathrm{is}\:\mathrm{1}.\mathrm{02}\:×\:\mathrm{10}^{\mathrm{5}} \:\mathrm{Pa}.\:\mathrm{calculate}\:\mathrm{the}\:\mathrm{pressure}\:\mathrm{on}\:\mathrm{the}\:\mathrm{driver}. \\ $$

Question Number 17970 Answers: 1 Comments: 0

Question Number 17969 Answers: 0 Comments: 0

Question Number 17963 Answers: 0 Comments: 4

Question Number 17961 Answers: 1 Comments: 0

Question Number 17959 Answers: 1 Comments: 0

Question Number 17957 Answers: 1 Comments: 0

prove that (1+(a/x))^n =(1+((an)/x)) , x≫a

$$\mathrm{prove}\:\mathrm{that}\:\left(\mathrm{1}+\frac{\mathrm{a}}{\mathrm{x}}\right)^{\mathrm{n}} =\left(\mathrm{1}+\frac{\mathrm{an}}{\mathrm{x}}\right)\:,\:\:\mathrm{x}\gg\mathrm{a} \\ $$

Question Number 17939 Answers: 1 Comments: 1

∫secxdx

$$\int{secxdx}\: \\ $$

Question Number 17938 Answers: 2 Comments: 2

If only downward motion along lines is allowed, what is the total number of paths from point P to point Q in the figure below?

$$\mathrm{If}\:\mathrm{only}\:\mathrm{downward}\:\mathrm{motion}\:\mathrm{along}\:\mathrm{lines}\:\mathrm{is} \\ $$$$\mathrm{allowed},\:\mathrm{what}\:\mathrm{is}\:\mathrm{the}\:\mathrm{total}\:\mathrm{number}\:\mathrm{of} \\ $$$$\mathrm{paths}\:\mathrm{from}\:\mathrm{point}\:\mathrm{P}\:\mathrm{to}\:\mathrm{point}\:\mathrm{Q}\:\mathrm{in}\:\mathrm{the} \\ $$$$\mathrm{figure}\:\mathrm{below}? \\ $$

Question Number 17936 Answers: 2 Comments: 1

Two particles start moving towards each other with constant acceleration of 1 m/s^2 . If their initial separation is 100 m, find after what time they will meet each other (A) 40s (B) 45s (C) 50 s (D)55s

$$\mathrm{Two}\:\mathrm{particles}\:\mathrm{start}\:\mathrm{moving}\:\mathrm{towards} \\ $$$$\mathrm{each}\:\mathrm{other}\:\mathrm{with}\:\mathrm{constant}\:\mathrm{acceleration} \\ $$$$\mathrm{of}\:\:\mathrm{1}\:{m}/{s}^{\mathrm{2}} .\:\mathrm{If}\:\mathrm{their}\:\mathrm{initial}\:\mathrm{separation}\:\mathrm{is} \\ $$$$\mathrm{100}\:\mathrm{m},\:\mathrm{find}\:\mathrm{after}\:\mathrm{what}\:\mathrm{time}\:\mathrm{they}\:\mathrm{will} \\ $$$$\mathrm{meet}\:\mathrm{each}\:\mathrm{other} \\ $$$$\left(\mathrm{A}\right)\:\mathrm{40}{s}\:\:\:\:\left(\mathrm{B}\right)\:\mathrm{45}{s}\:\:\:\:\left(\mathrm{C}\right)\:\mathrm{50}\:{s}\:\left(\mathrm{D}\right)\mathrm{55}{s} \\ $$

Question Number 17919 Answers: 0 Comments: 0

How do the electronic configurations of the elements with Z = 107 − 109 differ from one another?

$$\mathrm{How}\:\mathrm{do}\:\mathrm{the}\:\mathrm{electronic}\:\mathrm{configurations}\:\mathrm{of} \\ $$$$\mathrm{the}\:\mathrm{elements}\:\mathrm{with}\:\mathrm{Z}\:=\:\mathrm{107}\:−\:\mathrm{109}\:\mathrm{differ} \\ $$$$\mathrm{from}\:\mathrm{one}\:\mathrm{another}? \\ $$

Question Number 17918 Answers: 0 Comments: 0

Write the electronic configuration and the block to which an element with Z = 90 belongs.

$$\mathrm{Write}\:\mathrm{the}\:\mathrm{electronic}\:\mathrm{configuration}\:\mathrm{and} \\ $$$$\mathrm{the}\:\mathrm{block}\:\mathrm{to}\:\mathrm{which}\:\mathrm{an}\:\mathrm{element}\:\mathrm{with} \\ $$$$\mathrm{Z}\:=\:\mathrm{90}\:\mathrm{belongs}. \\ $$

Question Number 17901 Answers: 1 Comments: 2

Question Number 17895 Answers: 0 Comments: 2

Question Number 17909 Answers: 0 Comments: 1

Please answer Q. 17525

$${Please}\:{answer}\:{Q}.\:\mathrm{17525} \\ $$

Question Number 17890 Answers: 0 Comments: 0

Question Number 17948 Answers: 1 Comments: 3

Question Number 17886 Answers: 0 Comments: 7

Question Number 17884 Answers: 1 Comments: 1

Question Number 17879 Answers: 0 Comments: 0

Question Number 17878 Answers: 0 Comments: 0

Question Number 17872 Answers: 2 Comments: 0

Solve : ∣x − 1∣ + ∣x∣ + ∣x + 1∣ = x + 2

$$\mathrm{Solve}\:: \\ $$$$\mid{x}\:−\:\mathrm{1}\mid\:+\:\mid{x}\mid\:+\:\mid{x}\:+\:\mathrm{1}\mid\:=\:{x}\:+\:\mathrm{2} \\ $$

Question Number 17867 Answers: 1 Comments: 0

prove that (2+(√3))^(2n) +(2−(√3))^(2n) is an even integer and that (2+(√3))^(2n) −(2−(√3))^(2n) =w(√3) for some integers w,for all integer n≥1.

$${prove}\:{that}\:\left(\mathrm{2}+\sqrt{\mathrm{3}}\right)^{\mathrm{2}{n}} +\left(\mathrm{2}−\sqrt{\mathrm{3}}\right)^{\mathrm{2}{n}} {is}\:{an} \\ $$$${even}\:{integer}\:{and}\:{that}\:\left(\mathrm{2}+\sqrt{\mathrm{3}}\right)^{\mathrm{2}{n}} −\left(\mathrm{2}−\sqrt{\mathrm{3}}\right)^{\mathrm{2}{n}} ={w}\sqrt{\mathrm{3}} \\ $$$${for}\:{some}\:{integers}\:{w},{for}\:{all}\:{integer}\:{n}\geqslant\mathrm{1}. \\ $$$$ \\ $$

Question Number 17866 Answers: 1 Comments: 0

Prove that sin 5A = 5 cos^4 A sin A − 10 cos^2 A sin^3 A + sin^5 A

$$\mathrm{Prove}\:\mathrm{that}\:\mathrm{sin}\:\mathrm{5}{A}\:=\:\mathrm{5}\:\mathrm{cos}^{\mathrm{4}} \:{A}\:\mathrm{sin}\:{A}\:− \\ $$$$\mathrm{10}\:\mathrm{cos}^{\mathrm{2}} \:{A}\:\mathrm{sin}^{\mathrm{3}} \:{A}\:+\:\mathrm{sin}^{\mathrm{5}} \:{A} \\ $$

Question Number 17852 Answers: 0 Comments: 1

A particle moves in a straight line (x-axis) with the velocity shown in the figure. Knowing that x = −16 m at t = 0, draw the a-t and x-t curves for the interval 0 < t < 40 s and determine (i) Maximum value of the position coordinate of the particle. (ii) The values of t for which the particle is at a distance of 50 m from the origin.

$$\mathrm{A}\:\mathrm{particle}\:\mathrm{moves}\:\mathrm{in}\:\mathrm{a}\:\mathrm{straight}\:\mathrm{line} \\ $$$$\left({x}-\mathrm{axis}\right)\:\mathrm{with}\:\mathrm{the}\:\mathrm{velocity}\:\mathrm{shown}\:\mathrm{in}\:\mathrm{the} \\ $$$$\mathrm{figure}.\:\mathrm{Knowing}\:\mathrm{that}\:{x}\:=\:−\mathrm{16}\:\mathrm{m}\:\mathrm{at} \\ $$$${t}\:=\:\mathrm{0},\:\mathrm{draw}\:\mathrm{the}\:{a}-{t}\:\mathrm{and}\:{x}-{t}\:\mathrm{curves}\:\mathrm{for} \\ $$$$\mathrm{the}\:\mathrm{interval}\:\mathrm{0}\:<\:{t}\:<\:\mathrm{40}\:\mathrm{s}\:\mathrm{and}\:\mathrm{determine} \\ $$$$\left(\mathrm{i}\right)\:\mathrm{Maximum}\:\mathrm{value}\:\mathrm{of}\:\mathrm{the}\:\mathrm{position} \\ $$$$\mathrm{coordinate}\:\mathrm{of}\:\mathrm{the}\:\mathrm{particle}. \\ $$$$\left(\mathrm{ii}\right)\:\mathrm{The}\:\mathrm{values}\:\mathrm{of}\:{t}\:\mathrm{for}\:\mathrm{which}\:\mathrm{the} \\ $$$$\mathrm{particle}\:\mathrm{is}\:\mathrm{at}\:\mathrm{a}\:\mathrm{distance}\:\mathrm{of}\:\mathrm{50}\:\mathrm{m}\:\mathrm{from} \\ $$$$\mathrm{the}\:\mathrm{origin}. \\ $$

Question Number 17935 Answers: 0 Comments: 0

Ball A is dropped from the top of a building. At the same instant ball B is thrown vertically upwards from the ground. When the ball collide, they are moving in opposite directions and the speed of A(u) is twice the speed of B. The relative velocity of the ball just before collision and relative acceleration between them is (only their magnitudes) (A) 0 and 0 (B) ((3u)/2) and 0 (C) ((3u)/2) and 2g (D) ((3u)/2) and g

$$\mathrm{Ball}\:{A}\:\mathrm{is}\:\mathrm{dropped}\:\mathrm{from}\:\mathrm{the}\:\mathrm{top}\:\mathrm{of}\:\mathrm{a}\:\mathrm{building}. \\ $$$$\mathrm{At}\:\mathrm{the}\:\mathrm{same}\:\mathrm{instant}\:\mathrm{ball}\:{B}\:\mathrm{is}\:\mathrm{thrown} \\ $$$$\mathrm{vertically}\:\mathrm{upwards}\:\mathrm{from}\:\mathrm{the}\:\mathrm{ground}. \\ $$$$\mathrm{When}\:\mathrm{the}\:\mathrm{ball}\:\mathrm{collide},\:\mathrm{they}\:\mathrm{are}\:\mathrm{moving}\:\:\mathrm{in} \\ $$$$\mathrm{opposite}\:\mathrm{directions}\:\mathrm{and}\:\mathrm{the}\:\mathrm{speed}\:\mathrm{of}\:{A}\left({u}\right) \\ $$$$\mathrm{is}\:\mathrm{twice}\:\mathrm{the}\:\mathrm{speed}\:\mathrm{of}\:{B}.\:\mathrm{The}\:\mathrm{relative}\: \\ $$$$\mathrm{velocity}\:\mathrm{of}\:\mathrm{the}\:\mathrm{ball}\:\mathrm{just}\:\mathrm{before}\:\mathrm{collision} \\ $$$$\mathrm{and}\:\mathrm{relative}\:\mathrm{acceleration}\:\mathrm{between}\:\mathrm{them} \\ $$$$\mathrm{is}\:\left(\mathrm{only}\:\mathrm{their}\:\mathrm{magnitudes}\right) \\ $$$$\left(\mathrm{A}\right)\:\mathrm{0}\:\mathrm{and}\:\mathrm{0}\:\:\:\:\:\:\:\:\left(\mathrm{B}\right)\:\frac{\mathrm{3}{u}}{\mathrm{2}}\:\mathrm{and}\:\mathrm{0} \\ $$$$\left(\mathrm{C}\right)\:\frac{\mathrm{3}{u}}{\mathrm{2}}\:\mathrm{and}\:\mathrm{2}{g}\:\:\:\left(\mathrm{D}\right)\:\frac{\mathrm{3}{u}}{\mathrm{2}}\:\mathrm{and}\:{g} \\ $$

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